Hi Neil,
I have tried it like that with no luck, what is below just happens to be
my latest attempts to get it working.
What is happening is that it is saying that $C and $G are zero, when in
fact there is data in there.
How do I get it to 'refresh' the variables? That is what I am trying to
do with:
>$query = "SELECT C, G FROM media";
>$result = mysql_query($query);
-Original Message-
From: Neil Smith [MVP, Digital media]
[mailto:[EMAIL PROTECTED]
Sent: Friday, 25 June 2004 1:51 AM
To: [EMAIL PROTECTED]
Cc: Baiocchi, Justin (LI, Armidale)
Subject: Re: Subject: Update data problem
Is there any obvious reason why you're not doing this in one query
$query = "UPDATE media SET A='$A', B='$B', C='$C', G=E*'$C'";
Or have I missed something here ?
Cheers - Neil
At 10:07 24/06/2004 +, you wrote:
>MIME-Version: 1.0
>Content-Type: multipart/alternative;
> boundary="_=_NextPart_001_01C459A5.F8D9AF1D"
>Date: Thu, 24 Jun 2004 14:44:45 +1000
>Message-ID:
<[EMAIL PROTECTED]>
>From: <[EMAIL PROTECTED]>
>To: <[EMAIL PROTECTED]>
>Subject: Update data problem
>
>
>if($update)
>
>{
>
>mysql_pconnect("localhost","root","password");
>mysql_select_db("options");
>
>
>$query = "UPDATE media SET A='$A', B='$B', C='$C'";
>$result = mysql_query($query);
>
>$query = "SELECT C, G FROM media";
>$result = mysql_query($query);
>
>$E= "$C*$G";
>
>
>$query = "UPDATE media SET E='$E'";
>$result = mysql_query($query);
>
>}
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