Re: [PHP-DB] isset or ! isset what is my problem?
Actually this has nothing to do with rows. I'm just trying to substitute a value when a query returns an empty value. On Jan 3, 2006, at 5:24 AM, El Bekko wrote: On Monday 02 January 2006 7:54 pm, Ralph wrote: I'm building a URL based on data extracted from mySQL and I want the text space.gif used as my default value should the variable $picture by NULL. The results of the code below kick back a value for $picture when it is set in the database, but ignores the space.gif if the database result is empty. If I flip the test from ! isset to isset then I get the space.gif for each result. I've had no luck searching out an answer. Thanks in advance. --The Code- > span> > span> Showtime: Location: ---END- Seeing as you're querying, use mysql_num_rows() to check. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] isset or ! isset what is my problem?
On Monday 02 January 2006 7:54 pm, Ralph wrote: I'm building a URL based on data extracted from mySQL and I want the text space.gif used as my default value should the variable $picture by NULL. The results of the code below kick back a value for $picture when it is set in the database, but ignores the space.gif if the database result is empty. If I flip the test from ! isset to isset then I get the space.gif for each result. I've had no luck searching out an answer. Thanks in advance. --The Code- Showtime: Location: ---END- Seeing as you're querying, use mysql_num_rows() to check. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] isset or ! isset what is my problem?
NULL != Not set. isset() tests to see if the variable exists. If your variable has a null value it is set, it DOES exist, it just has NULL for a value. You should test for a null value if that's what you want: if ($picture == null) Or perhaps the empty() function might be what you're looking for. -Micah On Monday 02 January 2006 7:54 pm, Ralph wrote: > I'm building a URL based on data extracted from mySQL and I want the > text space.gif used as my default value should the variable $picture > by NULL. > > The results of the code below kick back a value for $picture when it > is set in the database, but ignores the space.gif if the database > result is empty. > > If I flip the test from ! isset to isset then I get the space.gif for > each result. > > > I've had no luck searching out an answer. > > Thanks in advance. > > --The Code- > > > span> > span> > > Showtime: ['ShowTime']; ?> > Location: ['Location']; ?> > > ($rst_screenings)); ?> > > ---END- -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] isset or ! isset what is my problem?
On Monday 02 January 2006 8:54 pm, Ralph wrote: > I'm building a URL based on data extracted from mySQL and I want the > text space.gif used as my default value should the variable $picture > by NULL. > > The results of the code below kick back a value for $picture when it > is set in the database, but ignores the space.gif if the database > result is empty. Have you tried strlen()? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] isset or ! isset what is my problem?
I'm building a URL based on data extracted from mySQL and I want the text space.gif used as my default value should the variable $picture by NULL. The results of the code below kick back a value for $picture when it is set in the database, but ignores the space.gif if the database result is empty. If I flip the test from ! isset to isset then I get the space.gif for each result. I've had no luck searching out an answer. Thanks in advance. --The Code- span> span> Showtime: ['ShowTime']; ?> Location: ['Location']; ?> ($rst_screenings)); ?> ---END-
