[PHP-DB] Re: Hi,
John Jairo Vega Angulo wrote: Hi, How are u doing these days?Yesterday I found a web of a large trading company from china,which is an agent of all the well-known digital product factories,and facing to both wholesalers,retailsalers,and personal customer all over the world. They export all kinds of digital products and offer most competitive and reasonable price and high quality goods for our clients,so i think we you make a big profit if we do business with them.And they promise they will provide the best after-sales-service.In my opinion we can make a trial order to test that. Look forward to your early reply! The Web address:http://www.mwhdy.com/ Hi John Jairo Vega Angulo, I'm doing well. Wow! That's truly awesome! I'm all about promises, let's do a trial order! Happy Independence Day! -Shawn -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Hi I am new
Since you didn't mention what database you are using I'm assuming MySQL. Here's a good place to start: http://dev.mysql.com/tech-resources/articles/ddws/ "Water_foul" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > I am new to databases and php and I was wondering if any one would point me > to a good guide > anything would help :) > thanks in advance, > water_foul -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Hi I am new to PHP
[EMAIL PROTECTED] (Andy Amol) wrote in news:[EMAIL PROTECTED]: > > I have posted my problem at No: 33892 of this mailing list. I have > received 1 reply. No: 33897 > > My exact problem with second file is as follows: > > Warning: mysql_num_rows(): supplied argument is not a valid MySQL > result resource on line 15 > > > Can you help me to solve problem, any help would be appreciated. > > Thanks. Your sql syntax is probably wrong. Somewhere before line 15 you are presumably using mysql_query to submit your query. Try adding to that line or exit( 'Error: ' .mysql_error() ); which will halt your script and return a useful error string from mysql if there is an error. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Hi I am new to PHP
It means there is a problem with your query, if you send the query back to the group someone may be able to help. "Andy Amol" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > > I have posted my problem at No: 33892 of this mailing list. I have received 1 reply. No: 33897 > > My exact problem with second file is as follows: > > Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource on line 15 > > > Can you help me to solve problem, any help would be appreciated. > > Thanks. > > > > - > Do you Yahoo!? > Yahoo! Tax Center - File online by April 15th -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: Hi, simple question
Hi,
or u can just try "select last_insert_id() from test" - thats what i do.
however even mentioning the table-name doesn't seem to be necessary; i just
do it for readability.
-shiva
"Patrik Fomin" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi,
>
> im adding a post to the database, is there any way to retrive back the ID
> for the post that i just created?
>
> the id is auto_increment and primary key.
>
> like
> $sql = "insert into test (namn, www) values('test', 'test.com')";
> mysql_query($sql);
>
> $row = mysql_get_post("id");
> ?
>
> the only way i could think of was to create a tempfield in the database
and
> each time you post you give the temp field a unique value, like:
>
> $sql = "insert into test (namn, www, unique) values('test',
> 'test.com','25323324')";
> mysql_query($sql);
>
> $sql = "select id from test where unique = '25323324'";
> $res = mysql_query($sql);
>
>
> regards
> patrick
>
>
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