Thanks Martin, oddly enough that still doesn't pull any results, it won't
even print the variables if I try to list them to see, I know my db
connection is good checked that, and can do really simple queries, would
something be preventing a JOIN from working?
When I Reveal my variables this query
What I wrote with HAVING doesn't do any difference - replace back to WHERE.
Your query is OK.
Try: echo mysql_error();
And try to remove the condition WHERE admin.user... if that outputs
anything.
Martin
Terion Miller napsal(a):
Thanks Martin, oddly enough that still doesn't pull any
When I removed the WHERE admin.user... part it did return something, granted
it returned one adminID and one order (which did belong together) but the
adminID was not mine so I don't know how it picked that one randomly ...is
there a way to do what I need using two queries one to find out the
Are you sure you have MORE than ONE [order + admin that belongs
together] in those tables?
Now, turn on your brain and don't wait for my instructions, you already
know what to do... test test test
Terion Miller napsal(a):
When I removed the WHERE admin.user... part it did return something,
Try that query in console or use Navicat/phpMyAdmin to run it. Remove
the HAVING part to see if the SELECT returns what you need.
Terion Miller napsal(a):
Thanks Martin, oddly enough that still doesn't pull any results, it won't
even print the variables if I try to list them to see, I know my
Yes I've already done that and checked the db etc and I've turned my brain
ON hours ago, I came to the list because I'm stumped and have tried all
manners of different ways to tell mySql
if admin ID = session user then get workorders where orderID = admin ID
On Thu, Jan 29, 2009 at 1:28
SELECT adminID FROM admin WHERE username= $username
$adminid = mysql_fetch_row ...
SELECT * FROM workorders WHERE adminid = $adminid
Terion Miller napsal(a):
Yes I've already done that and checked the db etc and I've turned my
brain ON hours ago, I came to the list because I'm stumped and
Martin Zvarík wrote:
This will work:
$sql =
SELECT admin.AdminID, workorders.WHAT_YOU_WANT
FROM admin
INNER JOIN workorders ON admin.AdminID=workorders.AdminID
HAVING admin.username='.$_SESSION['user'].'
;
Don't use having in this case - this should be a 'where' clause.
A 'having' clause is
Actually I have tried EVERYTHING suggested and it just does not work, in my
last query here I put in a user I know has orders and still nothing :
$sql3 = SELECT admin.AdminID, workorders.WorkOrderID,
workorders.DATE_FORMAT(CreatedDate,'%m/%e/%y') AS SubmitDate,
workorders.Location,
Terion Miller wrote:
Actually I have tried EVERYTHING suggested and it just does not work, in
my last query here I put in a user I know has orders and still nothing :
$sql3 = SELECT admin.AdminID, workorders.WorkOrderID,
workorders.DATE_FORMAT(CreatedDate,'%m/%e/%y') AS SubmitDate,
Yep they both work separately ... can't believe I've been stuck on the same
thing all day, it seems like an easy thing...
On Thu, Jan 29, 2009 at 5:09 PM, Chris dmag...@gmail.com wrote:
Terion Miller wrote:
Actually I have tried EVERYTHING suggested and it just does not work, in
my last
Please post under the other replies, it makes it easier to follow.
Terion Miller wrote:
Yep they both work separately ... can't believe I've been stuck on the
same thing all day, it seems like an easy thing...
From what you've shown us it should work.
Maybe post the output of:
show create
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