Hi Nick,
Assuming you have the rest of the databse interaction, all you need to is
store the value of the selection (the store script will recieve a varialbe
$state=AK or whatever.
To then display the users state do the following
//Get the users state from the database
//do this however appropiate in your code
$users_state = AK; //(for the sake of argument)
//create array of states (better way of making the form
$states = array(AK,AR,);
$numstates=count($states);
echo(select name=\state\);
for($i=0;$inumstates;$i++)
{
$currstate=$states[$i];
echo(option value=\$currstate\); //print first part of statement
//if this option is the users add the selected keywork
if($currstate==$users_state) echo( SELECTED);
echo( $currstate);//finish the tag
}
echo(/select);
Hope this helps!
Tom
On Sun, 6 May 2001, Nick
Terzich wrote:
hi...
I have a user registration system that I need to add a
state field to. Part of the form will look something
like this but with all 50 states instead of just two:
form
select name=state
option value=AKAK/option
option value=ALAL/option
/select
/form
...how do I insert the user's state into the database
and then how do I show the user's state as the
selected state in the drop down list later when the
user comes back to update his/her profile?
hope this makes sense.. thanks,
nick
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