Hi,
how can I display the stored data of an user as value in a formfield.
Actualy the formfield vorname shows no entry and the formfield name
shows .$row-Name.
What is the correct syntax in this case.
Regards,
Ruprecht
?
mysql_connect(localhost,user,password);
]
To: php-db@lists.php.net
Subject: [PHP-DB] Scriptproblem
Date: Tue, 24 Jan 2006 16:12:53 +0100
Hi,
how can I display the stored data of an user as value in a formfield.
Actualy the formfield vorname shows no entry and the formfield name
shows .$row-Name.
What is the correct syntax in this case
Hi,
Actually you have an undefined variable called $row which is in this
context ($row-Vorname) is an object...but $row has nor content
neither type.
I think you'd better use arrays...in this way:
(according to the PHP manual mysql_db_query() is decrepated)
?php
$link = mysql_connect(_host_,