> ok so you would have to use :
> --select count(distinct itemid) from business where name like 'word1'
or
> name like 'word2' or name like 'word3';
> no other go.
If you're not going to use wildcards, then you can use IN. The whole
idea of using LIKE is that you can use _ and % as wildcards when
with IN, only with LIKE or regular expressions.
---John Holmes...
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:Amit_Wadhwa@;Dell.com]
> Sent: Sunday, November 03, 2002 5:31 PM
> To: [EMAIL PROTECTED]
> Subject: RE: [PHP-DB] LIKE statement or IN statement?
>
>
Chris Barnes wrote:
Yeah I really need to search for multiple words. Can anyone confirm if
the IN statement will work for me in this situation?
Chris --
Why not just try it you self and let's us know.
Also check to MySQL doc at http://mysql.org
David
On Mon, 2002-11-04 at 09:31, [EMAIL PROT
You can't use wildcards with IN, only with LIKE or regular expressions.
---John Holmes...
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:Amit_Wadhwa@;Dell.com]
> Sent: Sunday, November 03, 2002 5:31 PM
> To: [EMAIL PROTECTED]
> Subject: RE: [PHP-DB] LIKE state
Yeah I really need to search for multiple words. Can anyone confirm if
the IN statement will work for me in this situation?
On Mon, 2002-11-04 at 09:31, [EMAIL PROTECTED] wrote:
> if you want to search for multiple words, u have to use multiple like
> operators:
> select count(distinct itemid) fro
if you want to search for multiple words, u have to use multiple like
operators:
select count(distinct itemid) from business where name like 'word1' or
name like 'word2' or name like 'word3';
or the IN statement with wildcards:
select count(distinct itemid) from business where name IN
('%word1%',
