Hi,
You could use something like
#start
do
{
echo "<tr>";
$fields=odbc_num_fields($data2);
for($i=3 ; $i<=$fields ; $i++)
echo "<td nowrap>";
if (odbc_result($data2,$i) = 'SOX')
echo "<a href='sox_page_url'>".odbc_result($data2,$i)."</a>";
else
echo odbc_result($data2,$i);
echo "</td></tr>\n";
} while(odbc_fetch_row($data2));
echo "</table>";
#end
The idea is to output one thing when the result matches your criteria and
another when it doesn't.
Hope this helps
Dobromir Velev
-----Original Message-----
From: John A DAVIS <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
Date: Tuesday, July 17, 2001 2:39 AM
Subject: [PHP-DB] Need syntax for conditional in recordset loop
How would I code "IF .odbc_result($data2,$i) = 'SOX' THEN make it a link"?
By link I mean that I want the word "SOX" highlited in blue and underlined
and referencing a webpage that explains SOX verbosefully. Don't know PHP IF
THEN syntax too well.
/* fill table with data */
do
{
echo "<tr>";
$fields=odbc_num_fields($data2);
for($i=3 ; $i<=$fields ; $i++)
echo "<td nowrap>".odbc_result($data2,$i)."</td>";
echo "</tr>\n";
} while(odbc_fetch_row($data2));
echo "</table>";
John A. Davis
Information Systems Specialist
OHD DWP
State of Oregon
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