Re: [PHP-DB] One more GD ? -- filename
Hi There (again),
My apologies for being a complete pest with this issue. I changed a
few things around and I can now pass the image name thanks to Jos,
however, I'm getting a permission errors now.
Warning: imagejpeg(): Unable to open 'corneilus.jpg' for writing
I've changed image folder and subfolder permissions to 777 and no luck.
Any ideas.
Again thanks your help. :)
Craig
On Apr 6, 2005, at 11:18 AM, Juffermans, Jos wrote:
Hi,
Are you trying to display more images at once then?
You can store the image like you do now, then have the GD script
output the
image tag and use the image you've just stored as a source.
GD script:
...
ImageJPEG($thumb, $route_photo, '100');
echo ''; // add this line
ImageDestroy($thumb);
...
in the other script instead of
echo ("");
do this:
require("include/function_gd.php?route_photo=$thumb");
Jos
-Original Message-
From: Craig Hoffman [mailto:[EMAIL PROTECTED]
Sent: 06 April 2005 18:12
To: php-db@lists.php.net
Cc: Juffermans, Jos
Subject: Re: [PHP-DB] One more GD ? -- filename
Hi Jos,
I understand what your saying. The problem is all the image names are
listed in the DB (image.jpg, image1.jpg and so on) and all images have
titles attached. For example,
Title: Large Green Sea Turtle
Image: LargeGreenSeaTurtle.jpg
As you can see, the GD script randomly pulls photo names from the DB
and shows them. When I output the image with using the image tag I get
a blank variable.
Since the image name is empty, I can not match/query the title and
image. The image output may be showing a Blue Sea Turtle but the
title says, Green Sea Turtle. If I could just get the image name, I
could run a query to match them. Does this make sense?
On Apr 6, 2005, at 10:36 AM, Juffermans, Jos wrote:
Hi,
If I understand correctly, you're using
"include/function_gd.php?route_photo=$thumb" as image source which is
the
script you pasted. If you use a script as image source, the script
should
output the image data - not just store the image.
I'm not sure what you're trying to do but if you have an image object
in php
(eg $thumb), you should output that image:
output instead of save)
exit();
?>
However, you cannot use that to show multiple images from 1 script.
Jos
-Original Message-
From: Craig Hoffman [mailto:[EMAIL PROTECTED]
Sent: 06 April 2005 15:24
To: php-db@lists.php.net
Subject: [PHP-DB] One more GD ? -- filename
Thanks everyone for answering my other post. However, I'm still
having
trouble passing the image name from the GD script to the image tag.
I'm including the GD script below. Any help would be great. Thanks -
Craig
//GD script
while($row = mysql_fetch_array($result)) {
//Photo varibale
$route_photo = $row["route_photo"];
//Start GD
//New Image resize
$new_width = 125;
$new_height = 225;
//Content Type
header("Content-type: image/jpeg");
//Start new image resize
list($width_orig, $height_orig) =
getImageSize("../images/climbs/$route_photo");
if ($new_width && ($width_orig < $height_orig)) {
$new_width = ($new_height / $height_orig) *
$width_orig;
} else {
$new_height = ($new_width / $width_orig) *
$height_orig;
}
//resample the image
$thumb = ImageCreateTrueColor($new_width, $new_height);
$tmp_image =
ImageCreateFromJPEG("../images/climbs/$route_photo");
ImageCopyResampled($thumb, $tmp_image, 0, 0, 0, 0,
$new_width,
$new_height, $width_orig, $height_orig);
ImageJPEG($thumb, $route_photo, '100');
ImageDestroy($thumb);
}
?>
//Image Tag:
echo ("");
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] One more GD ? -- filename
Hi,
Are you trying to display more images at once then?
You can store the image like you do now, then have the GD script output the
image tag and use the image you've just stored as a source.
GD script:
...
ImageJPEG($thumb, $route_photo, '100');
echo '';// add this line
ImageDestroy($thumb);
...
in the other script instead of
echo ("");
do this:
require("include/function_gd.php?route_photo=$thumb");
Jos
-Original Message-
From: Craig Hoffman [mailto:[EMAIL PROTECTED]
Sent: 06 April 2005 18:12
To: php-db@lists.php.net
Cc: Juffermans, Jos
Subject: Re: [PHP-DB] One more GD ? -- filename
Hi Jos,
I understand what your saying. The problem is all the image names are
listed in the DB (image.jpg, image1.jpg and so on) and all images have
titles attached. For example,
Title: Large Green Sea Turtle
Image: LargeGreenSeaTurtle.jpg
As you can see, the GD script randomly pulls photo names from the DB
and shows them. When I output the image with using the image tag I get
a blank variable.
Since the image name is empty, I can not match/query the title and
image. The image output may be showing a Blue Sea Turtle but the
title says, Green Sea Turtle. If I could just get the image name, I
could run a query to match them. Does this make sense?
On Apr 6, 2005, at 10:36 AM, Juffermans, Jos wrote:
> Hi,
>
> If I understand correctly, you're using
> "include/function_gd.php?route_photo=$thumb" as image source which is
> the
> script you pasted. If you use a script as image source, the script
> should
> output the image data - not just store the image.
>
> I'm not sure what you're trying to do but if you have an image object
> in php
> (eg $thumb), you should output that image:
>
>$thumb = ImageCreateTrueColor($new_width, $new_height);
> $tmp_image = ImageCreateFromJPEG("../images/climbs/$route_photo");
> ImageCopyResampled($thumb, $tmp_image, 0, 0, 0, 0, $new_width,
> $new_height, $width_orig, $height_orig);
> header("Content-type: image/jpeg"); // tell the browser
> to expect a JPG
> imagejpeg($thumb, "", 100); // send the image to
> the browser (filename="" => output instead of save)
> exit();
> ?>
>
> However, you cannot use that to show multiple images from 1 script.
>
> Jos
>
>
> -Original Message-
> From: Craig Hoffman [mailto:[EMAIL PROTECTED]
> Sent: 06 April 2005 15:24
> To: php-db@lists.php.net
> Subject: [PHP-DB] One more GD ? -- filename
>
>
> Thanks everyone for answering my other post. However, I'm still having
> trouble passing the image name from the GD script to the image tag.
> I'm including the GD script below. Any help would be great. Thanks -
> Craig
>
> //GD script
>include ("db.php");
> $query = "SELECT route_photo FROM routes WHERE route_photo IS NOT
> NULL
> ORDER BY RAND() LIMIT 1";
> $result = mysql_query($query, $db) or die(mysql_error());
>
> while($row = mysql_fetch_array($result)) {
>
> //Photo varibale
> $route_photo = $row["route_photo"];
>
> //Start GD
> //New Image resize
> $new_width = 125;
> $new_height = 225;
>
> //Content Type
> header("Content-type: image/jpeg");
>
> //Start new image resize
> list($width_orig, $height_orig) =
> getImageSize("../images/climbs/$route_photo");
>
> if ($new_width && ($width_orig < $height_orig)) {
> $new_width = ($new_height / $height_orig) *
> $width_orig;
> } else {
> $new_height = ($new_width / $width_orig) *
> $height_orig;
> }
>
> //resample the image
> $thumb = ImageCreateTrueColor($new_width, $new_height);
> $tmp_image =
> ImageCreateFromJPEG("../images/climbs/$route_photo");
> ImageCopyResampled($thumb, $tmp_image, 0, 0, 0, 0,
> $new_width,
> $new_height, $width_orig, $height_orig);
>
> ImageJPEG($thumb, $route_photo, '100');
> ImageDestroy($thumb);
> }
> ?>
>
> //Image Tag:
> echo (" align='center' id='image'>");
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] One more GD ? -- filename
Hi Jos,
I understand what your saying. The problem is all the image names are
listed in the DB (image.jpg, image1.jpg and so on) and all images have
titles attached. For example,
Title: Large Green Sea Turtle
Image: LargeGreenSeaTurtle.jpg
As you can see, the GD script randomly pulls photo names from the DB
and shows them. When I output the image with using the image tag I get
a blank variable.
Since the image name is empty, I can not match/query the title and
image. The image output may be showing a Blue Sea Turtle but the
title says, Green Sea Turtle. If I could just get the image name, I
could run a query to match them. Does this make sense?
On Apr 6, 2005, at 10:36 AM, Juffermans, Jos wrote:
Hi,
If I understand correctly, you're using
"include/function_gd.php?route_photo=$thumb" as image source which is
the
script you pasted. If you use a script as image source, the script
should
output the image data - not just store the image.
I'm not sure what you're trying to do but if you have an image object
in php
(eg $thumb), you should output that image:
output instead of save)
exit();
?>
However, you cannot use that to show multiple images from 1 script.
Jos
-Original Message-
From: Craig Hoffman [mailto:[EMAIL PROTECTED]
Sent: 06 April 2005 15:24
To: php-db@lists.php.net
Subject: [PHP-DB] One more GD ? -- filename
Thanks everyone for answering my other post. However, I'm still having
trouble passing the image name from the GD script to the image tag.
I'm including the GD script below. Any help would be great. Thanks -
Craig
//GD script
while($row = mysql_fetch_array($result)) {
//Photo varibale
$route_photo = $row["route_photo"];
//Start GD
//New Image resize
$new_width = 125;
$new_height = 225;
//Content Type
header("Content-type: image/jpeg");
//Start new image resize
list($width_orig, $height_orig) =
getImageSize("../images/climbs/$route_photo");
if ($new_width && ($width_orig < $height_orig)) {
$new_width = ($new_height / $height_orig) *
$width_orig;
} else {
$new_height = ($new_width / $width_orig) *
$height_orig;
}
//resample the image
$thumb = ImageCreateTrueColor($new_width, $new_height);
$tmp_image =
ImageCreateFromJPEG("../images/climbs/$route_photo");
ImageCopyResampled($thumb, $tmp_image, 0, 0, 0, 0,
$new_width,
$new_height, $width_orig, $height_orig);
ImageJPEG($thumb, $route_photo, '100');
ImageDestroy($thumb);
}
?>
//Image Tag:
echo ("");
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] One more GD ? -- filename
Hi,
If I understand correctly, you're using
"include/function_gd.php?route_photo=$thumb" as image source which is the
script you pasted. If you use a script as image source, the script should
output the image data - not just store the image.
I'm not sure what you're trying to do but if you have an image object in php
(eg $thumb), you should output that image:
output instead of save)
exit();
?>
However, you cannot use that to show multiple images from 1 script.
Jos
-Original Message-
From: Craig Hoffman [mailto:[EMAIL PROTECTED]
Sent: 06 April 2005 15:24
To: php-db@lists.php.net
Subject: [PHP-DB] One more GD ? -- filename
Thanks everyone for answering my other post. However, I'm still having
trouble passing the image name from the GD script to the image tag.
I'm including the GD script below. Any help would be great. Thanks -
Craig
//GD script
//Image Tag:
echo ("");
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] One more GD ? -- filename
I believe the problem is somewhere in the GD script. Because when I
view the source it shows an empty variable. I should at least see the
name of variable in the source. Any ideas?
On Apr 6, 2005, at 9:46 AM, Bastien Koert wrote:
Have a look here...I have some sample code on calling images from a
db. It used the two pages like you do here and passes the ID back and
forth to the image production page...maybe it will help
http://www.weberdev.com/get_example-4062.html
bastien
From: Craig Hoffman <[EMAIL PROTECTED]>
To: php-db@lists.php.net
Subject: [PHP-DB] One more GD ? -- filename
Date: Wed, 6 Apr 2005 08:23:40 -0500
Thanks everyone for answering my other post. However, I'm still
having trouble passing the image name from the GD script to the image
tag. I'm including the GD script below. Any help would be great.
Thanks - Craig
//GD script
include ("db.php");
$query = "SELECT route_photo FROM routes WHERE route_photo IS NOT
NULL ORDER BY RAND() LIMIT 1";
$result = mysql_query($query, $db) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
//Photo varibale
$route_photo = $row["route_photo"];
//Start GD
//New Image resize
$new_width = 125;
$new_height = 225;
//Content Type
header("Content-type: image/jpeg");
//Start new image resize
list($width_orig, $height_orig) =
getImageSize("../images/climbs/$route_photo");
if ($new_width && ($width_orig < $height_orig)) {
$new_width = ($new_height / $height_orig) *
$width_orig;
} else {
$new_height = ($new_width / $width_orig) *
$height_orig;
}
//resample the image
$thumb = ImageCreateTrueColor($new_width, $new_height);
$tmp_image = ImageCreateFromJPEG("../images/climbs/$route_photo");
ImageCopyResampled($thumb, $tmp_image, 0, 0, 0, 0, $new_width,
$new_height, $width_orig, $height_orig);
ImageJPEG($thumb, $route_photo, '100');
ImageDestroy($thumb);
}
?>
//Image Tag:
echo ("");
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] One more GD ? -- filename
Have a look here...I have some sample code on calling images from a db. It
used the two pages like you do here and passes the ID back and forth to the
image production page...maybe it will help
http://www.weberdev.com/get_example-4062.html
bastien
From: Craig Hoffman <[EMAIL PROTECTED]>
To: php-db@lists.php.net
Subject: [PHP-DB] One more GD ? -- filename
Date: Wed, 6 Apr 2005 08:23:40 -0500
Thanks everyone for answering my other post. However, I'm still having
trouble passing the image name from the GD script to the image tag. I'm
including the GD script below. Any help would be great. Thanks - Craig
//GD script
include ("db.php");
$query = "SELECT route_photo FROM routes WHERE route_photo IS NOT NULL
ORDER BY RAND() LIMIT 1";
$result = mysql_query($query, $db) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
//Photo varibale
$route_photo = $row["route_photo"];
//Start GD
//New Image resize
$new_width = 125;
$new_height = 225;
//Content Type
header("Content-type: image/jpeg");
//Start new image resize
list($width_orig, $height_orig) =
getImageSize("../images/climbs/$route_photo");
if ($new_width && ($width_orig < $height_orig)) {
$new_width = ($new_height / $height_orig) *
$width_orig;
} else {
$new_height = ($new_width / $width_orig) *
$height_orig;
}
//resample the image
$thumb = ImageCreateTrueColor($new_width, $new_height);
$tmp_image = ImageCreateFromJPEG("../images/climbs/$route_photo");
ImageCopyResampled($thumb, $tmp_image, 0, 0, 0, 0, $new_width,
$new_height, $width_orig, $height_orig);
ImageJPEG($thumb, $route_photo, '100');
ImageDestroy($thumb);
}
?>
//Image Tag:
echo ("");
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] One more GD ? -- filename
Thanks everyone for answering my other post. However, I'm still having
trouble passing the image name from the GD script to the image tag.
I'm including the GD script below. Any help would be great. Thanks -
Craig
//GD script
include ("db.php");
$query = "SELECT route_photo FROM routes WHERE route_photo IS NOT NULL
ORDER BY RAND() LIMIT 1";
$result = mysql_query($query, $db) or die(mysql_error());
while($row = mysql_fetch_array($result)) {
//Photo varibale
$route_photo = $row["route_photo"];
//Start GD
//New Image resize
$new_width = 125;
$new_height = 225;
//Content Type
header("Content-type: image/jpeg");
//Start new image resize
list($width_orig, $height_orig) =
getImageSize("../images/climbs/$route_photo");
if ($new_width && ($width_orig < $height_orig)) {
$new_width = ($new_height / $height_orig) * $width_orig;
} else {
$new_height = ($new_width / $width_orig) * $height_orig;
}
//resample the image
$thumb = ImageCreateTrueColor($new_width, $new_height);
$tmp_image = ImageCreateFromJPEG("../images/climbs/$route_photo");
ImageCopyResampled($thumb, $tmp_image, 0, 0, 0, 0, $new_width,
$new_height, $width_orig, $height_orig);
ImageJPEG($thumb, $route_photo, '100');
ImageDestroy($thumb);
}
?>
//Image Tag:
echo ("");
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
