I tried what you had suggested and I still get the same result.
Robert Twitty wrote:
The date() is for use with the 32-bit C time value returned by functions
like time(). Data from fields of type datetime are returned as strings in
the form Jan 9 2004 by the mssql extension as the default. To
Oops
Use Off instead of On, or execute this in your script:
ini_set('mssql.datetimeconvert' , 0 );
Note: Do not use the date() function to display the value. Just display
it asis.
-- bob
On Tue, 27 Jan 2004, Steve wrote:
I tried what you had suggested and I still get the same result.
I have Apache 1.3 and PHP 4 running on Windows 98 connecting to a local
MS SQL 7.0 server. MS SQL has the date as 2004-01-09 (-MM-DD), when
I print the date to a webpage with this PHP code:
printf(Date Picked Up: %s\nDate, date(Y/j/n,$row[0]);
I get this output:
1969/12/31
What is
The date() is for use with the 32-bit C time value returned by functions
like time(). Data from fields of type datetime are returned as strings in
the form Jan 9 2004 by the mssql extension as the default. To return it
using ISO format set mssql.datetimeconvert to On in the php.ini file, or
use
