Ramil and Jochem,
Having mySQL format the date is the best solution... thanks!
Frank
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On Tue, 14 Dec 2004 15:39:52 -0600, Frank Marousek
[EMAIL PROTECTED] wrote:
I'm using the following code to display dates returned from a query of a
mySQL database.
$new_timestamp = strtotime($row_SearchPlayerRcrdSt['Date']);
$new_date_formatted = date (m/d/y, $new_timestamp);
echo
Frank Marousek wrote:
I'm using the following code to display dates returned from a query of a
mySQL database.
What kind of field is it? (int,timestamp,datetime,etc)
$new_timestamp = strtotime($row_SearchPlayerRcrdSt['Date']);
what do the following contain:
$new_timestamp
Sorry to visit this once again, but this is a problem with bits the solution
to which causes other problems.
I need to do this in a SQL query:
(arrival+nights)='$thisdate'
'arrival' is a date field, and 'nights' is an integer, so the above makes no
sense, being like 2004/12/31+7 which is
The answer seems to be DATE_ADD but I haven't got it to work yet...asking
the MySQL people.
I need to do this in a SQL query:
(arrival+nights)='$thisdate'
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Quoting ioannes [EMAIL PROTECTED]:
The answer seems to be DATE_ADD but I haven't got it to work yet...asking
the MySQL people.
Check your version of MySQL... I think that's a newer function.
-Ed
This message was sent using
) '$thisdate';
INTERVAL means what it says, so from 1/1/04 add an interval of 1 gives
3/1/04, not 2/1/04. Hence my -1.
John
- Original Message -
From: ioannes [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, September 02, 2004 7:42 PM
Subject: Re: [PHP-DB] Dates - adding to unix 86400
From: ioannes [EMAIL PROTECTED]
?
//unix date is 1099177200 seconds since 01/01/1970
//date based on unix 31 10 2004
$thisdate=date(d m Y,1099177200);
print($thisdate);
$next=1099177200+60*60*24; //86400
//add 86400 should give next unix date
//date based on this is also 31 10 2004
print(br);
what are you seeing for output?
When I run your code I get the following
30 10 2004
31 10 2004
running on Fedora Core 1, Apache 2.0.5, PHP 5.0.1
--
Craig Brothers
[EMAIL PROTECTED]
On Wed, 2004-09-01 at 08:49, ioannes wrote:
Code:
?
//unix date is 1099177200 seconds since 01/01/1970
I don't get you...
your code outputs:
30 10 2004br31 10 2004
so, y added..:
$next+=(60*60*24);
print(br);
$thisdate=date(d m Y,$next);
print($thisdate);
and the output is: 30 10 2004br31 10 2004br01 11 2004
nice
Ref: Server: Apache/1.3.26 (Unix) PHP/4.3.8
On Wed, 1 Sep 2004 13:49:33
When I run this code I get:
31 10 2004
31 10 2004
http://www.shortstay-london.com/testdates.php
- Original Message -
From: Craig Brothers [EMAIL PROTECTED]
To: ioannes [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, September 01, 2004 2:00 PM
Subject: Re: [PHP-DB] Dates - adding
From: ioannes [EMAIL PROTECTED]
When I run this code I get:
31 10 2004
31 10 2004
http://www.shortstay-london.com/testdates.php
Try printing out the hours, minutes and seconds along with the date and
you'll see the issue.
---John Holmes...
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To
[day after first day above], but this gives me 11pm on 31 Oct as above.
?
- Original Message -
From: John Holmes [EMAIL PROTECTED]
To: ioannes [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, September 01, 2004 2:31 PM
Subject: Re: [PHP-DB] Dates - adding to unix 86400 seconds
From: ioannes [EMAIL PROTECTED]
Sunday 31st of October 2004 12:00:00 AM unix: 1099177200 - first day
Saturday 30th of October 2004 12:00:00 AM unix: 1099090800 - previous day
Sunday 31st of October 2004 11:00:00 PM unix: 1099263600 - day after first
day
if I add 86400 to first - 1099177200 - I
: [PHP-DB] Dates - adding to unix 86400 seconds not equal nextday
From: ioannes [EMAIL PROTECTED]
When I run this code I get:
31 10 2004
31 10 2004
http://www.shortstay-london.com/testdates.php
Try printing out the hours, minutes and seconds along with the date and
you'll see
Magnificent.
- Original Message -
From: John Holmes [EMAIL PROTECTED]
To: ioannes [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, September 01, 2004 3:10 PM
Subject: Re: [PHP-DB] Dates - adding to unix 86400 seconds not equal nextday
From: ioannes [EMAIL PROTECTED]
Sunday 31st
From: Craig Brothers [EMAIL PROTECTED]
I think your problem might be due to daylight savings time. 10/31/04 is
the day that the clocks get set back 1 hour (at 2am). therefore we have
25 hours in the day on 10/31.
not sure how to get around it though, or why my system accounts for it.
You're just
Isn't this due to how your operating system handles the switch from
daylight saving time to GMT (or local equivilent)? Or is this handled by
PHP? That could account for different experiences. Of course if your
locale doesn't switch from DST on this date you won't see the issue
either...
Using
Message -
From: Simon Rees [EMAIL PROTECTED]
To: ioannes [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, September 01, 2004 3:16 PM
Subject: Re: [PHP-DB] Dates - adding to unix 86400 seconds not equal nextday
Isn't this due to how your operating system handles the switch from
daylight
Of course, it's because the whole of Summer is an hour out and this changes
31 Oct. I had it backwards.
I'd still like to find out if there is a mysql equivalent of gmmktime for
use in queries like:
SELECT UNIX_TIMESTAMP(mydate) FROM MyTable WHERE
UNIX_TIMESTAMP(mydate)='$thisdate';
and
I'd still like to find out if there is a mysql equivalent of gmmktime for
use in queries like:
SELECT UNIX_TIMESTAMP(mydate) FROM MyTable WHERE
UNIX_TIMESTAMP(mydate)='$thisdate';
and $thisdate is a gm date. Otherwise I need to convert the GMT date back
to Summer time just for the query. Is
Final problem on this was adding a number of nights to an arrival date in a
query:
$query=SELECT field FROM Table WHERE
(UNIX_TIMESTAMP(arrival)+nights*86400-86400+3600)='$thisdate');
When the arrival date is in Summer, adding a number of night requires
adjusting for the hour [3600], because
.
Any help on these two?
Cheers,
Shannon
-Original Message-
From: Pablo M. Rivas [mailto:[EMAIL PROTECTED]
Sent: Monday, 28 June 2004 9:21 AM
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Dates and Count
Hello Shannon,
SD First, I have two dates stored in a MySQL DB
To: [EMAIL PROTECTED]
Subject: Re: [PHP-DB] Dates and Count
Hello Shannon,
SD First, I have two dates stored in a MySQL DB that I want to do a compare
on
SD and then only display via a web page those records that have a 5 or
greater
SD day difference in them. What would be the best way to achieve
Hello Shannon,
SD First, I have two dates stored in a MySQL DB that I want to do a compare on
SD and then only display via a web page those records that have a 5 or greater
SD day difference in them. What would be the best way to achieve this.
Depends on your mysql version...
select * from
On Sunday 26 January 2003 17:02, Paul Chvostek wrote:
So what's the best way to store a date? I've always liked storing epoch
seconds as INTs, and leaving the translation to/from a human-readable
date up to the application, but aside from the relative unreadability of
this, are there any
[snip]
Would I be better off spending a few bytes extra per record and
storing
things as DATETIME rather than an INT? If I'm looking at the
possibily
making the application more database-portable in the future, are there
gotchas I should be aware of with any particular field types?
This has
May I recommend setting the field type to INT, and just using timestamps?
That's what I usually do, then you can manipulate things however you want.
Much more convenient than the date style type I think. Looking at how the
MySQL docs talk about the DATETIME field, I bet the database is doing
I am doing a database of things that have dates, some I know the
month and year of, some I only know the year. I suppose I could do a
field for the year, and one for month, and then allow the month to be
NULL. But is there a date type that allows years and / or months???
If that's all you
ventdate = $todaysdate ORDER BY
eventdate;
Mike
- Original Message -
From: Alex Francis [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, April 17, 2002 5:26 PM
Subject: Re: [PHP-DB] Dates in MYSQL
Tried the following as suggested - Still no dates showing
Hi Alex Francis,
SELECT From the database WHERE date = todays date.
^ somethink like now() or date()
an other method you put the date in a variable that you get by the
datecommand and make
SELECT From table WHERE date = datevar (variable with current
Hi Alex,
Got my select statement to work as follows:
$query = ' SELECT * FROM notices WHERE TO_DAYS(eventdate) =
TO_DAYS(now())
order by eventdate';
=well done!
However the TO-DAYS calls do seem a bit OTT.
Please post the schema for tbl:notices - specifically the datatype for
eventdate.
Tried the following as suggested - Still no dates showing
$query = ' SELECT id, eventheading, DATE_FORMAT(eventdate, %D %M %Y)as
evdt FROM notices WHERE TO_DAYS(eventdate) = TO_DAYS(now()) order by
eventdate';
$result=mysql_db_query($dbname, $query, $link);
if (!$result) { echo(
PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, April 17, 2002 5:26 PM
Subject: Re: [PHP-DB] Dates in MYSQL
Tried the following as suggested - Still no dates showing
$query = ' SELECT id, eventheading, DATE_FORMAT(eventdate, %D %M %Y)as
evdt FROM notices WHERE TO_DAYS(eventdate) = TO_DAYS(now
te ORDER BY
eventdate;
Mike
- Original Message -
From: Alex Francis [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Wednesday, April 17, 2002 5:26 PM
Subject: Re: [PHP-DB] Dates in MYSQL
Tried the following as suggested - Still no dates showing
$query = ' SELECT id, eventheading, DAT
Try something like:
date_format(news_date, '%d %M %Y @ %H:%I:%S')
Go to http://www.mysql.com/doc/D/a/Date_and_time_functions.html and look for
date_format to determine what parameters to use in order to format the date
as you want it. Note that this method will actually format the date
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