I'm not sure I understand your question, but my interpretation would be
solved like this
select * from table where variable in (select id from tablefield1)
I hope this helps you!!
Natalie
On 9/16/06, Hassan [EMAIL PROTECTED] wrote:
Hi My Best List, I have a field in a table contains
If you have the literal string 3,31,11,10 in a field in your table
then you can 'search' for numbers in the string like this:
SELECT * FROM table WHERE CONCAT(',', tablefield1, ',') LIKE '%,3,%'
I don't know if it's the best way of doing it but it works for me.
Natalie Leotta wrote:
I'm not
I guess this is this closest, but apparently in this case if the 3 at the
beginning doesn't exact, and even using LIKE '%3,%' (removing the first comma)
would match an entry like 33, !
I need a better solution, does mysql have something similar to explode() in
PHP?
if it does, then how
