[PHP-DB] Updating count on record results

2004-11-19 Thread Stuart Felenstein
I am setting up a table to log a count on individual
records for every time they are returned in a results
return.

Just so to illustrate 

Record1 

First search brings up Record1 (counter is set too 1)
Second search brings up Record1 (counter is set too 2)
Third search brings up Record1 (counter is set too 3)
...etc.

So I have a vauge idea of the sql statement but where
to place is the question. My thoughts are that it
should be in the loop that generates the result rows
return.  In other words - 

Maybe here :
?php echo $row_rsVJ['JobTitle']; ?/div/td

Or maybe here ?: 
?php } while ($row_rsVJ = mysql_fetch_assoc($rsVJ));
?

Hope what I'm asking is clear.

Thank you ,
Stuart

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RE: [PHP-DB] Updating count on record results

2004-11-19 Thread Bastien Koert
this is how I did it for a client's site
// update the number of times the vehicle has been viewed
mysql_db_query($dbname, UPDATE vehicle_inventory SET viewed=viewed+1 WHERE 
ccode='$ccode', $link);

bastien
From: Stuart Felenstein [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Updating count on record results
Date: Fri, 19 Nov 2004 04:59:20 -0800 (PST)
I am setting up a table to log a count on individual
records for every time they are returned in a results
return.
Just so to illustrate
Record1
First search brings up Record1 (counter is set too 1)
Second search brings up Record1 (counter is set too 2)
Third search brings up Record1 (counter is set too 3)
...etc.
So I have a vauge idea of the sql statement but where
to place is the question. My thoughts are that it
should be in the loop that generates the result rows
return.  In other words -
Maybe here :
?php echo $row_rsVJ['JobTitle']; ?/div/td
Or maybe here ?:
?php } while ($row_rsVJ = mysql_fetch_assoc($rsVJ));
?
Hope what I'm asking is clear.
Thank you ,
Stuart
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RE: [PHP-DB] Updating count on record results

2004-11-19 Thread Stuart Felenstein

--- Bastien Koert [EMAIL PROTECTED] wrote:

 this is how I did it for a client's site
 
 // update the number of times the vehicle has been
 viewed
 mysql_db_query($dbname, UPDATE vehicle_inventory
 SET viewed=viewed+1 WHERE 
 ccode='$ccode', $link);
 
Where did this code go though ? Meaning, was it in a
seperate script / page or was it part of a bigger
query that first got the results based on certain
criteria , the did the update?

Stuart

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RE: [PHP-DB] Updating count on record results

2004-11-19 Thread Bastien Koert
its a separate query on the same page, its activated after the data 
retreival query runs.

?
...
// get the information for this vehicle
$result = mysql_db_query($dbname, SELECT * FROM vehicle_inventory WHERE 
ccode='$ccode', $link);
$data = mysql_fetch_array($result);
$data[comments] = nl2br($data[comments]);

// update the number of times the vehicle has been viewed
mysql_db_query($dbname, UPDATE vehicle_inventory SET viewed=viewed+1 WHERE 
ccode='$ccode', $link);

...?
bastien
From: Stuart Felenstein [EMAIL PROTECTED]
To: Bastien Koert [EMAIL PROTECTED], [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Updating count on record results
Date: Fri, 19 Nov 2004 07:28:48 -0800 (PST)
--- Bastien Koert [EMAIL PROTECTED] wrote:
 this is how I did it for a client's site

 // update the number of times the vehicle has been
 viewed
 mysql_db_query($dbname, UPDATE vehicle_inventory
 SET viewed=viewed+1 WHERE
 ccode='$ccode', $link);

Where did this code go though ? Meaning, was it in a
seperate script / page or was it part of a bigger
query that first got the results based on certain
criteria , the did the update?
Stuart
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