On Thu, 06 Feb 2003 10:33:23 -0700, Doug Thompson wrote:
>Try getting the results from the query like the following.
-snip-
With the correct syntax. 8-(
Doh!
>
>//
>$numrows = mysql_num_rows ($result);
> ^
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Try getting the results from the query like the following.
Doug
// generate and execute query
$query = "select * from changelog where changedBy = '$changedBy' or
vendorNumber = '$vendorNumber'
or oldName like '$oldName' or newName like '$newName' or
newVendorNumber =
'$newVendorNumber'";
$result
Okay, I figured out that the issue is not due to the PHP code, but by the
query I'm using against the MySQL DB...
What I need to know is how to structure the code where the query is based
off of fields filled in by the user. I would like to structure the query
where if the user provides a value f
> I am a novice PHP dev having a strange issue with
mysql_fetch_array.
> For some reason, it is keeping data from previous queries in the
array,
> and
> displaying it in the web page.
> My development platform is Win2k SP2, Apache 1.3.23, PHP 4.3.0,
> MySQL-MAX 3.23.47-nt.
> Here is the
