RE: [PHP-DB] Direct Access to an Array Item?

2006-09-03 Thread Naintara
Perhaps you could elaborate on the exact motive
Say, why would you be checking against the 4th element of an array.

I could understand why you would want to check every element of an array
against a particular value, but why just the 4th element, just for interest.

In response to your question, there wasn't a way to access the index of an
array using the square bracket, but you could explore the various array
functions available in php. If you have a dynamic variable/counter, you
could instead use each() or next()

For instance, 
You can get this to work
$str = "123#456#789";
"123" == current(explode('#', $str)) 

The result will be true.

Not sure if this helps you, but worth a shot.

-Original Message-
From: J R [mailto:[EMAIL PROTECTED] 
Sent: 10 August 2006 4:54 AM
To: php-db@lists.php.net
Subject: [PHP-DB] Direct Access to an Array Item?

On 8/9/06, Peter Beckman <[EMAIL PROTECTED]> wrote:
>
> I want to access a variable within a function-returned array without 
> setting the array to a variable first.  Example -- test for equal to 
> string 'foo' on the 4th element of a returned fetch row:
>
>  if (($row = mysql_fetch_row($result))[3] == 'foo') {
>  $user = $row;
>  }
>
> or
>
>  $bar = explode('#', $str)[2];


i don't think it is possible to do such syntax. nor theres a work around on
to make it way you want it. (i'm not an expert. just IMHO)

I know I can do this in perl, but can it be done in PHP?  Obviously this is
> pseudo code, it doesn't actually work, but I wonder if there is a way 
> that escapes me currently?
>
> I know I can assign the result to a variable and then test the 
> element; I am addicted to trying to cut down the amount and complexity 
> of code.  Even
>
> if you disagree with my goal as good computing practices,


i agree, its not a good programming practice and its makes your code less
readable. :)

I simply want to
> know if what I ask is possible, and if so, how. :-)
>
> Beckman
>
>
---
> Peter Beckman  Internet
> Guy
> [EMAIL PROTECTED]
> http://www.purplecow.com/
> --
> -
>
>
> --
> PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: 
> http://www.php.net/unsub.php
>
>


--
GMail Rocks!!!


-- 
GMail Rocks!!!

-- 
No virus found in this incoming message.
Checked by AVG Free Edition.
Version: 7.1.405 / Virus Database: 268.10.8/413 - Release Date: 08/08/2006
 

-- 
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



Re: [PHP-DB] Direct Access to an Array Item?

2006-08-09 Thread Bastien Koert

Closest you might get is
if ( mysql_result($result,0,3 ) == 'foo') {
   $user = $mysql_fetch_row($result);

 }

bastien


From: Stut <[EMAIL PROTECTED]>
To: Peter Beckman <[EMAIL PROTECTED]>
CC: PHP-DB Mailing List 
Subject: Re: [PHP-DB] Direct Access to an Array Item?
Date: Thu, 10 Aug 2006 00:33:15 +0100

Peter Beckman wrote:
> if (($row = mysql_fetch_row($result))[3] == 'foo') {
> $user = $row;
> }
>
> or
>
> $bar = explode('#', $str)[2];

PHP does not currently support this type of syntax in any form. You must
assign the return value of a function to a variable if you want to
access it as an array.

-Stut

--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



Re: [PHP-DB] Direct Access to an Array Item?

2006-08-09 Thread Stut
Peter Beckman wrote:
> if (($row = mysql_fetch_row($result))[3] == 'foo') {
> $user = $row;
> }
> 
> or
> 
> $bar = explode('#', $str)[2];

PHP does not currently support this type of syntax in any form. You must
assign the return value of a function to a variable if you want to
access it as an array.

-Stut

-- 
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



Re: [PHP-DB] Direct Access to an Array Item?

2006-08-09 Thread J R

On 8/9/06, Peter Beckman <[EMAIL PROTECTED]> wrote:


I want to access a variable within a function-returned array without
setting the array to a variable first.  Example -- test for equal to
string
'foo' on the 4th element of a returned fetch row:

 if (($row = mysql_fetch_row($result))[3] == 'foo') {
 $user = $row;
 }

or

 $bar = explode('#', $str)[2];



i don't think it is possible to do such syntax. nor theres a work around on
to make it way you want it. (i'm not an expert. just IMHO)

I know I can do this in perl, but can it be done in PHP?  Obviously this is

pseudo code, it doesn't actually work, but I wonder if there is a way that
escapes me currently?

I know I can assign the result to a variable and then test the element; I
am addicted to trying to cut down the amount and complexity of code.  Even
if you disagree with my goal as good computing practices,



i agree, its not a good programming practice and its makes your code less
readable. :)

I simply want to

know if what I ask is possible, and if so, how. :-)

Beckman

---
Peter Beckman  Internet
Guy
[EMAIL PROTECTED]
http://www.purplecow.com/

---

--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php





--
GMail Rocks!!!


RE: [PHP-DB] Direct Access to an Array Item?

2006-08-09 Thread Peter Beckman

On Wed, 9 Aug 2006, Bastien Koert wrote:


use mysql_result

mysql_result ( $result, 0,  2 )

where 2 is the offset of the fields in the row


 In one line of code, I want to fetch the row into a variable, and test a
 variable within that row.

 I want to know how to do this both within a DB query and outside of.

 Your solution is valid, but not what I'm looking for.

---
Peter Beckman  Internet Guy
[EMAIL PROTECTED] http://www.purplecow.com/
---

--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



RE: [PHP-DB] Direct Access to an Array Item?

2006-08-09 Thread Bastien Koert

use mysql_result

mysql_result ( $result, 0,  2 )

where 2 is the offset of the fields in the row

Bastien



From: Peter Beckman <[EMAIL PROTECTED]>
To: PHP-DB Mailing List 
Subject: [PHP-DB] Direct Access to an Array Item?
Date: Tue, 8 Aug 2006 22:34:55 -0400 (EDT)

I want to access a variable within a function-returned array without
setting the array to a variable first.  Example -- test for equal to string
'foo' on the 4th element of a returned fetch row:

if (($row = mysql_fetch_row($result))[3] == 'foo') {
$user = $row;
}

or

$bar = explode('#', $str)[2];

I know I can do this in perl, but can it be done in PHP?  Obviously this is
pseudo code, it doesn't actually work, but I wonder if there is a way that
escapes me currently?

I know I can assign the result to a variable and then test the element; I
am addicted to trying to cut down the amount and complexity of code.  Even
if you disagree with my goal as good computing practices, I simply want to
know if what I ask is possible, and if so, how. :-)

Beckman
---
Peter Beckman  Internet Guy
[EMAIL PROTECTED] http://www.purplecow.com/
---

--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php



--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php