[PHP-DB] Warning: Unable to jump to row...

2003-03-31 Thread Benjamin Trépanier
Hi, I'm trying to using a news script and improve somes with a query. $req = MYSQL_QUERY(SELECT * FROM $TBL_NEWS); $res = MYSQL_NUM_ROWS($req); ? table border=0 width=400 cellspacing=0 cellpadding=0 tr td img src=img/titre_calendrier.gif alt= width=404 height=51 border=0 ?

Re: [PHP-DB] Warning: Unable to jump to row...

2003-03-31 Thread Ronan Chilvers
Hi Ben Comments inline On 31 Mar,2003 at 13:46 Benjamin Trépanier wrote: snip border=0 ? $i!=$id_news_ $id= mysql_result($req,$i,id); $titre = mysql_result($req,$i,titre); $date = mysql_result($req,$i,date); $heure = mysql_result($req,$i,heure);