I was having the same problem for a while... although, I
was using this:
for($i=0;$i
Good luck,
Ben
Quoting BrianSander <[EMAIL PROTECTED]>:
> Greetings,
>
> I'm experiencing the strangest problem and I was
> wondering if anyone
> else has had the same problem.
>
> I have a fairly simple scr
You must use a loop to show each row of your query.
"mysql_fetch_array($result)" only get the current row.
while($row = mysql_fetch_array($result) ){
// do something
}
The "mysql_fetch_array" function returns an associative array where you can
use the field names to have access to its val
> How can I refer to one specific row in this query..?
> What I mean is, how can i refer to result row number 4...?
>
> If I only selected rows from one table I could do something like this:
>
> $i = mysql_fetch_array($sql) ;
> echo "$i[4]" ;
Actually, no. mysql_fetch_array return the _current r
Trond,
What is your table structure?
I'm guessing you need a different query.
Also, be aware that mysql_fetch_array returns an array with the field name
as value, so:
$sql="select fields from table where id = $id";
$connection_handle=(mysql_connect($user, $pass, $host);
mysql_select_db($databa
