Re: [PHP-DB] MySQL: Alphabetizing title results in library format

2001-11-01 Thread Ian Evans

Petr Tuma wrote:

 What error message it produce?

Ok, table titles is composed of:

+--+-++
| titlesid | releaseyear | title  |
+--+-++

mysql select *,(case when title like 'The %' then substring (title, 5, 255) when 
title like 'A %' then substring (title, 3, 255) when title like 'An %' then substring 
(title, 4, 255) else title end) as sort_col from titles order by sort_col;
ERROR 1064: You have an error in your SQL syntax near 'when title like 'The %' then 
substring (title, 5, 255) when title like 'A %' the' at line 1


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Ian Evans
Digital Hit Entertainment - News and Information
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RE: [PHP-DB] MySQL: Alphabetizing title results in library format

2001-11-01 Thread Cami

Hi Ian,
Try this:
mysql select *,(case when title like '%The%' then substring (title, 5, 255)
when title like '%A%' then substring (title, 3, 255) when title like '%An%'
then substring (title, 4, 255) else title end) as sort_col from titles order
by sort_col;
Hope it helps,
Cami

-Original Message-
From: Ian Evans [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 01, 2001 9:20 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL: Alphabetizing title results in library
format


Petr Tuma wrote:

 What error message it produce?

Ok, table titles is composed of:

+--+-++
| titlesid | releaseyear | title  |
+--+-++

mysql select *,(case when title like 'The %' then substring (title, 5, 255)
when title like 'A %' then substring (title, 3, 255) when title like 'An %'
then substring (title, 4, 255) else title end) as sort_col from titles order
by sort_col;
ERROR 1064: You have an error in your SQL syntax near 'when title like 'The
%' then substring (title, 5, 255) when title like 'A %' the' at line 1


--
Ian Evans
Digital Hit Entertainment - News and Information
http://www.digitalhit.com


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Re: [PHP-DB] MySQL: Alphabetizing title results in library format

2001-11-01 Thread Ian Evans

Cami wrote:

 Try this:
 mysql select *,(case when title like '%The%' then substring (title, 5, 255)
 when title like '%A%' then substring (title, 3, 255) when title like '%An%'
 then substring (title, 4, 255) else title end) as sort_col from titles order
 by sort_col;

Argh, that still produces the same syntax error. Our hosting company is 
using MySQL 3.22.32 if that's any help.

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Ian Evans
Digital Hit Entertainment - News and Information
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RE: [PHP-DB] MySQL: Alphabetizing title results in library format

2001-11-01 Thread Cami

Have you tried it like this:
mysql select case when title like '%The %' then substring (title, 5, 255)
when title like '%A %' then substring (title, 3, 255) when title like '%An
%' then substring (title, 4, 255) else title end as sort_col from titles
order by sort_col;
I can't tested, but that's what the manual say.
Cami

-Original Message-
From: Ian Evans [mailto:[EMAIL PROTECTED]]
Sent: Thursday, November 01, 2001 9:20 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] MySQL: Alphabetizing title results in library
format


Petr Tuma wrote:

 What error message it produce?

Ok, table titles is composed of:

+--+-++
| titlesid | releaseyear | title  |
+--+-++

mysql select *,(case when title like 'The %' then substring (title, 5, 255)
when title like 'A %' then substring (title, 3, 255) when title like 'An %'
then substring (title, 4, 255) else title end) as sort_col from titles order
by sort_col;
ERROR 1064: You have an error in your SQL syntax near 'when title like 'The
%' then substring (title, 5, 255) when title like 'A %' the' at line 1


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Ian Evans
Digital Hit Entertainment - News and Information
http://www.digitalhit.com


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Re: [PHP-DB] MySQL: Alphabetizing title results in library format

2001-11-01 Thread Petr Tuma

Hi,

seems a bit strange.
Try this select (use mysql client)
mysql select title,if(title like 'The %','yes','no') from titles;
if it works try substring functions and if that works try 'order by' clause.
It's at least working on server v. 3.23, so in case it will not work find out 
in the 'list of changes' (for version 3.23) if this feature is not new. In 
such case tell whoever to upgrade. :(
I can't find any error in your query (and at least at 3.23 it's working!)

Regards

On Thursday 01 November 2001 10:19, you wrote:
 Petr Tuma wrote:
  What error message it produce?

 Ok, table titles is composed of:

 +--+-++

 | titlesid | releaseyear | title  |

 +--+-++

 mysql select *,(case when title like 'The %' then substring (title, 5,
 255) when title like 'A %' then substring (title, 3, 255) when title like
 'An %' then substring (title, 4, 255) else title end) as sort_col from
 titles order by sort_col; ERROR 1064: You have an error in your SQL syntax
 near 'when title like 'The %' then substring (title, 5, 255) when title
 like 'A %' the' at line 1

-- 
Petr Tuma
IT Manager, M.Ward Manufacturing

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Re: [PHP-DB] MySQL: Alphabetizing title results in library format

2001-10-31 Thread Ian Evans

Petr Tuma wrote:

 select *,(case when Title like 'The %' then substring (Title, 5, 255)

  ETC.

Alas, MySQL doesn't like that syntax either. :(



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Ian Evans
Digital Hit Entertainment - News and Information
http://www.digitalhit.com


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