[PHP-DB] What's wrong with this QUERY??
Hi, I have a database with members details and PK is id. $thing = [EMAIL PROTECTED]; $query = SELECT id, email, familyname FROM members WHERE email=$thing; $result = mysql_query($query); If i do a query where id=$thing. and $thing=20; this works fine and I get the desired result. But what is wrong with the other one, when I do search for the email address?? The email address does exist exactly as quoted above in the email field in my members table but still doesn't produce any results. Any help is much appreciated. Harmeet -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this QUERY??
$thing = [EMAIL PROTECTED]; $query = SELECT id, email, familyname FROM members WHERE email=$thing; You need to quote non-numeric values in SQL. It should be $query = SELECT id, email, familyname FROM members WHERE email=''$thing'; Also, you don't really need to select the email value since you should already have it. Larry -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this QUERY??
--- Harry G [EMAIL PROTECTED] wrote: Hi, I have a database with members details and PK is id. $thing = [EMAIL PROTECTED]; $query = SELECT id, email, familyname FROM members WHERE email=$thing; Make it $query = SELECT id, email, familyname FROM members WHERE email='$thing'; It should work zareef ahmed $result = mysql_query($query); If i do a query where id=$thing. and $thing=20; this works fine and I get the desired result. But what is wrong with the other one, when I do search for the email address?? The email address does exist exactly as quoted above in the email field in my members table but still doesn't produce any results. Any help is much appreciated. Harmeet -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php = Zareef Ahmed :: A PHP Developer in Delhi(India). Homepage :: http://www.zasaifi.com __ Do you Yahoo!? Vote for the stars of Yahoo!'s next ad campaign! http://advision.webevents.yahoo.com/yahoo/votelifeengine/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this QUERY??
On Friday 23 July 2004 10:57, Harry G wrote: I have a database with members details and PK is id. $thing = [EMAIL PROTECTED]; $query = SELECT id, email, familyname FROM members WHERE email=$thing; $query = SELECT id, email, familyname FROM members WHERE email='$thing'; Please refer to some SQL primer to learn the basics of SQL. $result = mysql_query($query); Look at the examples in the manual to see how you can incorporate error checking into your code. In particular look at mysql_error(). If i do a query where id=$thing. and $thing=20; this works fine and I get the desired result. But what is wrong with the other one, when I do search for the email address?? Because your 'id' column is numeric and 'email' column is text. Text columns needs their values enclosed by quotes. The email address does exist exactly as quoted above in the email field in my members table but still doesn't produce any results. mysql_error() would let you know that there was an error in your query. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-db -- /* I don't wish to appear overly inquisitive, but are you still alive? */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] What's wrong with this IF statement?
My IF statement should be picking up on the numbers, and if the number
matches not be displaying out the information, however I look at the
outputted page and the information is still there, what have I got wrong
on the code?
CODE SNIPPET
//Show categories first
$get_cats = select id_num, id_name, description, cat_code from
categories order by id_name;
$get_cats_res = mysql_query($get_cats) or die(mysql_error());
if (mysql_num_rows($get_cats_res) 1)
{
$display_block = PemSorry, no categories to browse./em/P;
}
else
{
while ($cats = mysql_fetch_array($get_cats_res))
{
$cat_id = $cats[id_num];
if ($cat_id != 53 || $cat_id != 54 || $cat_id != 55 || $cat_id
!= 117 || $cat_id != 118 || $cat_id != 74)
{
$cat_title = strtoupper(stripslashes($cats[id_name]));
$cat_desc = stripslashes($cats[description]);
$display_block .= stronga
href=$_SERVER[PHP_SELF]?cat_id=$cat_id$cat_title
$cat_desc/a/strongbr\n;
while ($items = mysql_fetch_array($get_items_res))
{
$item_id = $items[id];
$item_num = $items[item_num];
$item_desc = stripslashes($items[description]);
if ($item_num != ABC-R37 || $item_num != ABC-R42 || $item_num
!= HB-99100 || $item_num != RO-PUMPS || $item_num != ML-HDGALJUG
|| $item_num != PFS-CAC21 || $item_num != PFS-CO2)
{
$item_num = ltrim($item_num);
$item_num = rtrim($item_num);
$display_block .= nbsp;nbsp;nbsp;nbsp;emstronga
href=\catalog/$item_id.html\$item_num/a/strong -
$item_desc/embr\n;
}
}
END SNIPPETS
My assumption is that BOTH IF statements are not working correctly since
the logic is that if they are built the same they would react the same.
HELP!
TIA!
Robert
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[PHP-DB] What's wrong with this query?
I've just tried to do something I've done a thousand times. It does not work. I've checked all of the syntax, made sure the field and variable names are correct. No matter what I do it just doesn't work. The table remains empty. Here's the query: $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); Now that doesn't look too difficult does it? Well, apparently it's impossible! I'm really hoping someone out there can see something that I missed. Nick -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
What is the error? there i something i always do when i have this problem, try this: error_reporting(E_ALL); $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); echo $sql; $logit = mysql_query($sql); This makes all kind of notice about uninitialized variables and other things that may cause problems, great for debugging, and the echo $sql prints the sql that is sent to the client, here you can see if one of the variable yo are sendding to the query have some kind of problem, like a ' in the middle, which could cause problems in your script. If you can't see the problem after this post the output of this code. - Original Message - From: Axel IS Main [EMAIL PROTECTED] To: PHP-DB [EMAIL PROTECTED] Sent: Thursday, February 26, 2004 9:05 AM Subject: [PHP-DB] What's wrong with this query? I've just tried to do something I've done a thousand times. It does not work. I've checked all of the syntax, made sure the field and variable names are correct. No matter what I do it just doesn't work. The table remains empty. Here's the query: $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); Now that doesn't look too difficult does it? Well, apparently it's impossible! I'm really hoping someone out there can see something that I missed. Nick -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] What's wrong with this query?
You haven't done that a thousand times - the syntax is wrong :).
You are using a combo of INSERT and UPDATE syntax there.
Try
INSERT INTO log (term, returns, time, date, ip) VALUES ('$search',
'$arrayword',CURTIME(), CURDATE(), '$ip');
Cheers,
Paul
-Original Message-
From: Axel IS Main [mailto:[EMAIL PROTECTED]
Sent: Thursday, February 26, 2004 7:06 PM
To: PHP-DB
Subject: [PHP-DB] What's wrong with this query?
I've just tried to do something I've done a thousand times. It does not
work. I've checked all of the syntax, made sure the field and variable
names are correct. No matter what I do it just doesn't work. The table
remains empty. Here's the query:
$logit = mysql_query(INSERT INTO log SET term='$search',
returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip');
Now that doesn't look too difficult does it? Well, apparently it's
impossible! I'm really hoping someone out there can see something that I
missed.
Nick
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Re: [PHP-DB] What's wrong with this query?
Try this:
$logit = mysql_query(INSERT INTO log (term,returns,time,date,ip) VALUES
('$search','$arrayword',CURTIME(), CURDATE(), '$ip'));
Regards,
Muhammed Mamedov
turkmenweb.com
- Original Message -
From: Axel IS Main [EMAIL PROTECTED]
To: PHP-DB [EMAIL PROTECTED]
Sent: Thursday, February 26, 2004 11:05 AM
Subject: [PHP-DB] What's wrong with this query?
I've just tried to do something I've done a thousand times. It does not
work. I've checked all of the syntax, made sure the field and variable
names are correct. No matter what I do it just doesn't work. The table
remains empty. Here's the query:
$logit = mysql_query(INSERT INTO log SET term='$search',
returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip');
Now that doesn't look too difficult does it? Well, apparently it's
impossible! I'm really hoping someone out there can see something that I
missed.
Nick
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To unsubscribe, visit: http://www.php.net/unsub.php
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Re: [PHP-DB] What's wrong with this query?
Ok guys, I found the problem. It's actually something I've run into before. If you take a look at the query you'll notice that one of the fields is named returns. When I created the test table with phpMyAdmin it created it and everything seemed fine. Then I decided to try something. I tweaked my install script to add creation of the new log table and ran it. It failed on that field. When I changed the name of the field it worked. I've seen this before when I tried to create a field for another database called group. Apparently these are MySQL reserved words and you can't use them as names for fields. Go figure. Anyway, that solves the problem. When I run it the data is put into the table, and the line where I echo the $logit var displays a 1. By the way, I changed the name of the returns field to found. Nick Micah Stevens wrote: Right.. a resource.. sorry. On Thursday 26 February 2004 12:55 pm, [EMAIL PROTECTED] wrote: An interesting thought. I tried this: echo Term: $search, Returns: $arrayword, UserIP: $ipbr; $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); echo Query Value: $logit; And got this on the page: Term: skater, Returns: 312, UserIP: 192.168.1.234 Query Value: - mysql_query returns a Resource, which is not a printable 'string', You could print_r($logit), or var_dump($logit) and you would most likely see Resouce ID #3 (or some other number). So even if you're query excecutes properly printing $logit will always show as you've written above. The same would hold true of an array, when just using print. the returned value preceeds the function call in the manual. from php.net/mysql_query resource mysql_query ( string query [, resource link_identifier]) hth jeff - Notice that the variables are set with appropriate values, but the $logit variable is blank. This, I think is the problem. The question is why would it do this and not return any type of error? By the way, I tried this using the other syntax people where suggesting and I got the same results. I gotta tell you, this one is really kicking my ass. It's the last piece of an update that I can't release until it's finished. Nick Hutchins, Richard wrote: Been kind of following this thread off and on... If the syntax is acceptable by MySQL, which it appears to be, is it possible that the variables you are using within the query string are not set to anything? Or is it possible that there is something broken immediately before the query string is fired? Most times, when I run into query problems, immediately before I send the query to the database, I'll echo the statement out to the browser so I can see the exact string that's being sent to the db. So can you do this: $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); And check out what gets spit out to the browser when $sql is echoed? Maybe that'll point out something that's going wrong. If nothing is apparent, post the results of echo $sql back to the list and maybe one of us will find something. HTH. Rich -Original Message- From: Axel IS Main [mailto:[EMAIL PROTECTED] Sent: Thursday, February 26, 2004 2:37 PM To: PHP DB Subject: Re: [PHP-DB] What's wrong with this query? Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] What's wrong with this query?
I agree this is a valid format. People should check the manual before making statements that are untrue to the list server. Axel did you get an error message or just no update? -Original Message- From: Nitin Mehta [mailto:[EMAIL PROTECTED] Sent: 26 February 2004 12:26 To: Erwin Kerk; [EMAIL PROTECTED]; PHP DB Subject: Re: [PHP-DB] What's wrong with this query? exactly, i'm using it for more than a year - Original Message - From: Erwin Kerk [EMAIL PROTECTED] To: [EMAIL PROTECTED]; PHP DB [EMAIL PROTECTED] Sent: Thursday, February 26, 2004 5:36 PM Subject: Re: [PHP-DB] What's wrong with this query? Viorel Dragomir wrote: I'm using MySQL for about 2 years and never heard about this kind of INSERT. Is not SQL compliant neither. YOU CAN NOT MAKE : INSERT INTO table SET var=1 [as I know] As a matter of fact it IS possible, according to the MySQL manual on http://www.mysql.com/doc/en/INSERT.html [snip] INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name [(col_name,...)] VALUES ((expression | DEFAULT),...),(...),... [ ON DUPLICATE KEY UPDATE col_name=expression, ... ] or INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name [(col_name,...)] SELECT ... HERE- or INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name SET col_name=(expression | DEFAULT), ... [ ON DUPLICATE KEY UPDATE col_name=expression, ... ] [/snip] I use this syntax all the time, and always without any trouble. @Axel: try this: $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip') or die(mysql_error()); to see what is going wrong... Erwin Kerk Web Developer -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
Actually, yes, a thousand times is an obvious exaggeration, but I have
done a whole lot of times, and the query syntax is the query syntax.
Different don't make it wrong. This is working in several other places
throughout this particular set of scripts.
Paul Fitz wrote:
You haven't done that a thousand times - the syntax is wrong :).
You are using a combo of INSERT and UPDATE syntax there.
Try
INSERT INTO log (term, returns, time, date, ip) VALUES ('$search',
'$arrayword',CURTIME(), CURDATE(), '$ip');
Cheers,
Paul
-Original Message-
From: Axel IS Main [mailto:[EMAIL PROTECTED]
Sent: Thursday, February 26, 2004 7:06 PM
To: PHP-DB
Subject: [PHP-DB] What's wrong with this query?
I've just tried to do something I've done a thousand times. It does not
work. I've checked all of the syntax, made sure the field and variable
names are correct. No matter what I do it just doesn't work. The table
remains empty. Here's the query:
$logit = mysql_query(INSERT INTO log SET term='$search',
returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip');
Now that doesn't look too difficult does it? Well, apparently it's
impossible! I'm really hoping someone out there can see something that I
missed.
Nick
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RE: [PHP-DB] What's wrong with this query?
Been kind of following this thread off and on... If the syntax is acceptable by MySQL, which it appears to be, is it possible that the variables you are using within the query string are not set to anything? Or is it possible that there is something broken immediately before the query string is fired? Most times, when I run into query problems, immediately before I send the query to the database, I'll echo the statement out to the browser so I can see the exact string that's being sent to the db. So can you do this: $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); And check out what gets spit out to the browser when $sql is echoed? Maybe that'll point out something that's going wrong. If nothing is apparent, post the results of echo $sql back to the list and maybe one of us will find something. HTH. Rich -Original Message- From: Axel IS Main [mailto:[EMAIL PROTECTED] Sent: Thursday, February 26, 2004 2:37 PM To: PHP DB Subject: Re: [PHP-DB] What's wrong with this query? Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
An interesting thought. I tried this: echo Term: $search, Returns: $arrayword, UserIP: $ipbr; $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); echo Query Value: $logit; And got this on the page: Term: skater, Returns: 312, UserIP: 192.168.1.234 Query Value: Notice that the variables are set with appropriate values, but the $logit variable is blank. This, I think is the problem. The question is why would it do this and not return any type of error? By the way, I tried this using the other syntax people where suggesting and I got the same results. I gotta tell you, this one is really kicking my ass. It's the last piece of an update that I can't release until it's finished. Nick Hutchins, Richard wrote: Been kind of following this thread off and on... If the syntax is acceptable by MySQL, which it appears to be, is it possible that the variables you are using within the query string are not set to anything? Or is it possible that there is something broken immediately before the query string is fired? Most times, when I run into query problems, immediately before I send the query to the database, I'll echo the statement out to the browser so I can see the exact string that's being sent to the db. So can you do this: $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); And check out what gets spit out to the browser when $sql is echoed? Maybe that'll point out something that's going wrong. If nothing is apparent, post the results of echo $sql back to the list and maybe one of us will find something. HTH. Rich -Original Message- From: Axel IS Main [mailto:[EMAIL PROTECTED] Sent: Thursday, February 26, 2004 2:37 PM To: PHP DB Subject: Re: [PHP-DB] What's wrong with this query? Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
mysql_query does not return a specific value, rather a pointer to a range of values (depending on what the query returns..) so what you're seeing is normal. I think depending on your error settings, PHP will actually return the value as 'POINTER' or something like that to let you know it's not a real variable.. The same thing happens if you try and echo an array.. -Micah On Thursday 26 February 2004 12:23 pm, Axel IS Main wrote: An interesting thought. I tried this: echo Term: $search, Returns: $arrayword, UserIP: $ipbr; $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); echo Query Value: $logit; And got this on the page: Term: skater, Returns: 312, UserIP: 192.168.1.234 Query Value: Notice that the variables are set with appropriate values, but the $logit variable is blank. This, I think is the problem. The question is why would it do this and not return any type of error? By the way, I tried this using the other syntax people where suggesting and I got the same results. I gotta tell you, this one is really kicking my ass. It's the last piece of an update that I can't release until it's finished. Nick Hutchins, Richard wrote: Been kind of following this thread off and on... If the syntax is acceptable by MySQL, which it appears to be, is it possible that the variables you are using within the query string are not set to anything? Or is it possible that there is something broken immediately before the query string is fired? Most times, when I run into query problems, immediately before I send the query to the database, I'll echo the statement out to the browser so I can see the exact string that's being sent to the db. So can you do this: $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); And check out what gets spit out to the browser when $sql is echoed? Maybe that'll point out something that's going wrong. If nothing is apparent, post the results of echo $sql back to the list and maybe one of us will find something. HTH. Rich -Original Message- From: Axel IS Main [mailto:[EMAIL PROTECTED] Sent: Thursday, February 26, 2004 2:37 PM To: PHP DB Subject: Re: [PHP-DB] What's wrong with this query? Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
An interesting thought. I tried this: echo Term: $search, Returns: $arrayword, UserIP: $ipbr; $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); echo Query Value: $logit; And got this on the page: Term: skater, Returns: 312, UserIP: 192.168.1.234 Query Value: - mysql_query returns a Resource, which is not a printable 'string', You could print_r($logit), or var_dump($logit) and you would most likely see Resouce ID #3 (or some other number). So even if you're query excecutes properly printing $logit will always show as you've written above. The same would hold true of an array, when just using print. the returned value preceeds the function call in the manual. from php.net/mysql_query resource mysql_query ( string query [, resource link_identifier]) hth jeff - Notice that the variables are set with appropriate values, but the $logit variable is blank. This, I think is the problem. The question is why would it do this and not return any type of error? By the way, I tried this using the other syntax people where suggesting and I got the same results. I gotta tell you, this one is really kicking my ass. It's the last piece of an update that I can't release until it's finished. Nick Hutchins, Richard wrote: Been kind of following this thread off and on... If the syntax is acceptable by MySQL, which it appears to be, is it possible that the variables you are using within the query string are not set to anything? Or is it possible that there is something broken immediately before the query string is fired? Most times, when I run into query problems, immediately before I send the query to the database, I'll echo the statement out to the browser so I can see the exact string that's being sent to the db. So can you do this: $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); And check out what gets spit out to the browser when $sql is echoed? Maybe that'll point out something that's going wrong. If nothing is apparent, post the results of echo $sql back to the list and maybe one of us will find something. HTH. Rich -Original Message- From: Axel IS Main [mailto:[EMAIL PROTECTED] Sent: Thursday, February 26, 2004 2:37 PM To: PHP DB Subject: Re: [PHP-DB] What's wrong with this query? Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
Right.. a resource.. sorry. On Thursday 26 February 2004 12:55 pm, [EMAIL PROTECTED] wrote: An interesting thought. I tried this: echo Term: $search, Returns: $arrayword, UserIP: $ipbr; $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); echo Query Value: $logit; And got this on the page: Term: skater, Returns: 312, UserIP: 192.168.1.234 Query Value: - mysql_query returns a Resource, which is not a printable 'string', You could print_r($logit), or var_dump($logit) and you would most likely see Resouce ID #3 (or some other number). So even if you're query excecutes properly printing $logit will always show as you've written above. The same would hold true of an array, when just using print. the returned value preceeds the function call in the manual. from php.net/mysql_query resource mysql_query ( string query [, resource link_identifier]) hth jeff - Notice that the variables are set with appropriate values, but the $logit variable is blank. This, I think is the problem. The question is why would it do this and not return any type of error? By the way, I tried this using the other syntax people where suggesting and I got the same results. I gotta tell you, this one is really kicking my ass. It's the last piece of an update that I can't release until it's finished. Nick Hutchins, Richard wrote: Been kind of following this thread off and on... If the syntax is acceptable by MySQL, which it appears to be, is it possible that the variables you are using within the query string are not set to anything? Or is it possible that there is something broken immediately before the query string is fired? Most times, when I run into query problems, immediately before I send the query to the database, I'll echo the statement out to the browser so I can see the exact string that's being sent to the db. So can you do this: $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); And check out what gets spit out to the browser when $sql is echoed? Maybe that'll point out something that's going wrong. If nothing is apparent, post the results of echo $sql back to the list and maybe one of us will find something. HTH. Rich -Original Message- From: Axel IS Main [mailto:[EMAIL PROTECTED] Sent: Thursday, February 26, 2004 2:37 PM To: PHP DB Subject: Re: [PHP-DB] What's wrong with this query? Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
Good point, but all you needed to do is surround the field name with back quotes.. i.e.: $logit = mysql_query(INSERT INTO log SET `term`='$search',`returns`='$arrayword', `time`=CURTIME(), `date`=CURDATE(), ip='$ip'); I think phpmyadmin does this automatically, which is why that worked. -Micah On Thursday 26 February 2004 01:12 pm, Axel IS Main wrote: Ok guys, I found the problem. It's actually something I've run into before. If you take a look at the query you'll notice that one of the fields is named returns. When I created the test table with phpMyAdmin it created it and everything seemed fine. Then I decided to try something. I tweaked my install script to add creation of the new log table and ran it. It failed on that field. When I changed the name of the field it worked. I've seen this before when I tried to create a field for another database called group. Apparently these are MySQL reserved words and you can't use them as names for fields. Go figure. Anyway, that solves the problem. When I run it the data is put into the table, and the line where I echo the $logit var displays a 1. By the way, I changed the name of the returns field to found. Nick Micah Stevens wrote: Right.. a resource.. sorry. On Thursday 26 February 2004 12:55 pm, [EMAIL PROTECTED] wrote: An interesting thought. I tried this: echo Term: $search, Returns: $arrayword, UserIP: $ipbr; $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); echo Query Value: $logit; And got this on the page: Term: skater, Returns: 312, UserIP: 192.168.1.234 Query Value: - mysql_query returns a Resource, which is not a printable 'string', You could print_r($logit), or var_dump($logit) and you would most likely see Resouce ID #3 (or some other number). So even if you're query excecutes properly printing $logit will always show as you've written above. The same would hold true of an array, when just using print. the returned value preceeds the function call in the manual. from php.net/mysql_query resource mysql_query ( string query [, resource link_identifier]) hth jeff - Notice that the variables are set with appropriate values, but the $logit variable is blank. This, I think is the problem. The question is why would it do this and not return any type of error? By the way, I tried this using the other syntax people where suggesting and I got the same results. I gotta tell you, this one is really kicking my ass. It's the last piece of an update that I can't release until it's finished. Nick Hutchins, Richard wrote: Been kind of following this thread off and on... If the syntax is acceptable by MySQL, which it appears to be, is it possible that the variables you are using within the query string are not set to anything? Or is it possible that there is something broken immediately before the query string is fired? Most times, when I run into query problems, immediately before I send the query to the database, I'll echo the statement out to the browser so I can see the exact string that's being sent to the db. So can you do this: $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); And check out what gets spit out to the browser when $sql is echoed? Maybe that'll point out something that's going wrong. If nothing is apparent, post the results of echo $sql back to the list and maybe one of us will find something. HTH. Rich -Original Message- From: Axel IS Main [mailto:[EMAIL PROTECTED] Sent: Thursday, February 26, 2004 2:37 PM To: PHP DB Subject: Re: [PHP-DB] What's wrong with this query? Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http
Re: [PHP-DB] What's wrong with this query?
Ok guys, I found the problem. It's actually something I've run into before. If you take a look at the query you'll notice that one of the fields is named returns. When I created the test table with phpMyAdmin it created it and everything seemed fine. Then I decided to try something. I tweaked my install script to add creation of the new log table and ran it. It failed on that field. When I changed the name of the field it worked. I've seen this before when I tried to create a field for another database called group. Apparently these are MySQL reserved words and you can't use them as names for fields. Go figure. Anyway, that solves the problem. When I run it the data is put into the table, and the line where I echo the $logit var displays a 1. By the way, I changed the name of the returns field to found. just as an FYI, although i would have changed the name as well, if you're using, or think you are using, a reserved word, you can enclose it in `backticks` and mysql will treat it as a regular word, which is how PHPMyAdmin creates and uses all fields. That being said, your solution of changing the field is better. Jeff - Nick Micah Stevens wrote: Right.. a resource.. sorry. On Thursday 26 February 2004 12:55 pm, [EMAIL PROTECTED] wrote: An interesting thought. I tried this: echo Term: $search, Returns: $arrayword, UserIP: $ipbr; $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'); echo Query Value: $logit; And got this on the page: Term: skater, Returns: 312, UserIP: 192.168.1.234 Query Value: - mysql_query returns a Resource, which is not a printable 'string', You could print_r($logit), or var_dump($logit) and you would most likely see Resouce ID #3 (or some other number). So even if you're query excecutes properly printing $logit will always show as you've written above. The same would hold true of an array, when just using print. the returned value preceeds the function call in the manual. from php.net/mysql_query resource mysql_query ( string query [, resource link_identifier]) hth jeff - Notice that the variables are set with appropriate values, but the $logit variable is blank. This, I think is the problem. The question is why would it do this and not return any type of error? By the way, I tried this using the other syntax people where suggesting and I got the same results. I gotta tell you, this one is really kicking my ass. It's the last piece of an update that I can't release until it's finished. Nick Hutchins, Richard wrote: Been kind of following this thread off and on... If the syntax is acceptable by MySQL, which it appears to be, is it possible that the variables you are using within the query string are not set to anything? Or is it possible that there is something broken immediately before the query string is fired? Most times, when I run into query problems, immediately before I send the query to the database, I'll echo the statement out to the browser so I can see the exact string that's being sent to the db. So can you do this: $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); And check out what gets spit out to the browser when $sql is echoed? Maybe that'll point out something that's going wrong. If nothing is apparent, post the results of echo $sql back to the list and maybe one of us will find something. HTH. Rich -Original Message- From: Axel IS Main [mailto:[EMAIL PROTECTED] Sent: Thursday, February 26, 2004 2:37 PM To: PHP DB Subject: Re: [PHP-DB] What's wrong with this query? Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] What's wrong with this query?
What about the single quotes? Might try this. $sql = INSERT INTO log SET term=\'$search\', returns=\'$arrayword\', time=CURTIME(), date=CURDATE(), ip=\'$ip\'; $sql = INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'; echo $sql; $logit = mysql_query($sql) or die(mysql_error()); -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
Ok, ok. I get the message about the syntax. Since I've used this syntax for a long time and so far there hasn't been a problem I'll assume that's not the problem. I will, however, review this and probably make some changes for the sake of compliance if nothing else. In any event, the syntax is NOT why it is failing, smart ass comments by people who think two years is a long time not withstanding. As to the useful questions that where asked. There is no error reported. Error reporting is set to E_ALL ~E_NOTICE. I removed the notice part so I would get everything and still nothing showed up. I'm also logging errors and nothing is showing up in the log either. Not all PHP/MySQL errors are reported. Sometimes what happens is not considered an error, even though it does not do what you would expect it to do. If the query syntax was wrong, I would get a syntax error. There is no error, it just doesn't write to the table. I can go into phpMyAdmin and with the same syntax insert into the table all day long. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
exactly, i'm using it for more than a year - Original Message - From: Erwin Kerk [EMAIL PROTECTED] To: [EMAIL PROTECTED]; PHP DB [EMAIL PROTECTED] Sent: Thursday, February 26, 2004 5:36 PM Subject: Re: [PHP-DB] What's wrong with this query? Viorel Dragomir wrote: I'm using MySQL for about 2 years and never heard about this kind of INSERT. Is not SQL compliant neither. YOU CAN NOT MAKE : INSERT INTO table SET var=1 [as I know] As a matter of fact it IS possible, according to the MySQL manual on http://www.mysql.com/doc/en/INSERT.html [snip] INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name [(col_name,...)] VALUES ((expression | DEFAULT),...),(...),... [ ON DUPLICATE KEY UPDATE col_name=expression, ... ] or INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name [(col_name,...)] SELECT ... HERE- or INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name SET col_name=(expression | DEFAULT), ... [ ON DUPLICATE KEY UPDATE col_name=expression, ... ] [/snip] I use this syntax all the time, and always without any trouble. @Axel: try this: $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip') or die(mysql_error()); to see what is going wrong... Erwin Kerk Web Developer -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with this query?
Viorel Dragomir wrote: I'm using MySQL for about 2 years and never heard about this kind of INSERT. Is not SQL compliant neither. YOU CAN NOT MAKE : INSERT INTO table SET var=1 [as I know] As a matter of fact it IS possible, according to the MySQL manual on http://www.mysql.com/doc/en/INSERT.html [snip] INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name [(col_name,...)] VALUES ((expression | DEFAULT),...),(...),... [ ON DUPLICATE KEY UPDATE col_name=expression, ... ] or INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name [(col_name,...)] SELECT ... HERE- or INSERT [LOW_PRIORITY | DELAYED] [IGNORE] [INTO] tbl_name SET col_name=(expression | DEFAULT), ... [ ON DUPLICATE KEY UPDATE col_name=expression, ... ] [/snip] I use this syntax all the time, and always without any trouble. @Axel: try this: $logit = mysql_query(INSERT INTO log SET term='$search', returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip') or die(mysql_error()); to see what is going wrong... Erwin Kerk Web Developer -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] What's wrong with my update query select works, but updatedoesn't?
Here's the code: with some extraneous html removed to make it easier to
read...
? require('connect.php') ?
?
/* check for a request to display a new fg number and if so make sure the
data is good
if the fg number is good it is used for all other data queries */
$fgNumber=;
if ($switchfg !==){
$switchfg = htmlentities($switchfg , ENT_QUOTES);
if (strlen($switchfg) 7) {
echo bad fg number;
}
else {
$fgNumber =$switchfg ;
echo $fgNumber;
}}
?
This works... I added the echo statement in the last line for debugging
purposes, the page does indeed display the fgNumber, and uses the variable
to perform other queries, which also work... until I try to update the
database
?
if ($tableid==products) {
echo updating products;
if ($productName != and $productDescription !=) {
$products_query= UPDATE products SET productName='$productName',
productDescription='$productDescription' where fgNumber='$fgNumber' limit
1;
$productsResult = mysql_query($products_query);
echo $products_query;
}
}
?
Again, that last line is a debugging entry, and it echoes back the query
I'm expecting, except that the variable $fgNumber looses it's value
somewhere and the query looks like this:
UPDATE products SET productName='ZR-4630 MultiZone Receiver',
productDescription='4-Source 6-Zone Receiver with AM/FM Tuner' where
fgNumber='' limit 1
I expect it to say where fgNumber='FG00813
Here's the form that triggers the update
!-- __ PRODUCTS TABLE
__ --
?
$productsQuery =SELECT id, fgNumber, productName, productDescription FROM
products where fgNumber='$fgNumber' ;
$productsRecordset = mysql_query($productsQuery) or die(mysql_error());
$productsRow=mysql_fetch_array($productsRecordset);
//$fgNumber=$productsRow['fgNumber']
?
form name=products method=post action=? $_SERVER['php_self']
?input name=tableid type=hidden value=products
table width=100% border=0 cellpadding=10 cellspacing=0 bgcolor=
#CC
tr
td colspan=4h2Products Table/h2
hr
/td
/tr
tr
tdID:
input name=productId type=text id=productId
value=? echo $productsRow['id'] ? size=5/td
tdFG#:
input name=fgNumber type=text id
=fgNumber value=? echo $productsRow['fgNumber'] ? size=10/td
tdName:
input name=productName type=text
id=productName value=? echo $productsRow['productName'] ? size
=36/td
tdDescription
input name=productDescription type
=text id=productDescription value=? echo $productsRow
['productDescription'] ? size=48/td
/tr
tr
td colspan=4Update Product Information
input type=submit name=Submit value
=Submit/td
/tr
/table
/form
I keep looking for an error and not finding one, am I missing something
obvious?
Michael
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RE: [PHP-DB] What's wrong with my update query select works, but update doesn't?
Well, it seems to me that if these two happen within the same scope level (same
function, same class) which I cannot verify based on what you gave us, the $fgNumber
should not be empty. Therefore I'd bet there's some code in between that reinitializes
$fgNumber or the update is in a function that does not have access to the $fgNumber.
You can give a function access to that variable by declaring it global inside of the
function, or passing it as a variable.
Ryan
-Original Message-
From: Michael Knauf/Niles [mailto:[EMAIL PROTECTED]]
Sent: Thursday, December 26, 2002 1:41 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] What's wrong with my update query select works,
but update doesn't?
Here's the code: with some extraneous html removed to make it easier to
read...
? require('connect.php') ?
?
/* check for a request to display a new fg number and if so make sure the
data is good
if the fg number is good it is used for all other data queries */
$fgNumber=;
if ($switchfg !==){
$switchfg = htmlentities($switchfg , ENT_QUOTES);
if (strlen($switchfg) 7) {
echo bad fg number;
}
else {
$fgNumber =$switchfg ;
echo $fgNumber;
}}
?
This works... I added the echo statement in the last line for debugging
purposes, the page does indeed display the fgNumber, and uses the variable
to perform other queries, which also work... until I try to update the
database
?
if ($tableid==products) {
echo updating products;
if ($productName != and $productDescription !=) {
$products_query= UPDATE products SET productName='$productName',
productDescription='$productDescription' where fgNumber='$fgNumber' limit
1;
$productsResult = mysql_query($products_query);
echo $products_query;
}
}
?
Again, that last line is a debugging entry, and it echoes back the query
I'm expecting, except that the variable $fgNumber looses it's value
somewhere and the query looks like this:
UPDATE products SET productName='ZR-4630 MultiZone Receiver',
productDescription='4-Source 6-Zone Receiver with AM/FM Tuner' where
fgNumber='' limit 1
I expect it to say where fgNumber='FG00813
Here's the form that triggers the update
!-- __ PRODUCTS TABLE
__ --
?
$productsQuery =SELECT id, fgNumber, productName, productDescription FROM
products where fgNumber='$fgNumber' ;
$productsRecordset = mysql_query($productsQuery) or die(mysql_error());
$productsRow=mysql_fetch_array($productsRecordset);
//$fgNumber=$productsRow['fgNumber']
?
form name=products method=post action=? $_SERVER['php_self']
?input name=tableid type=hidden value=products
table width=100% border=0 cellpadding=10 cellspacing=0 bgcolor=
#CC
tr
td colspan=4h2Products Table/h2
hr
/td
/tr
tr
tdID:
input name=productId type=text id=productId
value=? echo $productsRow['id'] ? size=5/td
tdFG#:
input name=fgNumber type=text id
=fgNumber value=? echo $productsRow['fgNumber'] ? size=10/td
tdName:
input name=productName type=text
id=productName value=? echo $productsRow['productName'] ? size
=36/td
tdDescription
input name=productDescription type
=text id=productDescription value=? echo $productsRow
['productDescription'] ? size=48/td
/tr
tr
td colspan=4Update Product Information
input type=submit name=Submit value
=Submit/td
/tr
/table
/form
I keep looking for an error and not finding one, am I missing something
obvious?
Michael
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[PHP-DB] What's wrong with this code?
Hi all, I'm running PHP4. What's wrong with this code:
?
$db = mysql_connect(localhost, Taj, wyethia);
mysql_select_db(s2s,$db);
mysql_query(INSERT INTO prod VALUES ( 'Name', 'ShortDesc', 'LongDesc',
'PriceOZ', 'PriceLB', 'URLOZ', 'URLLB', 'IMG') VALUES ('$_POST[Name]',
'$_POST[ShortDesc]', '$_POST[LongDesc], '$POST[PriceOZ',
'$_POST[PriceLB]', '$_POST[URLOZ]', '$_POST[URLLB], '$_POST[IMG]');)
?
This will wrap, but, it should work.
TIA, Taj
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[PHP-DB] What's wrong with this code?
Hi all, I'm running PHP4. What's wrong with this code:
?
$db = mysql_connect(localhost, Taj, passwordhere);
mysql_select_db(s2s,$db);
mysql_query(INSERT INTO prod VALUES ( 'Name', 'ShortDesc', 'LongDesc',
'PriceOZ', 'PriceLB', 'URLOZ', 'URLLB', 'IMG') VALUES ('$_POST[Name]',
'$_POST[ShortDesc]', '$_POST[LongDesc], '$POST[PriceOZ',
'$_POST[PriceLB]', '$_POST[URLOZ]', '$_POST[URLLB], '$_POST[IMG]');)
?
This will wrap, but, it should work.
TIA, Taj
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RE: [PHP-DB] What's wrong with this code?
I'd use var inclusions like this;
VALUES (' . $_POST['Name'] . ',
that might help you
// -Original Message-
// From: Shoulder to Shoulder Farm [mailto:[EMAIL PROTECTED]]
// Sent: Monday, 2 September 2002 11:42 AM
// To: PHP Database List
// Subject: [PHP-DB] What's wrong with this code?
//
//
// Hi all, I'm running PHP4. What's wrong with this code:
//
// ?
//
// $db = mysql_connect(localhost, Taj, passwordhere);
//
// mysql_select_db(s2s,$db);
//
// mysql_query(INSERT INTO prod VALUES ( 'Name', 'ShortDesc',
// 'LongDesc',
// 'PriceOZ', 'PriceLB', 'URLOZ', 'URLLB', 'IMG') VALUES
// ('$_POST[Name]',
// '$_POST[ShortDesc]', '$_POST[LongDesc], '$POST[PriceOZ',
// '$_POST[PriceLB]', '$_POST[URLOZ]', '$_POST[URLLB], '$_POST[IMG]');)
//
// ?
//
// This will wrap, but, it should work.
//
// TIA, Taj
//
//
// --
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//
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[PHP-DB] what's wrong with this ereg?
I am trying an email verification function, like this:
if (empty($useremail)) || !eregi(^[A-Za-z0-9\_-]+@[A-Za-z0-9\_-]
+.[A-Za-z0-9\_-]+.*, $email))
{
$errmsg .= The email address appears to be invalid\n;
}
But it will not work, on one server I get this error:
Parse error: parse error in
/home/virtual/site109/fst/var/www/html/auth_dealers/user_input2.php on line
70
and on another server I get this error:
Parse error: parse error, unexpected T_BOOLEAN_OR in
/usr/local/apache/htdocs/auth_dealers/user_input2.php on line 70
What do I need to do to fix this?
--
Chip Wiegand
Computer Services
Simrad, Inc
www.simradusa.com
[EMAIL PROTECTED]
There is no reason anyone would want a computer in their home.
--Ken Olson, president, chairman and founder of Digital Equipment
Corporation, 1977
(They why do I have 9? Somebody help me!)
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Re: [PHP-DB] what's wrong with this ereg?
Well, one thing is you've got mismatched parentheses. You need another
another opening paren right after the if.
Also, don't you need to escape the last hyphen in your character sets?
As well as the . before the third character set?
-Steve
On Tuesday, August 20, 2002, at 11:11 AM, [EMAIL PROTECTED] wrote:
I am trying an email verification function, like this:
if (empty($useremail)) || !eregi(^[A-Za-z0-9\_-]+@[A-Za-z0-9\_-]
+.[A-Za-z0-9\_-]+.*, $email))
{
$errmsg .= The email address appears to be invalid\n;
}
But it will not work, on one server I get this error:
Parse error: parse error in
/home/virtual/site109/fst/var/www/html/auth_dealers/user_input2.php on
line
70
and on another server I get this error:
Parse error: parse error, unexpected T_BOOLEAN_OR in
/usr/local/apache/htdocs/auth_dealers/user_input2.php on line 70
What do I need to do to fix this?
--
Chip Wiegand
Computer Services
Simrad, Inc
www.simradusa.com
[EMAIL PROTECTED]
There is no reason anyone would want a computer in their home.
--Ken Olson, president, chairman and founder of Digital Equipment
Corporation, 1977
(They why do I have 9? Somebody help me!)
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Re: [PHP-DB] what's wrong with this ereg?
Steve Cayford [EMAIL PROTECTED] wrote on 08/20/2002 10:28:46 AM:
Well, one thing is you've got mismatched parentheses. You need another
another opening paren right after the if.
Also, don't you need to escape the last hyphen in your character sets?
As well as the . before the third character set?
-Steve
Got it fixed like this:
if (empty($useremail) || !eregi(^[A-Za-z0-9\.\_-]+@[A-Za-z0-9\_-]
+\.[A-Za-z0-9\_-]+$, $useremail))
--
Chip
On Tuesday, August 20, 2002, at 11:11 AM, [EMAIL PROTECTED] wrote:
I am trying an email verification function, like this:
if (empty($useremail)) || !eregi(^[A-Za-z0-9\_-]+@[A-Za-z0-9\_-]
+.[A-Za-z0-9\_-]+.*, $email))
{
$errmsg .= The email address appears to be invalid\n;
}
But it will not work, on one server I get this error:
Parse error: parse error in
/home/virtual/site109/fst/var/www/html/auth_dealers/user_input2.php on
line
70
and on another server I get this error:
Parse error: parse error, unexpected T_BOOLEAN_OR in
/usr/local/apache/htdocs/auth_dealers/user_input2.php on line 70
What do I need to do to fix this?
--
Chip Wiegand
Computer Services
Simrad, Inc
www.simradusa.com
[EMAIL PROTECTED]
There is no reason anyone would want a computer in their home.
--Ken Olson, president, chairman and founder of Digital Equipment
Corporation, 1977
(They why do I have 9? Somebody help me!)
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[PHP-DB] what's wrong with this?
hi all i've been trying this script for a day and i just can't figure out why it doesn't work. could someone check and see if there is something i did wrong? the error is unknown function include_menu() which actually exist in the menu.inc file. this is the structure: home.php includes (folder) layout.inc menu.inc thanks in advance Ali -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP-DB] what's wrong with this?
i'm not sure why the files didn't come through. i'll try again. -Original Message- From: Ali Nayeri [mailto:[EMAIL PROTECTED]] Sent: January 27, 2002 8:18 PM To: PHP Database Mailing List Subject: [PHP-DB] what's wrong with this? hi all i've been trying this script for a day and i just can't figure out why it doesn't work. could someone check and see if there is something i did wrong? the error is unknown function include_menu() which actually exist in the menu.inc file. this is the structure: home.php includes (folder) layout.inc menu.inc thanks in advance Ali -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
RE: [PHP-DB] what's wrong with this?
can't you attach files in this mailing list? is there a special way? could someone tell me. Thanks -Original Message- From: Ali Nayeri [mailto:[EMAIL PROTECTED]] Sent: January 27, 2002 8:27 PM To: PHP Database Mailing List Subject: RE: [PHP-DB] what's wrong with this? i'm not sure why the files didn't come through. i'll try again. -Original Message- From: Ali Nayeri [mailto:[EMAIL PROTECTED]] Sent: January 27, 2002 8:18 PM To: PHP Database Mailing List Subject: [PHP-DB] what's wrong with this? hi all i've been trying this script for a day and i just can't figure out why it doesn't work. could someone check and see if there is something i did wrong? the error is unknown function include_menu() which actually exist in the menu.inc file. this is the structure: home.php includes (folder) layout.inc menu.inc thanks in advance Ali _ Do You Yahoo!? Get your free @yahoo.com address at http://mail.yahoo.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP-DB] What's wrong?
Ho there...I really wonder what's wrong with this script. The error is in
this line below:
if((count($info) != 1) ($folder == $info[2])) echo tabletrtda
href= . $info[1] . . $info[0] . /abr/td/tr/table;
The condition ($folder == $info[2]) is not working!
I hope you can help me!
Here's the code:
?php
$link_name = Tudo sobre automação;
$link_address = http://www.automacao.eng.br;;
$link_folder = faculdade;
$file = teste.txt;
function write($file,$link_name,$link_address,$link_folder) {
$file=fopen($file,w);
fwrite($file,$link_name|$link_address|$link_folder\n);
fclose($file);
}
function read($file,$folder) {
$file=fopen($file,r);
while (!feof ($file)) {
$buffer = fgets($file,1024);
$info = explode(|,$buffer);
if((count($info) != 1) ($folder == $info[2])) echo tabletrtda
href= . $info[1] . . $info[0] . /abr/td/tr/table;
}
fclose($file);
}
write($file,$link_name,$link_address,$link_folder);
read($file,faculdade);
?
Thanks!
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Re: [PHP-DB] What's wrong?
Hi,
the most probable reason is that the file you're reading from was saved in a
different filesystem and the $info[2] has some newline characters at the
end.
You can use the trim() function to remove it. Than your expression will look
something like this
if(count($info) != 1 $folder == trim($info[2]))
HTH
Dobromir Velev
-Original Message-
From: Sergio Augusto Bitencourt Petrovcic [EMAIL PROTECTED]
To: [EMAIL PROTECTED] [EMAIL PROTECTED]
Date: Tuesday, November 20, 2001 13:58
Subject: [PHP-DB] What's wrong?
Ho there...I really wonder what's wrong with this script. The error is in
this line below:
if((count($info) != 1) ($folder == $info[2])) echo tabletrtda
href= . $info[1] . . $info[0] . /abr/td/tr/table;
The condition ($folder == $info[2]) is not working!
I hope you can help me!
Here's the code:
?php
$link_name = Tudo sobre automação;
$link_address = http://www.automacao.eng.br;;
$link_folder = faculdade;
$file = teste.txt;
function write($file,$link_name,$link_address,$link_folder) {
$file=fopen($file,w);
fwrite($file,$link_name|$link_address|$link_folder\n);
fclose($file);
}
function read($file,$folder) {
$file=fopen($file,r);
while (!feof ($file)) {
$buffer = fgets($file,1024);
$info = explode(|,$buffer);
if((count($info) != 1) ($folder == $info[2])) echo tabletrtda
href= . $info[1] . . $info[0] . /abr/td/tr/table;
}
fclose($file);
}
write($file,$link_name,$link_address,$link_folder);
read($file,faculdade);
?
Thanks!
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Re: [PHP-DB] What's wrong with my function? :(
Tx.
Yep I have read it now and understood it better than the first time I read
this part of the manual (it's amazing how things make more sense when you
can apply them to what you are doing).
Jesse Goerz [EMAIL PROTECTED] wrote in message
0110301727.19453@reign">news:0110301727.19453@reign...
On Tuesday 30 October 2001 15:49, TorrentUK wrote:
Please could some take a look at this code and tell me why
when I take my IF statements out of the function and put in
them in the same place where I call the function from they
work, but as soon as I replace them with the function name
they don't?
Appreciate any help.
torrent
Here's the code...
Your variable is not in scope. Either pass your variable as a
reference in the function definition:
function RatingFilter ($sql) {
...
}
or use the global keyword to bring your variable into scope:
function RatingFilter () {
global $sql;
if ($br) {$sql.= and beg_rate = '2';}
...
}
And follow the advice of Charles and read up on it so you know
how they are different.
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[PHP-DB] What's wrong with my function? :(
Please could some take a look at this code and tell me why when I take my IF
statements out of the function and put in them in the same place where I
call the function from they work, but as soon as I replace them with the
function name they don't?
Appreciate any help.
torrent
Here's the code...
// Define the rating's filter
?php
function RatingFilter () {
if ($br) {$sql.= and beg_rate = '2';}
if ($ir) {$sql.= and int_rate = '2';}
if ($ar) {$sql.= and adv_rate = '2';}
if ($sr) {$sql.= and sbd_rate = '2';}
}
?
if ($search) {
include ('logon-inc.php');
$sql = SELECT rsrt_name, ctry_name FROM resort_tbl WHERE
ctry_name='$country[0]';
RatingFilter(); --- If I put 'if' statement here instead it works
for ($n=1; count($country) $n; $n++){
$sql.= or ctry_name='$country[$n]';
RatingFilter(); -- Or here
}
.
.
.
.
}
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Re: [PHP-DB] What's wrong with my function? :(
On Tue, 30 Oct 2001, TorrentUK wrote:
SNIP
you either need to pass the variables to the function or use global
variables in the function see
http://www.php.net/manual/en/language.variables.scope.php
Here's the code...
// Define the rating's filter
?php
function RatingFilter () {
if ($br) {$sql.= and beg_rate = '2';}
if ($ir) {$sql.= and int_rate = '2';}
if ($ar) {$sql.= and adv_rate = '2';}
if ($sr) {$sql.= and sbd_rate = '2';}
}
?
if ($search) {
include ('logon-inc.php');
$sql = SELECT rsrt_name, ctry_name FROM resort_tbl WHERE
ctry_name='$country[0]';
RatingFilter(); --- If I put 'if' statement here instead it works
for ($n=1; count($country) $n; $n++){
$sql.= or ctry_name='$country[$n]';
RatingFilter(); -- Or here
}
.
.
.
.
}
--
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[EMAIL PROTECTED] ICQ: 2794793 | certainty is absurd.
[EMAIL PROTECTED] PGP: 0x20A5BCE5 | - Voltaire
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RE: [PHP-DB] What's wrong with my function? :(
I'm new to PHP but one thing I think might be happening is that maybe the
changes aren't being made to a global (I'm a Java programmer) $sql so they
aren't being kept. Does it actually break or is it not appending the
additional string? I'd try printing out the $sql and see what you're
getting - possibly at different stages of the program - like before and
after you call your function.
Good luck!
-Natalie
-Original Message-
From: TorrentUK [SMTP:[EMAIL PROTECTED]]
Sent: Tuesday, October 30, 2001 3:50 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] What's wrong with my function? :(
Please could some take a look at this code and tell me why when I take my
IF
statements out of the function and put in them in the same place where I
call the function from they work, but as soon as I replace them with the
function name they don't?
Appreciate any help.
torrent
Here's the code...
// Define the rating's filter
?php
function RatingFilter () {
if ($br) {$sql.= and beg_rate = '2';}
if ($ir) {$sql.= and int_rate = '2';}
if ($ar) {$sql.= and adv_rate = '2';}
if ($sr) {$sql.= and sbd_rate = '2';}
}
?
if ($search) {
include ('logon-inc.php');
$sql = SELECT rsrt_name, ctry_name FROM resort_tbl WHERE
ctry_name='$country[0]';
RatingFilter(); --- If I put 'if' statement here instead it works
for ($n=1; count($country) $n; $n++){
$sql.= or ctry_name='$country[$n]';
RatingFilter(); -- Or here
}
.
.
.
.
}
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Re: [PHP-DB] What's wrong with my function? :(
Yep, that'll be it.
Thanks for the help. :)
torrent
Charles F. McKnight [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
On Tue, 30 Oct 2001, TorrentUK wrote:
SNIP
you either need to pass the variables to the function or use global
variables in the function see
http://www.php.net/manual/en/language.variables.scope.php
Here's the code...
// Define the rating's filter
?php
function RatingFilter () {
if ($br) {$sql.= and beg_rate = '2';}
if ($ir) {$sql.= and int_rate = '2';}
if ($ar) {$sql.= and adv_rate = '2';}
if ($sr) {$sql.= and sbd_rate = '2';}
}
?
if ($search) {
include ('logon-inc.php');
$sql = SELECT rsrt_name, ctry_name FROM resort_tbl WHERE
ctry_name='$country[0]';
RatingFilter(); --- If I put 'if' statement here instead it works
for ($n=1; count($country) $n; $n++){
$sql.= or ctry_name='$country[$n]';
RatingFilter(); -- Or here
}
.
.
.
.
}
--
Charles F. McKnight IRC: sokudo | Doubt is not a pleasant
condition, but
[EMAIL PROTECTED] ICQ: 2794793 | certainty is absurd.
[EMAIL PROTECTED] PGP: 0x20A5BCE5 | -
Voltaire
[
http://chucksays.mywebsitesucks.com ]-
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[PHP-DB] What's wrong with this code?
Hi,
I really need help, I wrote a function so that I can
call for db user/password in an include file. It looks
like this:
// Connect to the database
function db_connect(){
global $MYSQL_USERNAME, $MYSQL_PASSWORD, $DB,
$HOST;
$db =
mysql_connect("$HOST","$MYSQL_USERNAME","$MYSQL_PASSWORD");
mysql_select_db("$DB",$db);
}
I have user/password/host variables inside a config
file but for some reason when I include this into a
php page when I test it, I get:
Fatal error: Cannot redeclare db_connect() in
/www/affiliate/include/functions.inc on line 7.
Am I missing something because everything looks good
to me.
Emir.
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RE: [PHP-DB] What's wrong with this code?
Hello...
Try mysql_pconnect instead
Dan
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From: Emir Musabasic
Sent: Monday, March 26, 2001 9:34 AM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] What's wrong with this code?
Hi,
I really need help, I wrote a function so that I can
call for db user/password in an include file. It looks
like this:
// Connect to the database
function db_connect(){
global $MYSQL_USERNAME, $MYSQL_PASSWORD, $DB,
$HOST;
$db =
mysql_connect("$HOST","$MYSQL_USERNAME","$MYSQL_PASSWORD");
mysql_select_db("$DB",$db);
}
I have user/password/host variables inside a config
file but for some reason when I include this into a
php page when I test it, I get:
Fatal error: Cannot redeclare db_connect() in
/www/affiliate/include/functions.inc on line 7.
Am I missing something because everything looks good
to me.
Emir.
__
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Get email at your own domain with Yahoo! Mail.
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Re: [PHP-DB] What's wrong with this code?
In article [EMAIL PROTECTED], [EMAIL PROTECTED] (Emir Musabasic) wrote: I have user/password/host variables inside a config file but for some reason when I include this into a php page when I test it, I get: Fatal error: Cannot redeclare db_connect() in /www/affiliate/include/functions.inc on line 7. Am I missing something because everything looks good to me. Try using include_once() instead of include(). You're probably inadvertantly re-including the file. In general, except where you're deliberately making multiple includes of the same file, it's a good idea to get in the habit of using include_once() or require_once() to save yourself from surprises like this. -- CC -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
