Re: [PHP-DB] strings of variables,php, sql
--- George Patterson <[EMAIL PROTECTED]> wrote: > On Mon, 24 Nov 2003 21:36:29 -0800 (PST) > Joffrey Leevy <[EMAIL PROTECTED]> wrote: > > > Would appreciate in anyone can help me. > > > > Let's say I do a query in php, eg. $query = > "select > > shed from structure"; With the mysql_fetch_array > > function and a loop I could see all the values > stored > > in the column, shed, using the command: echo > $shed; > > > > Let's say now that I am carrying over a variable > from > > a form called $form where $form = shed. I can > still > > say $query = "select $form from structure"; > because > > $form = shed. > > > > The problem I have now is with the strings and how > do > > I see my column values. > > > > Using echo $$value; or echo $($value) or echo > \$$value > > or echo $"$value" does not give me the values > stored > > in the column shed. > > > > Help anyone? > > thanks > > > > Joffrey, > > First it is easier for us if you just paste the > relevant code but I'll > try and assist without. > > Before you can fetch a record you must query the > database.. > $result=mysql_query($query) or die( "Bad Query=> > $query\n". > mysql_error() ); > > The die() function will print an error if there is > something wrong with > the query such as database not opened first. > > You are fetching a row (or record) from the > database. > > $row=mysql_fetch_array($result); > > therefore the value of shed column will be contained > within $row. > > It can be accessed by either of the two lines below. > > echo $row[0]; #by numeric index.. > echo $row["shed"];#or by column name.. > > If you wish to find out all the column names and > values, try > > print_r($row); > > > George Patterson > Ok, I see, so if the column name was a variable called $form passed from a previous page where $form could hold any value (shed,house,bungalow, etc), then I could do echo $row[$form]; __ Do you Yahoo!? Free Pop-Up Blocker - Get it now http://companion.yahoo.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] strings of variables,php, sql
On Mon, 24 Nov 2003 21:36:29 -0800 (PST) Joffrey Leevy <[EMAIL PROTECTED]> wrote: > Would appreciate in anyone can help me. > > Let's say I do a query in php, eg. $query = "select > shed from structure"; With the mysql_fetch_array > function and a loop I could see all the values stored > in the column, shed, using the command: echo $shed; > > Let's say now that I am carrying over a variable from > a form called $form where $form = shed. I can still > say $query = "select $form from structure"; because > $form = shed. > > The problem I have now is with the strings and how do > I see my column values. > > Using echo $$value; or echo $($value) or echo \$$value > or echo $"$value" does not give me the values stored > in the column shed. > > Help anyone? > thanks > Joffrey, First it is easier for us if you just paste the relevant code but I'll try and assist without. Before you can fetch a record you must query the database.. $result=mysql_query($query) or die( "Bad Query=> $query\n". mysql_error() ); The die() function will print an error if there is something wrong with the query such as database not opened first. You are fetching a row (or record) from the database. $row=mysql_fetch_array($result); therefore the value of shed column will be contained within $row. It can be accessed by either of the two lines below. echo $row[0]; #by numeric index.. echo $row["shed"]; #or by column name.. If you wish to find out all the column names and values, try print_r($row); George Patterson -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] strings of variables,php, sql
Would appreciate in anyone can help me. Let's say I do a query in php, eg. $query = "select shed from structure"; With the mysql_fetch_array function and a loop I could see all the values stored in the column, shed, using the command: echo $shed; Let's say now that I am carrying over a variable from a form called $form where $form = shed. I can still say $query = "select $form from structure"; because $form = shed. The problem I have now is with the strings and how do I see my column values. Using echo $$value; or echo $($value) or echo \$$value or echo $"$value" does not give me the values stored in the column shed. Help anyone? thanks __ Do you Yahoo!? Free Pop-Up Blocker - Get it now http://companion.yahoo.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Strings
CC/Steve Thanks for the advice. I managed to get the "... Code = '".$row['Primaryexpertise']."'" option working but not the others. Thanks again. Regards Mick Lloyd [EMAIL PROTECTED] Tel: +44 (0)1684 560224 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP-DB] Strings
$row[Primaryexpertise] //not like this
$row['Primaryexpertise'] //like this
$row["Primaryexpertise"] //or like this
>i always user double quotes with postgrtesql and it works like a treat.
> the difference seems to be with mysql.
Also, even though simple variable references are expanded within
double-quotes (ex. "where Profileid = '$profileid'"), the PHP parser seems
to be less certain about how to deal with array indexes: is the square
bracket intedned as plain text, as a special character (such as in a
regular expression) or is it actually an array index? I find that dropping
out of quotes whenever referencing array indexes eliminates a lot of parse
errors. For example:
"select Primaryid from primarycodes where Code = '" .
$row['Primaryexpertise'] . "'"
Another option is to use extract() so that the array element can be treated
as a simple string variable:
extract($row);
$result = mysql_query("select Primaryid from primarycodes where Code =
'$Primaryexpertise'")
> String manipulation has me baffled most of the time!
Re-read the manual's chapters on strings and arrays. Also check out the
Zend site. There are some interesting articles and tutorials over there
that address issues not yet adequately covered in the manual.
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Re: [PHP-DB] Strings
In article <003801c0afa2$2d5853e0$890083ca@oemcomputer>,
[EMAIL PROTECTED] ("Mick Lloyd") wrote:
> Can anyone advise on how to surround a string variable in a query. I select
> a string code from a column using:
>
> $result = mysql_query("SELECT * FROM $TA WHERE Profileid = '$profileid'");
> $row = mysql_fetch_array($result);
>
> I then want to extract from a second table an id that relates to the code
> from the first query. I've tried various combinations of:
>
> $result = mysql_query("select Primaryid from primarycodes where Code =
> '$row[Primaryexpertise]'")
Associate array indexes should be quoted:
$row[Primaryexpertise] //not like this
$row['Primaryexpertise'] //like this
$row["Primaryexpertise"] //or like this
Also, even though simple variable references are expanded within
double-quotes (ex. "where Profileid = '$profileid'"), the PHP parser seems
to be less certain about how to deal with array indexes: is the square
bracket intedned as plain text, as a special character (such as in a
regular expression) or is it actually an array index? I find that dropping
out of quotes whenever referencing array indexes eliminates a lot of parse
errors. For example:
"select Primaryid from primarycodes where Code = '" .
$row['Primaryexpertise'] . "'"
Another option is to use extract() so that the array element can be treated
as a simple string variable:
extract($row);
$result = mysql_query("select Primaryid from primarycodes where Code =
'$Primaryexpertise'")
> String manipulation has me baffled most of the time!
Re-read the manual's chapters on strings and arrays. Also check out the
Zend site. There are some interesting articles and tutorials over there
that address issues not yet adequately covered in the manual.
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[PHP-DB] Strings
Can anyone advise on how to surround a string variable in a query. I select
a string code from a column using:
$result = mysql_query("SELECT * FROM $TA WHERE Profileid = '$profileid'");
$row = mysql_fetch_array($result);
I then want to extract from a second table an id that relates to the code
from the first query. I've tried various combinations of:
$result = mysql_query("select Primaryid from primarycodes where Code =
'$row[Primaryexpertise]'")
with =, ==, ===, ', \", but always get a syntax error. I can get it to
work with LIKE as follows:
$result = mysql_query("select Primaryid from primarycodes where Code like
'%$row[Primaryexpertise]%'")
but I need greater accuracy because some codes contain similar data. String
manipulation has me baffled most of the time!
Thanks.
Mick Lloyd
[EMAIL PROTECTED]
Tel: +44 (0)1684 560224
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