Re: [PHP-DB] parameters not working under PDO
Ah, but the *contents* of the array are not what I thought they were...there was a leading space in "nj". Which brings me to something I've been wondering...is there a way to get the statement object to tell me EXACTLY what was sent to the database engine? Chris Curvey wrote: good thing to check...it seems to be OK. Array ( [0] => montclair [1] => nj ) Michael Preslar wrote: Check $parts.. print_r($parts) and make sure its 1) an array 2) contains 2 values -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] parameters not working under PDO
good thing to check...it seems to be OK.
Array ( [0] => montclair [1] => nj )
Michael Preslar wrote:
Check $parts.. print_r($parts) and make sure its 1) an array 2)
contains 2 values
On 10/31/07, Chris Curvey <[EMAIL PROTECTED]> wrote:
It's quite possible that I'm missing something obvious here. The
following code fragment does not return any rows, but if I take out the
parameters and replace them with hardcoded strings (enclosed in single
quotes), I get the right results.
I've scattered "print" statements throughout, and the query seems to get
past execute() OK, it's just not returning anything from the call to fetch()
Am I missing something obvious?
$stmt = $conn->prepare("select t.z from towns t
join counties c on t.county_z = c.z
where t.me = ?
and c.state_z = ?");
if ($stmt->execute($parts)) {
while ($row = $stmt->fetch()) {
$town_z = $row['z'];
}
} else {
print $stmt->errorCode();
print_r($stmt->errorInfo());
}
Thanks in advance!
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] parameters not working under PDO
Check $parts.. print_r($parts) and make sure its 1) an array 2)
contains 2 values
On 10/31/07, Chris Curvey <[EMAIL PROTECTED]> wrote:
> It's quite possible that I'm missing something obvious here. The
> following code fragment does not return any rows, but if I take out the
> parameters and replace them with hardcoded strings (enclosed in single
> quotes), I get the right results.
>
> I've scattered "print" statements throughout, and the query seems to get
> past execute() OK, it's just not returning anything from the call to fetch()
>
> Am I missing something obvious?
>
> $stmt = $conn->prepare("select t.z from towns t
> join counties c on t.county_z = c.z
> where t.me = ?
> and c.state_z = ?");
> if ($stmt->execute($parts)) {
> while ($row = $stmt->fetch()) {
> $town_z = $row['z'];
> }
> } else {
> print $stmt->errorCode();
> print_r($stmt->errorInfo());
> }
>
> Thanks in advance!
>
> --
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] parameters not working under PDO
O/H Chris Curvey ??:
It's quite possible that I'm missing something obvious here. The
following code fragment does not return any rows, but if I take out
the parameters and replace them with hardcoded strings (enclosed in
single quotes), I get the right results.
I've scattered "print" statements throughout, and the query seems to
get past execute() OK, it's just not returning anything from the call
to fetch()
Am I missing something obvious?
$stmt = $conn->prepare("select t.z from towns t
join counties c on t.county_z = c.z
where t.me = ?
and c.state_z = ?");
if ($stmt->execute($parts)) {
while ($row = $stmt->fetch()) {
$town_z = $row['z'];
}
What is $parts doing ?? You just need execute() and I suppose although
not posted that you did construct the object like:
$conn| = new PDO('mysql:host=localhost;dbname=test', $user, $pass);
|A good choice is to tell fetch a way to retrieve your data like this:
$town_z = $stmt->fetch(PDO::FETCH_ASSOC);
although I think that it will get both result sets in case you don't define.
} else {
print $stmt->errorCode();
print_r($stmt->errorInfo());
}
Thanks in advance!
A better way debug that I know is using exceptions like:
try {
$sth = $conn->query($query);
$rs = $sth->fetch();
} catch (Exception $e) {
print "failed :".$e->getMessage();
}
You can use try {} with almost everything so give it a "try" :-) .
Send us some feed back or post full source if you keep having trouble.
--
Thodoris
[PHP-DB] parameters not working under PDO
It's quite possible that I'm missing something obvious here. The
following code fragment does not return any rows, but if I take out the
parameters and replace them with hardcoded strings (enclosed in single
quotes), I get the right results.
I've scattered "print" statements throughout, and the query seems to get
past execute() OK, it's just not returning anything from the call to fetch()
Am I missing something obvious?
$stmt = $conn->prepare("select t.z from towns t
join counties c on t.county_z = c.z
where t.me = ?
and c.state_z = ?");
if ($stmt->execute($parts)) {
while ($row = $stmt->fetch()) {
$town_z = $row['z'];
}
} else {
print $stmt->errorCode();
print_r($stmt->errorInfo());
}
Thanks in advance!
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
