On Saturday 06 July 2002 08:18, Matthew Nock wrote: > I want to create a form that will input a number of records, into a number > of different tables. > > The first part of the detail will need to create a new "product" record. > this will create Product ID. the Product ID is required to insert the > "features" for this product ID into another table. > > Is there any way that run determine the ProdID of the record I am > inserting, so that I can run the insert for the features?
If ProdID is an autoincrement field (and if it isn't you really should make it so), then use mysql_insert_id(). > or am I going to need to Insert the Product record (to get the Product ID), > and then query the product database, to get the new ID, then use the newly > gained ID, to add all the features to the feature table? That's what you'll have to do if ProdID is not an autoincrement field. -- Jason Wong -> Gremlins Associates -> www.gremlins.com.hk Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * /* Someone's tie is caught in the printer, and if anything else gets printed, he'll be in it too. */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
