* Micah Stevens <[EMAIL PROTECTED]>:
> What kind of speed do you need?
I was aiming at something that would run in 2 hours or so. Currently, it
takes around 3 - 4.
> I had to go to temp tables for a logging application, but not until my
> table got upwards of a million records or so.. For the n
What kind of speed do you need? I had to go to temp tables for a logging
application, but not until my table got upwards of a million records or so..
For the numbers your quoting, it should be pretty quick unless your engine
needs optimization..
On Friday 11 February 2005 11:56 am, Matthew
* Micah Stevens <[EMAIL PROTECTED]>:
> Sounds like a self join should work wonders.
>
> I didn't test this, but the idea should work:
>
>
> select t1.app_id as a1, t2.app_id as a2, t2.word, t2.score
> from tablename as t1
> left join tablename as t2
> on t1.resource_id = t2.resource_id and t1.ap
Sounds like a self join should work wonders.
I didn't test this, but the idea should work:
select t1.app_id as a1, t2.app_id as a2, t2.word, t2.score
from tablename as t1
left join tablename as t2
on t1.resource_id = t2.resource_id and t1.app_id != t2.app_id
group by word
order by word
voila
* Martin Norland <[EMAIL PROTECTED]>:
> Matthew Weier O'Phinney wrote:
> > I have a table which contains the following:
> > id (primary key, auto incrementing)
> > app_id (integer, foreign key)
> > resource_id (integer, foreign key)
> > word
> > score
> >
> > (This is a search
Matthew Weier O'Phinney wrote:
I have a table which contains the following:
id (primary key, auto incrementing)
app_id (integer, foreign key)
resource_id (integer, foreign key)
word
score
(This is a search index.) I want to find all resource_ids from one app_id
that match resour
