Re: [PHP-DB] Re: PHP and MySQL queries...

2001-10-23 Thread Jason

Ok I made the changes and now I am getting these 2 errors...
Warning: 0 is not a MySQL result index in search01.php on line 141
  and this one...
Warning: 0 is not a MySQL result index in search01.php on line 143
No rows found
On line 141 - $count = mysql_num_rows($results);
On line 143 - if (mysql_num_rows($results) )
I am not sure what this error message means, does that mean that there were
no results to display? Oh by the way I sincerely want to thank you for
helping me out with this, I have been working on it for a few days and just
today decided I should get help with it.  Thanks again.
Jason

"Rick Emery" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> OK.  Ya followed me just a little too literally.  We needed you to
> restructure.  So you're part way there.
> i've made some changes below.
>
> I don't have access to PHP here at work, otherwise I'd test the changes I
> made below.  So you'll have to test them.
>
> You'll note that I placed the while(){} loop where it should be.
> I also split the Name line into two different array elements.  The array
> element names refer directly to the variables after SELECT in your SELECT
> query.
> I did the same in the Phone line.
>
> -Original Message-
> From: Jason Gerfen [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, October 23, 2001 2:23 PM
> To: [EMAIL PROTECTED]
> Subject: RE: [PHP-DB] Re: PHP and MySQL queries...
>
>
> Ok here is what I have done after your suggestions...
> if ($date == "")
> {$date = '%';}
>
> $result = mysql_query ("SELECT
>
fname,lname,address,city,state,zip,phonea,phone,email,crty,crnum,crmo,cryr,w
> eeks,ogden,rock,logan,ipaddress,ad,total,num,date,time
> FROM ads WHERE date LIKE
> '%$date%' LIMIT 0, 30 ");
> $count = mysql_num_rows($results);
>
> if (mysql_num_rows($results) )
> {
> while( $row = mysql_fetch_array($result) )
> {
>
>print "Name: ".$row['fname'].", ".$row[' lname']."\n";
>print "Address: ".$row['address']."\n";
>print "City: ".$row['city']."\n";
>print "State: ".$row['state']."\n";
>print "Zip: ".$row['zip']."\n";
>print "Phone: ".$row['phonea'].", ".$row[' phone']."\n";
>print "Email: ".$row['email']."\n";
>print "Credit Type: ".$row['crty']."\n";
>print "Credit Number: ".$row['crnum']."\n";
>print "Credit Date: ".$row['crmo']."\n";
>print "Weeks: ".$row['weeks']."\n";
>print "Ogden: ".$row['ogden']."\n";
>print "Logan: ".$row['logan']."\n";
>    print "IP Address: ".$row['ipaddress']."\n";
>print "Ad: ".$row['ad']."\n";
>print "Total: ".$row['total']."\n";
>print "Ad Number: ".$row['num']."\n";
>print "Date: ".$row['date']."\n";
>print "Time: ".$row['time']."\n";
> }
> }
> else {
> print "No rows found";
> }
> ?>
> After I have uploaded it to the webserver I now get a parse error on line
> 201 and that is the end of the php file, so there isn't anything to
change.
>
> I am still fairly new to this so any help you can provide would be great.
> Thanks again.
> Jason
>
>
> >From: Rick Emery <[EMAIL PROTECTED]>
> >To: 'Jason' <[EMAIL PROTECTED]>, [EMAIL PROTECTED]
> >Subject: RE: [PHP-DB] Re: PHP and MySQL queries...
> >Date: Tue, 23 Oct 2001 13:13:21 -0500
> >
> >First o all, GET RID of the 19 constructs using mysql_result().  You've
> >already captured the row with the $row=mysql_fetch_array().
> >mysql_result() cannot be mixed with mysql_fetch_arry().
> >
> >So instead of:
> >echo "Address: ";
> >printf(mysql_result($result,$count,"address"));
> >echo "\n";
> >
> >use:
> >print "Address: ".$row['address']."\n";
> >
> >Next, dates are stored in MySQL as -MM-DD.  Use that format in your
> >input.
> >
> >Next, don't combine that "if(mysql_fetch_array())" with the "do while()"
> >Instead, use:
> >
> >if (mysql_num_rows($results) )
> >

Re: [PHP-DB] Re: PHP and MySQL queries...

2001-10-23 Thread Jason Wood

Let me guess, the parse error is on the last line of the file?

I get that all the time, its usually caused by a loop thats still open...
and, in your case, your "do" and "if" statements arent closed

try this.



mysql_connect ("db_hostname", "db_username", "db_password");

mysql_select_db ("db_name");

if ($date == "")
{$date = '%';}

$result = mysql_query ("SELECT
fname,lname,address,city,state,zip,phonea,phone,email,crty,crnum,crmo,cryr,w
eeks,ogden,rock,logan,ipaddress,ad,total,num,date,time
  FROM ads WHERE date LIKE '%$date%' LIMIT 0, 30 ");
$count = -1;
if ($row = mysql_fetch_array($result))
 {
  $count ++;
  do
  {
   print "Name: ".$row['fname, lname']."\n";

   if (mysql_num_rows($results) )
   {
 while( $row = mysql_fetch_array($result) )
{
}
   }
   else
   {
print "No rows found";
   }
  }
 }

Let me know if it works!!


--
Jason Wood
Chief Technology Officer
Expressive Tek, Inc.
407 Kehrs Mill Road
Ballwin, MO 63011
Phone 636.256.1362
www.expressivetek.com

"Jason" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Ok here is the script after changes...
> 
> mysql_connect ("db_hostname", "db_username", "db_password");
>
> mysql_select_db ("db_name");
>
> if ($date == "")
> {$date = '%';}
>
> $result = mysql_query ("SELECT
>
fname,lname,address,city,state,zip,phonea,phone,email,crty,crnum,crmo,cryr,w
> eeks,ogden,rock,logan,ipaddress,ad,total,num,date,time
>   FROM ads WHERE date LIKE '%$date%' LIMIT 0, 30 ");
> $count = -1;
> if ($row = mysql_fetch_array($result)) {
> $count ++;
> do {
> print "Name: ".$row['fname, lname']."\n";
>
> if (mysql_num_rows($results) )
> {
>  while( $row = mysql_fetch_array($result) )
> {
> }
> }
> else {
> print "No rows found";
> }
> ?>
> And now I get a parse error on line 201 which is below the html and php
> code, so there isn't anything to change.  Please help?
>
> "Rick Emery" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > First o all, GET RID of the 19 constructs using mysql_result().  You've
> > already captured the row with the $row=mysql_fetch_array().
> > mysql_result() cannot be mixed with mysql_fetch_arry().
> >
> > So instead of:
> > echo "Address: ";
> > printf(mysql_result($result,$count,"address"));
> > echo "\n";
> >
> > use:
> > print "Address: ".$row['address']."\n";
> >
> > Next, dates are stored in MySQL as -MM-DD.  Use that format in your
> > input.
> >
> > Next, don't combine that "if(mysql_fetch_array())" with the "do while()"
> > Instead, use:
> >
> > if (mysql_num_rows($results) )
> > {
> > while( $row = mysql_fetch_array($result) )
> > {
> > }
> > }
> > else {
> > print "No rows found";
> > }
> >
> > Do the above.  Re-submit.  Tell me the results.  W'ell go from there...
> >
> > rick
> >
> > -Original Message-
> > From: Jason [mailto:[EMAIL PROTECTED]]
> > Sent: Tuesday, October 23, 2001 12:37 PM
> > To: [EMAIL PROTECTED]
> > Subject: [PHP-DB] Re: PHP and MySQL queries...
> >
> >
> > As of yet I have tried all sorts for date formating for the search field
> to
> > work.  I.E. 2001-10-23, 10/23/2001, 10/%/2001, 10%, %10%, etc.  The date
> > field in the database is stored as 10/23/2001 and yet when a user enters
> the
> > date and clicks the search button it does not display the results.  I am
> > almost certain that as the user clicks the submit button the php script
is
> > parsing the search string (i.e. 10/23/2001) incorrectly.  I believe it
is
> > parsing the sting as 10&nsb;23&nsb;2001 or something to that effect.  If
> > anyone has some more information on this please let me know.  I am
pretty
> > sure I have exhausted my resources.
> >
> > "Jason" <[EMAIL PROTECTED]> wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > I am having a hard time setting up a form for users to enter a date in
> the
> > > format of 00/00/ (of course they would use an actual date).  My
form
> > is
> > > as follows...
> > > 
> > >   *I.E. - Format is 04/01/2001*
> > >   Search for Ads by date:
> > > 
> > >   
> > >   
> > >  > > value="Submit">
> > >  > value="Reset">
> > >   
> > > 
> > > 
> > > On my search.php page I have the following MySQL connection and search
> > > parameters...
> > >  > >
> > > mysql_connect ("db_hostname", "db_username", "db_password");
> > >
> > > mysql_select_db ("db_name");
> > >
> > > if ($date == "")
> > > {$date = '%';}
> > >
> > > $result = mysql_query ("SELECT
> > >
> >
>
fname,lname,address,city,state,zip,phonea,phone,email,crty,crnum,crmo,cryr,w
> > > eeks,ogden,rock,logan,ipaddress,ad,total,num,date,time
> > >   FROM ads WHERE date LIKE '%$date%' LIMIT 0, 30 ");
> > > $count = -1;
> > > if ($row = mysql_fet

RE: [PHP-DB] Re: PHP and MySQL queries...

2001-10-23 Thread Rick Emery

OK.  Ya followed me just a little too literally.  We needed you to
restructure.  So you're part way there.
i've made some changes below.

I don't have access to PHP here at work, otherwise I'd test the changes I
made below.  So you'll have to test them.

You'll note that I placed the while(){} loop where it should be.
I also split the Name line into two different array elements.  The array
element names refer directly to the variables after SELECT in your SELECT
query.
I did the same in the Phone line.

-Original Message-
From: Jason Gerfen [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, October 23, 2001 2:23 PM
To: [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Re: PHP and MySQL queries...


Ok here is what I have done after your suggestions...
if ($date == "")
{$date = '%';}

$result = mysql_query ("SELECT 
fname,lname,address,city,state,zip,phonea,phone,email,crty,crnum,crmo,cryr,w
eeks,ogden,rock,logan,ipaddress,ad,total,num,date,time
FROM ads WHERE date LIKE
'%$date%' LIMIT 0, 30 ");
$count = mysql_num_rows($results);

if (mysql_num_rows($results) )
{
while( $row = mysql_fetch_array($result) )
{

   print "Name: ".$row['fname'].", ".$row[' lname']."\n";
   print "Address: ".$row['address']."\n";
   print "City: ".$row['city']."\n";
   print "State: ".$row['state']."\n";
   print "Zip: ".$row['zip']."\n";
   print "Phone: ".$row['phonea'].", ".$row[' phone']."\n";
   print "Email: ".$row['email']."\n";
   print "Credit Type: ".$row['crty']."\n";
   print "Credit Number: ".$row['crnum']."\n";
   print "Credit Date: ".$row['crmo']."\n";
   print "Weeks: ".$row['weeks']."\n";
   print "Ogden: ".$row['ogden']."\n";
   print "Logan: ".$row['logan']."\n";
   print "IP Address: ".$row['ipaddress']."\n";
   print "Ad: ".$row['ad']."\n";
   print "Total: ".$row['total']."\n";
   print "Ad Number: ".$row['num']."\n";
   print "Date: ".$row['date']."\n";
   print "Time: ".$row['time']."\n";
}
}
else {
print "No rows found";
}
?>
After I have uploaded it to the webserver I now get a parse error on line 
201 and that is the end of the php file, so there isn't anything to change.

I am still fairly new to this so any help you can provide would be great.  
Thanks again.
Jason


>From: Rick Emery <[EMAIL PROTECTED]>
>To: 'Jason' <[EMAIL PROTECTED]>, [EMAIL PROTECTED]
>Subject: RE: [PHP-DB] Re: PHP and MySQL queries...
>Date: Tue, 23 Oct 2001 13:13:21 -0500
>
>First o all, GET RID of the 19 constructs using mysql_result().  You've
>already captured the row with the $row=mysql_fetch_array().
>mysql_result() cannot be mixed with mysql_fetch_arry().
>
>So instead of:
>echo "Address: ";
>printf(mysql_result($result,$count,"address"));
>echo "\n";
>
>use:
>print "Address: ".$row['address']."\n";
>
>Next, dates are stored in MySQL as -MM-DD.  Use that format in your
>input.
>
>Next, don't combine that "if(mysql_fetch_array())" with the "do while()"
>Instead, use:
>
>if (mysql_num_rows($results) )
>{
>   while( $row = mysql_fetch_array($result) )
>   {
>   }
>}
>else {
>print "No rows found";
>}
>
>Do the above.  Re-submit.  Tell me the results.  W'ell go from there...
>
>rick
>
>-Original Message-
>From: Jason [mailto:[EMAIL PROTECTED]]
>Sent: Tuesday, October 23, 2001 12:37 PM
>To: [EMAIL PROTECTED]
>Subject: [PHP-DB] Re: PHP and MySQL queries...
>
>
>As of yet I have tried all sorts for date formating for the search field to
>work.  I.E. 2001-10-23, 10/23/2001, 10/%/2001, 10%, %10%, etc.  The date
>field in the database is stored as 10/23/2001 and yet when a user enters 
>the
>date and clicks the search button it does not display the results.  I am
>almost certain that as the user clicks the submit button the php script is
>parsing the search string (i.e. 10/23/2001) incorrectly.  I believe it is
>parsing the sting as 10&nsb;23&nsb;2001 or something to that effect.  If
>anyone has some more information on this please let me know.  I am pretty
>sure I have exhausted my resources.

Re: [PHP-DB] Re: PHP and MySQL queries...

2001-10-23 Thread Jason

Ok here is the script after changes...
Name: ".$row['fname, lname']."\n";

if (mysql_num_rows($results) )
{
 while( $row = mysql_fetch_array($result) )
{
}
}
else {
print "No rows found";
}
?>
And now I get a parse error on line 201 which is below the html and php
code, so there isn't anything to change.  Please help?

"Rick Emery" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> First o all, GET RID of the 19 constructs using mysql_result().  You've
> already captured the row with the $row=mysql_fetch_array().
> mysql_result() cannot be mixed with mysql_fetch_arry().
>
> So instead of:
> echo "Address: ";
> printf(mysql_result($result,$count,"address"));
> echo "\n";
>
> use:
> print "Address: ".$row['address']."\n";
>
> Next, dates are stored in MySQL as -MM-DD.  Use that format in your
> input.
>
> Next, don't combine that "if(mysql_fetch_array())" with the "do while()"
> Instead, use:
>
> if (mysql_num_rows($results) )
> {
> while( $row = mysql_fetch_array($result) )
> {
> }
> }
> else {
> print "No rows found";
> }
>
> Do the above.  Re-submit.  Tell me the results.  W'ell go from there...
>
> rick
>
> -Original Message-
> From: Jason [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, October 23, 2001 12:37 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] Re: PHP and MySQL queries...
>
>
> As of yet I have tried all sorts for date formating for the search field
to
> work.  I.E. 2001-10-23, 10/23/2001, 10/%/2001, 10%, %10%, etc.  The date
> field in the database is stored as 10/23/2001 and yet when a user enters
the
> date and clicks the search button it does not display the results.  I am
> almost certain that as the user clicks the submit button the php script is
> parsing the search string (i.e. 10/23/2001) incorrectly.  I believe it is
> parsing the sting as 10&nsb;23&nsb;2001 or something to that effect.  If
> anyone has some more information on this please let me know.  I am pretty
> sure I have exhausted my resources.
>
> "Jason" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > I am having a hard time setting up a form for users to enter a date in
the
> > format of 00/00/ (of course they would use an actual date).  My form
> is
> > as follows...
> > 
> >   *I.E. - Format is 04/01/2001*
> >   Search for Ads by date:
> > 
> >   
> >   
> >  > value="Submit">
> >  value="Reset">
> >   
> > 
> > 
> > On my search.php page I have the following MySQL connection and search
> > parameters...
> >  >
> > mysql_connect ("db_hostname", "db_username", "db_password");
> >
> > mysql_select_db ("db_name");
> >
> > if ($date == "")
> > {$date = '%';}
> >
> > $result = mysql_query ("SELECT
> >
>
fname,lname,address,city,state,zip,phonea,phone,email,crty,crnum,crmo,cryr,w
> > eeks,ogden,rock,logan,ipaddress,ad,total,num,date,time
> >   FROM ads WHERE date LIKE '%$date%' LIMIT 0, 30 ");
> > $count = -1;
> > if ($row = mysql_fetch_array($result)) {
> > $count ++;
> > do {
> > echo "Name: ";
> > printf(mysql_result($result,$count,"fname"));
> > echo " ";
> > printf(mysql_result($result,$count,"lname"));
> > echo "\n";
> >
> > echo "Address: ";
> > printf(mysql_result($result,$count,"address"));
> > echo "\n";
> >
> > echo "City: ";
> > printf(mysql_result($result,$count,"city"));
> > echo "\n";
> >
> > echo "State: ";
> > printf(mysql_result($result,$count,"state"));
> > echo "\n";
> >
> > echo "Zip: ";
> > printf(mysql_result($result,$count,"zip"));
> > echo "\n";
> >
> > echo "Phone: (";
> > printf(mysql_result($result,$count,"phonea"));
> > echo ") ";
> > printf(mysql_result($result,$count,"phone"));
> > echo "\n";
> >
> > echo "Email: ";
> > printf(mysql_result($result,$count,"email"));
> > echo "\n";
> >
> > echo "Credit Type: ";
> > printf(mysql_result($result,$count,"crty"));
> > echo "\n";
> >
> > echo "Credit Number: ";
> > printf(mysql_result($result,$count,"crnum"));
> > echo "\n";
> >
> > echo "Credit Card Date: ";
> > printf(mysql_result($result,$count,"crmo"));
> > echo " ";
> > printf(mysql_result($result,$count,"cryr"));
> > echo "\n";
> >
> > echo "Weeks: ";
> > printf(mysql_result($result,$count,"weeks"));
> > echo "\n";
> >
> > echo "town1: ";
> > printf(mysql_result($result,$count,"town1"));
> > echo "\n";
> >
> > echo "town2: ";
> > printf(mysql_result($result,$count,"town2"));
> > echo "\n";
> >
> > echo "town3: ";
> > printf(mysql_result($result,$count,"town3"));
> > echo "\n";
> >
> > echo "IP Address: ";
> > printf(mysql_result($result,$count,"ipaddress"));
> > echo "\n";
> >
> > echo "Ad: ";
> >
> > $ad[$count] = (mysql_result($result,$count,"ad"));
> >
> > $ad[$count] = ereg_replace ("&a&", "'", $ad[$count]);
> > $ad[$count] = ereg_rep

RE: [PHP-DB] Re: PHP and MySQL queries...

2001-10-23 Thread Rick Emery

First o all, GET RID of the 19 constructs using mysql_result().  You've
already captured the row with the $row=mysql_fetch_array().
mysql_result() cannot be mixed with mysql_fetch_arry().

So instead of:
echo "Address: ";
printf(mysql_result($result,$count,"address"));
echo "\n";

use:
print "Address: ".$row['address']."\n";

Next, dates are stored in MySQL as -MM-DD.  Use that format in your
input.

Next, don't combine that "if(mysql_fetch_array())" with the "do while()"
Instead, use:

if (mysql_num_rows($results) )
{
while( $row = mysql_fetch_array($result) )
{
}
}
else {
print "No rows found";
}

Do the above.  Re-submit.  Tell me the results.  W'ell go from there...

rick

-Original Message-
From: Jason [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, October 23, 2001 12:37 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Re: PHP and MySQL queries...


As of yet I have tried all sorts for date formating for the search field to
work.  I.E. 2001-10-23, 10/23/2001, 10/%/2001, 10%, %10%, etc.  The date
field in the database is stored as 10/23/2001 and yet when a user enters the
date and clicks the search button it does not display the results.  I am
almost certain that as the user clicks the submit button the php script is
parsing the search string (i.e. 10/23/2001) incorrectly.  I believe it is
parsing the sting as 10&nsb;23&nsb;2001 or something to that effect.  If
anyone has some more information on this please let me know.  I am pretty
sure I have exhausted my resources.

"Jason" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I am having a hard time setting up a form for users to enter a date in the
> format of 00/00/ (of course they would use an actual date).  My form
is
> as follows...
> 
>   *I.E. - Format is 04/01/2001*
>   Search for Ads by date:
> 
>   
>   
>  value="Submit">
> 
>   
> 
> 
> On my search.php page I have the following MySQL connection and search
> parameters...
> 
> mysql_connect ("db_hostname", "db_username", "db_password");
>
> mysql_select_db ("db_name");
>
> if ($date == "")
> {$date = '%';}
>
> $result = mysql_query ("SELECT
>
fname,lname,address,city,state,zip,phonea,phone,email,crty,crnum,crmo,cryr,w
> eeks,ogden,rock,logan,ipaddress,ad,total,num,date,time
>   FROM ads WHERE date LIKE '%$date%' LIMIT 0, 30 ");
> $count = -1;
> if ($row = mysql_fetch_array($result)) {
> $count ++;
> do {
> echo "Name: ";
> printf(mysql_result($result,$count,"fname"));
> echo " ";
> printf(mysql_result($result,$count,"lname"));
> echo "\n";
>
> echo "Address: ";
> printf(mysql_result($result,$count,"address"));
> echo "\n";
>
> echo "City: ";
> printf(mysql_result($result,$count,"city"));
> echo "\n";
>
> echo "State: ";
> printf(mysql_result($result,$count,"state"));
> echo "\n";
>
> echo "Zip: ";
> printf(mysql_result($result,$count,"zip"));
> echo "\n";
>
> echo "Phone: (";
> printf(mysql_result($result,$count,"phonea"));
> echo ") ";
> printf(mysql_result($result,$count,"phone"));
> echo "\n";
>
> echo "Email: ";
> printf(mysql_result($result,$count,"email"));
> echo "\n";
>
> echo "Credit Type: ";
> printf(mysql_result($result,$count,"crty"));
> echo "\n";
>
> echo "Credit Number: ";
> printf(mysql_result($result,$count,"crnum"));
> echo "\n";
>
> echo "Credit Card Date: ";
> printf(mysql_result($result,$count,"crmo"));
> echo " ";
> printf(mysql_result($result,$count,"cryr"));
> echo "\n";
>
> echo "Weeks: ";
> printf(mysql_result($result,$count,"weeks"));
> echo "\n";
>
> echo "town1: ";
> printf(mysql_result($result,$count,"town1"));
> echo "\n";
>
> echo "town2: ";
> printf(mysql_result($result,$count,"town2"));
> echo "\n";
>
> echo "town3: ";
> printf(mysql_result($result,$count,"town3"));
> echo "\n";
>
> echo "IP Address: ";
> printf(mysql_result($result,$count,"ipaddress"));
> echo "\n";
>
> echo "Ad: ";
>
> $ad[$count] = (mysql_result($result,$count,"ad"));
>
> $ad[$count] = ereg_replace ("&a&", "'", $ad[$count]);
> $ad[$count] = ereg_replace ("&q&", "\"", $ad[$count]);
> $ad[$count] = ereg_replace ("&p&", "%", $ad[$count]);
> $ad[$count] = ereg_replace ("&bs&", "\\", $ad[$count]);
>
>
> echo $ad[$count];
> echo "\n";
>
> echo "Total: ";
> printf(mysql_result($result,$count,"total"));
> echo "\n";
>
> echo "Ad Number: ";
> printf(mysql_result($result,$count,"num"));
> echo "\n";
>
> echo "Date: ";
> printf(mysql_result($result,$count,"date"));
> echo "\n";
>
> echo "Time: ";
> printf(mysql_result($result,$count,"time"));
> echo "\n";
>
> } while($row = mysql_fetch_array($result));
>
> } else {print "Sorry, no records were found!";}
>
> ?>
> So far I have come to the conclusion that the input from the user is
> probably where my problem is