On Feb 18, 2008 6:56 PM, Chris <[EMAIL PROTECTED]> wrote:
> $query = "INSERT INTO artist (name,about_u,imgdata, profile_url)
> VALUES('$aname','$aboutu','$uploadedImage','$url_provided')";
>
> You have an sql injection problem here. Read up about that on the
> phpsec.org site:
>
> http://phpsec.org
On Feb 18, 2008 6:56 PM, Chris <[EMAIL PROTECTED]> wrote:
> Which bit breaks exactly? Nobody's going to read through 200 lines of code..
Normally, you're right but today I did just to be a jerk and
prove you wrong. ;-P
> Nasreen Laghari wrote:
> > Hi All,
> >
> > First of all A very big
Nasreen Laghari wrote:
Hi All,
First of all A very big thank you to all of you for solving my Password()
encryption problem.
Now I'm stuck on new problem which is image not uploading. I'm using the following code.
Which bit breaks exactly? Nobody's going to read through 200 lines of code..
Hi All,
First of all A very big thank you to all of you for solving my Password()
encryption problem.
Now I'm stuck on new problem which is image not uploading. I'm using the
following code.
Regards
Nasreen
0){
echo "Image has been inserted succesfully";
}
else {
echo "Image can no
Hi All,
First of all A very big thank you to all of you for solving my Password()
encryption problem.
Now I'm stuck on new problem which is image not uploading. I'm using the
following code.
Regards
Nasreen
0){
echo "Image has been inserted succesfully";
}
else {
echo "Image can not be i
