Hi Dave,
I wrote the following script which does exaclty that.
Cami
?
mysql_connect ($hname, $usrname, $password) OR DIE (unable to connect);
$selectstmnt = your sql statement;
$result = mysql_db_query ($dbname, $selectstmnt);
$numrows = mysql_num_rows($result);
$i=3;
echo table cellpadding=0 border=0 callspacing=0;
if ($result) {
while ($list = mysql_fetch_array ($result))
{
if($i==3) { $i=0;
echo tr; }
echo td width=\126\ height=\23\ valign=\middle\
align=\center\.$list[yourvariablename]./td;
$i++;
if($i==3) {
echo /tr; }
} // end while fetch_array
if ($numrows%3==2){echo tdnbsp;/td/tr;}
if ($numrows%3==1){echo tdnbsp;/tdtdnbsp;/td/tr;}
} //end if numrows0
echo /table;
?
-Original Message-
From: Greg Donald [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 18, 2002 2:14 PM
To: Dave Carrera; php List
Subject: Re: [PHP-DB] I cant get the logic for this...
I want to display return results from my query (which works fine)
In I tidy way on screen.
So my result returns say seven results, I have a table, and I want to
show
3 results per row of the table... I.e.:
Table
TR
TD = result1 /TD TD result2 /TD TD = result3 /TD
/TD
/TR
TR
TD = result4 /TD TD result5 /TD TD = result6 /TD
/TD
/TR
TR
TD = result7 /TD TD resultempty /TD TD = resultempty /TD
/TD
/TR
/table
The last two td in row 3 are empty because result found 7 results.
This cant be fixed so echo statements wont work as the result could
Be 3 or 10 or 56 or whatever.
As Always your help and or guidance in this matter is appreciated.
You need a incrementer variable so you can tell when you have 3 td cells
built, so you know when to end the current tr and start a new one.
Then, you need to test that variable again when you run out of
mysql_num_rows(), and fill the 1 or 2 needed td cells with nbsp;
Also, you might wanna look around for some table building classes if your
data is always gonna be really abstract.
Greg Donald - http://destiney.com/
http://phprated.com/ | http://phplinks.org/ | http://phptopsites.com/
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