i tend to take the approach of
$next_wed = date("Y-m-d", strtotime("next wednesday"));
Bastien
From: Niel Archer <[EMAIL PROTECTED]>
Reply-To: php-db@lists.php.net
To: php-db@lists.php.net
Subject: Re: [PHP-DB] SELECT date query
Date: Sat, 07 Oct 2006 05:49:36 +0
Hi
> You can make this easier with date('w').
Doh, that'll teach me to code at 5 am. I knew there was a better way,
but couldn't think of it, the sound of my bed calling was too
distracting.
Niel
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Hi!
You can make this easier with date('w').
$correction = array(3, 2, 1, 7, 6, 5, 4);
list($year, $month, $day, $dayOfWeek) = explode('|', date('Y|m|d|w'));
echo date ("Y.m.d", mktime
(0,0,0,$month,$day+$correction[$dayOfWeek],$year));
Regards,
Felhő
Niel Archer wrote:
Hi Ron
I've ma
Hi Ron
I've made the assumption that if today is Wednesday, you still want next
Wednesday.
Try this:
$offset = array(3,2,1,7,6,5,4);
$date = explode("-", date("Y-n-j"));
$ToDay = DayOfWeek($date[0], $date[1], $date[2]);
$NextWed = date("Y-n-j", time() + ($offset[$ToDay] * 24 * 60 * 60));
// Retu
