MySQL cannot find the username in its grant tables.
The error message very clearly states that there is no user named
'x,@host' which is the value of your $user variable. For your example,
$email == 'x' and $femail == '@host'. The comma is included because it
is part of the literal string,
do you have any idea why the following(line 106)would return the
following
error message ? the login.php has an included form to create an
account and that is what will not connect.
$connection = mysql_connect($host, $user,$password) //this is line 106
Warning: Access denied for user:
