Re: [PHP-DB] Problem with select-tag within a php-script

[- Edwin -]

Hi,

Ruprecht Helms [EMAIL PROTECTED] wrote:

[snip]
 while($row = mysql_fetch_object($result))
 {
 echo option value=\'.$row-ID.\';
[/snip]

Should be:

  echo option value=' .$row-ID. ';

 ?

- E -
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[PHP-DB] Problem with select-tag within a php-script

[Ruprecht Helms]

Hi,

I've some trouble with a select-tag in a php-script.
In a database should be written the ID of a table, the user could select
the recordset by the Name. My problem is that the fieldentry of the
selecttag is not transfered to the executionscript. The different Names
within the recordset are shown correctly.

Here my listing

?
mysql_connect(localhost,root);
$result=mysql_db_query(chorportal,SELECT * FROM choere ORDER BY
Name);
echo select value='chorid';
while($row = mysql_fetch_object($result))
{
echo option value=\'.$row-ID.\';
echo $row-Name;
echo /option;
}
echo /select;
?

Regards,
Ruprecht


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RE: [PHP-DB] Problem with select-tag within a php-script

[Snijders, Mark]

the select has to be a name and not the id

the id has to be within the option value!



-Original Message-
From: Ruprecht Helms [mailto:[EMAIL PROTECTED]
Sent: woensdag 2 juli 2003 15:51
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Problem with select-tag within a php-script


Hi,

I've some trouble with a select-tag in a php-script.
In a database should be written the ID of a table, the user could select
the recordset by the Name. My problem is that the fieldentry of the
selecttag is not transfered to the executionscript. The different Names
within the recordset are shown correctly.

Here my listing

?
mysql_connect(localhost,root);
$result=mysql_db_query(chorportal,SELECT * FROM choere ORDER BY
Name);
echo select value='chorid';
while($row = mysql_fetch_object($result))
{
echo option value=\'.$row-ID.\';
echo $row-Name;
echo /option;
}
echo /select;
?

Regards,
Ruprecht


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