Whats wrong with this code?
$img1 = "episodeID_a.jpg";
$img2 = "episodeID_b.jpg";
$img3 = "episodeID_c.jpg";
$img$x="blank.jpg";
That doesn't what you expect. I think the syntax is the same as Perl:
$var = "$img$x"; # $var hold the _name_ of the variable
Why isn't this working?
?php
$img[] = "$episodeID_a.jpg";
$img[] = "$episodeID_b.jpg";
$img[] = "$episodeID_c.jpg";
for ($x=0; $xcount($img); $x++) {
if(!file_exists($img[$x])) {
print("td align=centerimg src=\"blank.gif\" width=160 height=120
border=\"1\"/td");
} else {
