I tested this and it seems to work:
$n = 1.90;
for($i=strlen($n);$i0;$i--){
if(substr($n,$i,1) == 0){
$n = substr($n,0,(strlen($n))-1);
}else{
break;
}
}
No charge...this time. =)
Regards,
Mike
- Original Message -
From: Thomas Murphy [EMAIL PROTECTED]
To:
Hello Mike,
Mike Maltese wrote:
I tested this and it seems to work:
$n = 1.90;
for($i=strlen($n);$i0;$i--){
if(substr($n,$i,1) == 0){
$n = substr($n,0,(strlen($n))-1);
}else{
break;
}
}
No charge...this time. =)
thank you very much. :)
bye,
Thomas
i still have some problems on typecasting my float-variable to a string
variable.
i used something like this:
$n = $row[Points];
settype($n,string);
but the zeros are still there - as if $n is still handled as a float
number not a string.
with $n = 1.90 it's converted to 1.9 without problems...
