Lots of people told me about the quote issue. Thanks!
One more thing, how do you encrypt a string into the password. In the
mysql database it is interperated as a password, so it is a different
combination than the actual password. How do I do this in php?
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Squeakypants wrote:
I can't figure this out, it just shows blank...
$user=$_POST['user'];
$pass=$_POST['pass'];
mysql_connect($host,$username,$password);
@mysql_select_db($database) or die( Unable to select database);
You're suppressing the error returned from mysql_select_db with the @
symbol.
Try this
$query = SELECT credits FROM krypto WHERE user='$user' AND pass='$pass';
That should work better then the original query...
Best regards
Andi
Squeakypants schrieb:
From a forum that recommended this to me, I changed the query execution to this:
$query = SELECT credits FROM krypto WHERE
Squeakypants wrote:
From a forum that recommended this to me, I changed the query execution to this:
$query = SELECT credits FROM krypto WHERE user=$user AND pass=$pass;
echo query = . $query .\n;
$result = mysql_query($query);
echo result = . $result .\n;
So now it outputs this:
query = SELECT
Well, any text elements need single quotes around it for the sql engine to
evaluate it properly
s/b
$query = SELECT credits FROM krypto WHERE user='$user' AND pass='$pass';
to give you
query = SELECT credits FROM krypto WHERE user='admin' AND pass=''
bastien
From: Squeakypants [EMAIL
Squeakypants ha scritto:
From a forum that recommended this to me, I changed the query execution to this:
$query = SELECT credits FROM krypto WHERE user=$user AND pass=$pass;
echo query = . $query .\n;
$result = mysql_query($query);
echo result = . $result .\n;
So now it outputs this:
query =
Personally, I would interpolate the $query and $user string like so:
$query = SELECT credits FROM krypto WHERE user='.$user.' AND
pass='.$pass.';
Always works for me...
rgd
chris r.
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