);
echo("Longitude: " . $row["ZG_LONGITUDE"]. "");
}
I get no results with this still, it acutally doesn't even go to the this
page. When I uncomment out:
//echo ($Lat1);
//echo ($Lat2);
//echo ($Lon1);
//echo ($Lon2);
and comment out everything below this,
n) = mysql_fetch_row($res);
$Lat1=Lat-2; $Lat2=Lat+2; $Lon1=Lon-2; $Lon2=Lat+2;
Now you can use the values in your final query.
Hth Henrik Hornemann
-Oprindelig meddelelse-
Fra: ReClMaples [mailto:[EMAIL PROTECTED]
Sendt: 16. april 2005 22:38
Til: php-db@lists.php.net
Emne: [PHP-DB] PH
Hello, I'm kinda new at PHP programming with MySQL. I am having an issue
and am not sure if this is the corret way to do this: Here is my code, I'll
start there:
Error performing query: " .
mysql_error() . "");
exit();
}
$Lat2 = mysql_query(
"SELECT (ZG_LATITUDE+2) FR
