Re: [PHP-DB] Notice: Undefined index: op
if you conisder passing the $_POST['op'] to a var called $op, then you could
define the var $op as an empty string
$op =;
Bastien
From: J. Connolly [EMAIL PROTECTED]
To: PHP list php-db@lists.php.net
Subject: Re: [PHP-DB] Notice: Undefined index: op
Date: Tue, 22 Feb 2005 12:20:06 -0500
Thank you everyone for your help. None of the solutions helped though. It
is a long story, I have to use the undefined 'op' in a few places and all f
the solution end up causing other error. But I appreciate the help and I
understand when the problem is alot clearer.. I just turned off the error
reporting like everyone suggested. Maybe when I learn a bit more I can go
back and fix it. My application runs fine, I just like everything to be
'perfect'.
jzf
Martin Norland wrote:
J. Connolly wrote:
I get the error message:
*Notice*: Undefined index: op
When trying to set up a form. I have looked everywhere for the solution.
I don't understnadn how to define that index. The come it comes from is:
if ($_POST['op'] != 'ds') {
$display_block =
form action=\$_SERVER[PHP_SELF]\ method=\POST\
Your E-mail Address:
input type=text name=\email\ size=40 maxlength=150/
input type=radio name=\action\ value=\sub\
checked/subscribebr/
input type=radio name=\action\ value=\unsub\ /unsubscribe
input type=\hidden\ name=\op\ value=\ds\/
input type=submit name=\submit\ value=\Submit Form\/
/form;
}
I am trying to create a form which allows my users to join a mailing
list. I conceptually understand what the problem is but cannot find out
how to solve the problem. I cannot find out how to define 'op'. Please do
not tell me to lower my error reporting levels. I would rather fix the
problems. Thank you,
Joseph
$_POST is likely empty, because the user requesting the page has likely
not submitted the form (yet). What you probably want (since you aren't
going to lower the error reporting levels) is:
if ( isset($_POST['op']) $_POST['op'] == 'ds' ) {
// do your operation here
} else {
// print your form/etc. here
}
You may want to use a different quoting style - I can't recall the name,
but it's taken from perl
echo EOF
form action=$_SERVER[PHP_SELF] method=POST
...
the rest of your stuff, then on its own line right at the beginning of the
line (no tabs/etc. :( )
...
EOF;
it basically echo's until it sees that delimiter, that could be EOD or
STOP or whatever (well, there might be reserved words issues - I could
more easily check if I could remember the name of the quoting style...)
Cheers
--
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To unsubscribe, visit: http://www.php.net/unsub.php
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[PHP-DB] Notice: Undefined index: op
I get the error message:
*Notice*: Undefined index: op
When trying to set up a form. I have looked everywhere for the solution.
I don't understnadn how to define that index. The come it comes from is:
if ($_POST['op'] != 'ds') {
$display_block =
form action=\$_SERVER[PHP_SELF]\ method=\POST\
Your E-mail Address:
input type=text name=\email\ size=40 maxlength=150/
input type=radio name=\action\ value=\sub\ checked/subscribebr/
input type=radio name=\action\ value=\unsub\ /unsubscribe
input type=\hidden\ name=\op\ value=\ds\/
input type=submit name=\submit\ value=\Submit Form\/
/form;
}
I am trying to create a form which allows my users to join a mailing
list. I conceptually understand what the problem is but cannot find out
how to solve the problem. I cannot find out how to define 'op'. Please
do not tell me to lower my error reporting levels. I would rather fix
the problems. Thank you,
Joseph
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Re: [PHP-DB] Notice: Undefined index: op
if ($_POST['op'] != 'ds') {
$display_block =
form action=\$_SERVER[PHP_SELF]\ method=\POST\
Your E-mail Address:
input type=text name=\email\ size=40 maxlength=150/
input type=radio name=\action\ value=\sub\ checked/subscribebr/
input type=radio name=\action\ value=\unsub\ /unsubscribe
input type=\hidden\ name=\op\ value=\ds\/
input type=submit name=\submit\ value=\Submit Form\/
/form;
}
try:
if (isset($_POST['op']) $_POST['op'] != 'ds')
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Re: [PHP-DB] Notice: Undefined index: op
On Tue, 22 Feb 2005 10:47:43 -0600, Matt M. [EMAIL PROTECTED] wrote:
if ($_POST['op'] != 'ds') {
$display_block =
form action=\$_SERVER[PHP_SELF]\ method=\POST\
Your E-mail Address:
input type=text name=\email\ size=40 maxlength=150/
input type=radio name=\action\ value=\sub\ checked/subscribebr/
input type=radio name=\action\ value=\unsub\ /unsubscribe
input type=\hidden\ name=\op\ value=\ds\/
input type=submit name=\submit\ value=\Submit Form\/
/form;
}
try:
if (isset($_POST['op']) $_POST['op'] != 'ds')
sorry for 2 emails, looks like you would want
if (!isset($_POST['op']) || $_POST['op'] != 'ds')
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Re: [PHP-DB] Notice: Undefined index: op
J. Connolly wrote:
I get the error message:
*Notice*: Undefined index: op
When trying to set up a form. I have looked everywhere for the solution.
I don't understnadn how to define that index. The come it comes from is:
if ($_POST['op'] != 'ds') {
$display_block =
form action=\$_SERVER[PHP_SELF]\ method=\POST\
Your E-mail Address:
input type=text name=\email\ size=40 maxlength=150/
input type=radio name=\action\ value=\sub\ checked/subscribebr/
input type=radio name=\action\ value=\unsub\ /unsubscribe
input type=\hidden\ name=\op\ value=\ds\/
input type=submit name=\submit\ value=\Submit Form\/
/form;
}
I am trying to create a form which allows my users to join a mailing
list. I conceptually understand what the problem is but cannot find out
how to solve the problem. I cannot find out how to define 'op'. Please
do not tell me to lower my error reporting levels. I would rather fix
the problems. Thank you,
Joseph
$_POST is likely empty, because the user requesting the page has likely
not submitted the form (yet). What you probably want (since you aren't
going to lower the error reporting levels) is:
if ( isset($_POST['op']) $_POST['op'] == 'ds' ) {
// do your operation here
} else {
// print your form/etc. here
}
You may want to use a different quoting style - I can't recall the name,
but it's taken from perl
echo EOF
form action=$_SERVER[PHP_SELF] method=POST
...
the rest of your stuff, then on its own line right at the beginning of
the line (no tabs/etc. :( )
...
EOF;
it basically echo's until it sees that delimiter, that could be EOD or
STOP or whatever (well, there might be reserved words issues - I could
more easily check if I could remember the name of the quoting style...)
Cheers
--
- Martin Norland, Sys Admin / Database / Web Developer, International
Outreach x3257
The opinion(s) contained within this email do not necessarily represent
those of St. Jude Children's Research Hospital.
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Re: [PHP-DB] Notice: Undefined index: op
On Tue, 2005-02-22 at 10:49, Matt M. wrote:
On Tue, 22 Feb 2005 10:47:43 -0600, Matt M. [EMAIL PROTECTED] wrote:
if ($_POST['op'] != 'ds') {
$display_block =
form action=\$_SERVER[PHP_SELF]\ method=\POST\
Your E-mail Address:
input type=text name=\email\ size=40 maxlength=150/
input type=radio name=\action\ value=\sub\ checked/subscribebr/
input type=radio name=\action\ value=\unsub\ /unsubscribe
input type=\hidden\ name=\op\ value=\ds\/
input type=submit name=\submit\ value=\Submit Form\/
/form;
}
try:
if (isset($_POST['op']) $_POST['op'] != 'ds')
sorry for 2 emails, looks like you would want
if (!isset($_POST['op']) || $_POST['op'] != 'ds')
I vote for the first one.
Bret
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Re: [PHP-DB] Notice: Undefined index: op
Bret Hughes wrote: On Tue, 2005-02-22 at 10:49, Matt M. wrote: On Tue, 22 Feb 2005 10:47:43 -0600, Matt M. [EMAIL PROTECTED] wrote: [snip] try: if (isset($_POST['op']) $_POST['op'] != 'ds') sorry for 2 emails, looks like you would want if (!isset($_POST['op']) || $_POST['op'] != 'ds') I vote for the first one. Bret Your vote is misplaced - the first one isn't what he wanted... with that statement, his form will never be printed and it can never be set. Cheers, -- - Martin Norland, Sys Admin / Database / Web Developer, International Outreach x3257 The opinion(s) contained within this email do not necessarily represent those of St. Jude Children's Research Hospital. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Notice: Undefined index: op
Thank you everyone for your help. None of the solutions helped though.
It is a long story, I have to use the undefined 'op' in a few places and
all f the solution end up causing other error. But I appreciate the help
and I understand when the problem is alot clearer.. I just turned off
the error reporting like everyone suggested. Maybe when I learn a bit
more I can go back and fix it. My application runs fine, I just like
everything to be 'perfect'.
jzf
Martin Norland wrote:
J. Connolly wrote:
I get the error message:
*Notice*: Undefined index: op
When trying to set up a form. I have looked everywhere for the
solution. I don't understnadn how to define that index. The come it
comes from is:
if ($_POST['op'] != 'ds') {
$display_block =
form action=\$_SERVER[PHP_SELF]\ method=\POST\
Your E-mail Address:
input type=text name=\email\ size=40 maxlength=150/
input type=radio name=\action\ value=\sub\
checked/subscribebr/
input type=radio name=\action\ value=\unsub\ /unsubscribe
input type=\hidden\ name=\op\ value=\ds\/
input type=submit name=\submit\ value=\Submit Form\/
/form;
}
I am trying to create a form which allows my users to join a mailing
list. I conceptually understand what the problem is but cannot find
out how to solve the problem. I cannot find out how to define 'op'.
Please do not tell me to lower my error reporting levels. I would
rather fix the problems. Thank you,
Joseph
$_POST is likely empty, because the user requesting the page has
likely not submitted the form (yet). What you probably want (since
you aren't going to lower the error reporting levels) is:
if ( isset($_POST['op']) $_POST['op'] == 'ds' ) {
// do your operation here
} else {
// print your form/etc. here
}
You may want to use a different quoting style - I can't recall the
name, but it's taken from perl
echo EOF
form action=$_SERVER[PHP_SELF] method=POST
...
the rest of your stuff, then on its own line right at the beginning of
the line (no tabs/etc. :( )
...
EOF;
it basically echo's until it sees that delimiter, that could be EOD or
STOP or whatever (well, there might be reserved words issues - I could
more easily check if I could remember the name of the quoting style...)
Cheers
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Notice: Undefined index: op
On Tue, 2005-02-22 at 11:31, Martin Norland wrote:
Bret Hughes wrote:
On Tue, 2005-02-22 at 10:49, Matt M. wrote:
On Tue, 22 Feb 2005 10:47:43 -0600, Matt M. [EMAIL PROTECTED] wrote:
[snip]
try:
if (isset($_POST['op']) $_POST['op'] != 'ds')
sorry for 2 emails, looks like you would want
if (!isset($_POST['op']) || $_POST['op'] != 'ds')
I vote for the first one.
Bret
Your vote is misplaced - the first one isn't what he wanted... with that
statement, his form will never be printed and it can never be set.
You are right of course, In looking at the original post I misread it
to be if (! $_POST['op'] != 'ds ). I guess Since this is the sort of
construct I have cleaned up the most lately. Actually most of what I
have been finding is stuff like if (!$varname ){
That is, doing something if a variable is not set to a true value and
also using that for a test for existence.
turn on notices and get a lesson on how to make a log file grow quickly
:)
Bret
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Re: [PHP-DB] Notice: Undefined index: op
Martin Norland wrote: J. Connolly wrote: ... You may want to use a different quoting style - I can't recall the name, but it's taken from perl HEREDOC. (i believe its custom to write it in capitals,) echo EOF form action=$_SERVER[PHP_SELF] method=POST ... the rest of your stuff, then on its own line right at the beginning of the line (no tabs/etc. :( ) ... EOF; it basically echo's until it sees that delimiter, that could be EOD or STOP or whatever (well, there might be reserved words issues - I could more easily check if I could remember the name of the quoting style...) Cheers -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
