RE: [PHP-DB] exporting to xml

2002-10-29 Thread Beau Lebens
you don't see them because they are interpreted as HTML tags, they are
unknown, so they are ignored.

options;

1. View -> Source

2. Encode all "<" as < (HTML version) and it will display it all
   as text, then you can copy-paste it to somewhere else

3. Wrap it all in a  tag, then follow 2.

4. Output the proper XML declaration at the top of the file so that
   IE treats it like XML, and does it's fancy dynamic-tree style
   presentation.

   

   ^--- a very basic XML declaration

HTH

Beau

// -Original Message-
// From: Martin Hudec [mailto:corwin@;corwin.sk]
// Sent: Wednesday, 30 October 2002 12:00 AM
// To: [EMAIL PROTECTED]
// Subject: [PHP-DB] exporting to xml
// 
// 
// Hello,
// 
//   i am creating script which will make select and desc to table and
//   then based on results it will make xml file...all is okay, 
// but on my
//   IE it takes it as xml file (it is okay) BUT on my screen I dont see
//   any of  tags...how can i override that?
// 
//   script is here:
// 
// header("Content-type: text/xml");
// 
// db related stuff...
// 
// $fcount = mysql_num_fields($result);
// 
// print ""; //will be table name
// 
// while($row = mysql_fetch_array($result)){
// print "";
// for($i=0; $i<$fcount; $i++){
// $tag = mysql_field_name($result,$i);
// print "<$tag>". $row[$i]. "";
// }
// print "";
// }
// 
// -- 
// Best regards,
//  Martin  mailto:corwin@;corwin.sk
// 
// 
// -- 
// PHP Database Mailing List (http://www.php.net/)
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// 

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[PHP-DB] exporting to xml

2002-10-29 Thread Martin Hudec
Hello,

  i am creating script which will make select and desc to table and
  then based on results it will make xml file...all is okay, but on my
  IE it takes it as xml file (it is okay) BUT on my screen I dont see
  any of  tags...how can i override that?

  script is here:

header("Content-type: text/xml");

db related stuff...

$fcount = mysql_num_fields($result);

print ""; //will be table name

while($row = mysql_fetch_array($result)){
print "";
for($i=0; $i<$fcount; $i++){
$tag = mysql_field_name($result,$i);
print "<$tag>". $row[$i]. "";
}
print "";
}

-- 
Best regards,
 Martin  mailto:corwin@;corwin.sk


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