Oops, actually forgot my GROUP BY clause. The full query is:
SELECT e1.field1, e1.field2, l1.field3, SUM(a1.adp_amount) as amount
FROM a1
inner join e1 on (e1.loanID = a1.adp_loanID)
inner join l1 on (l1.entreID = e1.entre_ID)
WHERE e1.entre_active = 'Y'
GROUP BY e1.field1, e1.field2, l1.field3
hth,
Yves
- Original Message -
From: Yves Sucaet yves.suc...@usa.net
To: php-db@lists.php.net
Sent: Tuesday, January 13, 2009 7:49 AM
Subject: Re: [PHP-DB] help me JOIN 3 tables.
Hi Joseph,
With the sum() aggregate function you'll need to use a GROUP BY clause and
specify which fields you want from e1 and l1. Something like this:
SELECT e1.field1, e1.field2, l1.field3, SUM(a1.adp_amount) as amount
FROM a1 inner join e1 on (e1.loanID = a1.adp_loanID) inner join l1 on
(l1.entreID = e1.entre_ID)
WHERE e1.entre_active = 'Y'
hth,
Yves
- Original Message -
From: Abah Joseph joefa...@gmail.com
To: php-db@lists.php.net
Sent: Tuesday, January 13, 2009 6:46 AM
Subject: [PHP-DB] help me JOIN 3 tables.
I have this SQL
SELECT e1.*, l1.* FROM e1
INNER JOIN l1 WHERE e1.entre_active = 'Y' AND l1.entreID = e1.entre_id
The above query works but i want to add the one below
SELECT SUM(a1.adp_amount) as amount FROM a1 WHERE a1.adp_loanID =
e1.loanID;
the last part of the query is to SUM the part payment made on table 'l1'
and
return total raised with the first query.
the whole idea is three tables, (business, loan, raised), loan referenced
ID
from business, raised referenced ID from loan.
loan maybe $300 and it can be raised over time till completed, so all the
amount raised + the loanId will be stored inside the raised table.
Thank you
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
