Lisi a écrit :

> That worked...why?
>

because in your table you wrote "_SPACE_Hatzoloh_SPACE_"
or _NEWLINE_Hatzoloh_NEWLINE_ ...any way you wrote "Hatzoloh" and some
caracter that you don't see it so easy (space, tab, new_line).

% is like * on regular expresion (wildcard)

>
> -Lisi
>
> At 09:23 AM 4/9/02 +0300, Marius Ursache wrote:
>
> >Lisi a écrit :
> >
> > > I have the following query:
> > >
> > > SELECT * FROM ayny WHERE organization LIKE 'Hatzoloh'
> > >
> >
> >try "SELECT * FROM ayny WHERE organization LIKE '%Hatzoloh%' "
> >
> > >
> > > which produces no results, when I set
> > >
> > > $numrows = mysql_num_rows($result);
> > >
> > > it equals 0.
> > >
> > > When I do the following:
> > >
> > > SELECT * FROM ayny
> > >
> > > and then loop through the results, echoing them to the screen with the
> > > following code:
> > >
> > > while ( list($key,$val) = each($result_array) ) {
> > >     echo "$key = $val<BR>";
> > > }
> > >
> > > I do get a line
> > >
> > > organization = Hatzoloh
> > >
> > > So why can't I pull just the record for Hatzoloh using my first query?
> > >
> > > Please let me know if you need more code to figure this out.
> > >
> > > Thanks,
> > >
> > > -Lisi
> > >
> > > --
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> >
> >--
> >   Marius Ursache (3563 || 3494)
> >
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> >
> >
> >
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--
  Marius Ursache (3563 || 3494)

                           \|/ ____ \|/
                           "@'/ ,. \`@"
                           /_| \__/ |_\
                              \__U_/



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