Re: [PHP-DB] New to PHP/MySQL - Need help with images

[Chris]

Thomas wrote:
I'm attempting to make a table with one row and 3 columns holding three 
different images. I want each image URL to be called from my database. 
Everything is set-up in my database. When I use the following code, it 
places the same picture across the three columns and does this three 
times (creating three rows.) I want a different picture to be placed 
across the three columns and to have only one row. What can I do?



Here is the code:

$result = @mysql_query('SELECT image FROM specials');


You're only querying one database field here. If you want more than one 
image to be loaded from the database, you need to include more fields.


So you'll end up with something like this:


?php

$query = select image1, image2, image3 from specials;
$result = mysql_query($query);

echo 'table';

while ($row = mysql_fetch_assoc($result)) {
echo 'tr';
echo 'td' . $row['image1'] . '/td';
echo 'td' . $row['image2'] . '/td';
echo 'td' . $row['image3'] . '/td';
echo '/tr';
}
echo '/table';
?


--
Postgresql  php tutorials
http://www.designmagick.com/

--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Re: [PHP-DB] New to PHP/MySQL - Need help with images

[Matt Anderton]

how about like this:

echo table\ntr;
$result = @mysql_query(SELECT image FROM specials);
while($row = mysql_fetch_row($result)) {
   echo tdimg src= . $row[0] .  //td\n;
}
echo /tr\n/table\n;

hope it helps!
matt

On Jan 5, 2008 4:51 PM, Thomas [EMAIL PROTECTED] wrote:

 I'm attempting to make a table with one row and 3 columns holding three
 different images. I want each image URL to be called from my database.
 Everything is set-up in my database. When I use the following code, it
 places the same picture across the three columns and does this three times
 (creating three rows.) I want a different picture to be placed across the
 three columns and to have only one row. What can I do?

 Here is the code:

 $result = @mysql_query('SELECT image FROM specials');
 $num=mysql_numrows($result);
 $i = 0;
 while ($i  $num) {
 $image=mysql_result($result,$i,image);
 ?
 table
 tr
 td
 img src=? echo $image; ?
 /td
 td
 img src=? echo $image; ?
 /td
 td
 img src=? echo $image; ?
 /td
 /tr
 ?
 $i++;
 }
 echo /table;
 ?

 --
 Using Opera's revolutionary e-mail client: http://www.opera.com/mail/

 --
 PHP Database Mailing List (http://www.php.net/)
 To unsubscribe, visit: http://www.php.net/unsub.php