MySQL cannot find the username in its grant tables.
The error message very clearly states that there is no user named
'x,@host' which is the value of your $user variable. For your example,
$email == 'x' and $femail == '@host'. The comma is included because it
is part of the literal string, i.e., inside the double quotes.
hth,
Doug
On Tue, 14 Jan 2003 22:08:11 -0600, Addison Ellis wrote:
hello,
do you have any idea why the following(line 106)would return
the following
error message ? the login.php has an included form to create an
account and that is what will not connect.
$connection = mysql_connect($host, $user,$password) //this is line 106
Warning: Access denied for user: 'x,@host' (Using password: YES) in
/users/infoserv/web/register/login.php on line 106
Warning: MySQL Connection Failed: Access denied for user: 'x,@host'
(Using password: YES) in /users/infoserv/web/register/login.php on
line 106
Couldn't connect to server.
my required file is as follows:
?
$user=$email,$femail;
$host=$hostname;
$password=password('$password'),password('$fpassword');
$database=$classes;
?
thank you again for your time. addison
--
Addison Ellis
small independent publishing co.
114 B 29th Avenue North
Nashville, TN 37203
(615) 321-1791
[EMAIL PROTECTED]
[EMAIL PROTECTED]
subsidiaries of small independent publishing co.
[EMAIL PROTECTED]
[EMAIL PROTECTED]
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