I read a bit of it, but it's still giving me trouble. I have the following
short, test, PHP script:
?
Header(Cache-control: private, no-cache);
Header(Expires: Mon, 26 Jul 1997 05:00:00 GMT); # Past date
Header(Pragma: no-cache);
$link = mysql_connect(localhost,root,password);
$R = mysql_db_query(database,SELECT uid FROM users LIMIT 200);
$N = mysql_num_rows($R);
?
FORM ACTION='?=$PHP_SELF;?' METHOD='POST'
Number of Users: ? print $N . - $Step; ?
INPUT TYPE='Hidden' NAME='Step' VALUE='? print $Step+1; ?'
INPUT TYPE='Submit'
/FORM
Now, I load that script up, which displays Number of Users: and a submit
button. I click on the submit button, and then again on the next page and I
basically see: Number of Users: 200 - 3 and a submit button.
Now, keeping the browser window open in the background, I go and edit the
script, changing LIMIT 200 to LIMIT 100 so that it will return just 100
users. I save and then go back to my browser and click the Back button, but
now I get an IE message saying that it cannot automatically resubmit the
posted information. What I want is to have it re-query the database with
this new LIMIT 100 query and return Number of Users: 100 - 2
So at this point I have either the option of forcing the user to see the IE
page and have them reload it, which works, or by allowing caching to go on.
Any more thoughts?
- Jonathan
Chris Boget [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
How can I ensure that a specific page is never cached and ALWAYS gets
processed every time it is viewed? Sometimes a viewer can hit his/her
browser's Back button (such a hateful button), and get a cached version
of
a dynamic page. I want this page's PHP code to be executed even if the
visitor uses their Back button to get to the page. Any thoughts on how
to
do this?
Check out the discussion on the following page:
http://www.web-caching.com/forums/Forum1/HTML/000133.html
Chris
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