Re: [PHP-DB] Problem with query
Im going to play devils advocate here and say, why is it the one who's helping that needs to be polite and respectful? Isn't it also the newbies responsibility to respect and be polite to those taking time out of their day to help them and not be so stubborn as to not take the advice given which has been the example given here by Ethan? Ethan has been given great advice and should be taking that advice and looking things up and learning, not asking Newbie confused, please explain?. It seems to me that the Help is being taken advantage of here and used as a crutch to get the work done that Ethan has taken upon himself even thought he knows he knows very little about programming in PHP. And that is PHP not PhD. But all that aside as you can see, the same people who Ethan has somewhat ignored their advice are still going against their better judgement to go out of their way to help.. again. Just how much help should be given before you realize the horse is just not drinking the water? I am all for Ethan getting help from the list and I don't want to chastise, but come on, someone with a PhD should know better and should know even better then most on how to listen and learn. Hence the PhD. You don't get one of those by doing what Ethan is doing. If he did that to his professors, he would have failed. Just saying. Best, Karl On Jun 25, 2013, at 1:32 AM, OJFR wrote: Yeah, Jim, please explain what u mean by Per the manual, associative arrays using string indices should always use ' ' around them. They work (as mentioned in the manual) but are wrong. As long as I remember I could use associative arrays in that way (ex. $_SESSION['Cust_Num']). There's another way to do that using string indices? Why do you say it's wrong? It's obsolete? I would like to make a call to all the members of this mailing list: knowledge is a wonderful gift so, why we don't share it politely and efficiency. Jim, I will take you as an example. You start saying Against my better judgement, here I go again. If it's against your better judgment please don't go anywhere, your conscience is a good adviser. After that you talked a little about standards and some manual. If you are not happy to help people who make some mistakes regarding to programming standards, you should inform them where they can find the glorious manual and what is the correct syntax to do what people need to do. This is a better way to show to others what you know in a humble way but I suppose that wasn't what you were trying to do. I consider this list is to HELP others and share what we know. Never break the silence if it's not to make it better. Ethan, I will check your problem and I'll write you back as soon as I can 'cause right now I don't have anything installed in my computer. I'll try to do it tomorrow, ok? Be nice and stay well!!! Osain. -Mensaje original- De: Ethan Rosenberg, PhD [mailto:erosenb...@hygeiabiomedical.com] Enviado el: domingo, junio 23, 2013 4:38 PM Para: php-db@lists.php.net; Jim Giner Asunto: [PHP-DB] Re: Problem with query On 6/23/2013 2:31 PM, Ethan Rosenberg, PhD wrote: Dear List - There is an error in my query, and I cannot find it. This fails: $_SESSION['Cust_Num'] = $_REQUEST['cnum']; $_SESSION['CustNum'] = $_REQUEST['cnum']; echo sessionbr /; //this has the proper values print_r($_SESSION); $sql10 = select Balance, Payments, Charges, Date from Charges where Cust_Num = $_SESSION[Cust_Num] order by Date; echo $sql10; //echos the correct query $result10 = mysqli_query($cxn, $sql10); var_dump($result1); // this returns NULL Against my better judgement, here I go again. Is this the actual code you executed, or is it once again a typeover? Your 1st error is in these two lines: $result10 = mysqli_query($cxn, $sql10); var_dump($result1); // this returns NULL Yes your dump returns null. And always will. Any further errors might be related to your non-standard syntax for the session variable. Per the manual, associative arrays using string indices should always use ' ' around them. They work (as mentioned in the manual) but are wrong. === Jim - Is this the actual code you executed, or is it once again a typeover? The actual code Any further errors might be related to your non-standard syntax for the session variable. Per the manual, associative arrays using string indices should always use ' ' around them. They work (as mentioned in the manual) but are wrong. Newbie is confused. Please explain. TIA Ethan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Este mensaje le ha llegado mediante el servicio de correo electronico que ofrece Infomed para respaldar el cumplimiento de las misiones del Sistema Nacional de Salud. La persona que envia este correo asume el compromiso de usar el servicio a tales fines y
Re: [PHP-DB] Problem with query
On Sun, Jun 23, 2013 at 8:31 PM, Ethan Rosenberg, PhD
erosenb...@hygeiabiomedical.com wrote:
Dear List -
There is an error in my query, and I cannot find it.
This fails:
$_SESSION['Cust_Num'] = $_REQUEST['cnum'];
$_SESSION['CustNum'] = $_REQUEST['cnum'];
echo sessionbr /; //this has the proper values
print_r($_SESSION);
$sql10 = select Balance, Payments, Charges, Date from Charges where
Cust_Num = $_SESSION[Cust_Num] order by Date;
echo $sql10; //echos the correct query
$result10 = mysqli_query($cxn, $sql10);
var_dump($result1); // this returns NULL
echo centerstrongCurrent Results/strong/center;
echo center;
echo table border='4' cellpadding='5' cellspacing='55' rules='all'
frame='box';
echo tr class='heading';
echo thBalance/th;
echo thPayments/th;
echo thCharges/th;
echo thDate/th;
echo /tr;
echo row1br /;
$row10 is undefined here, so:
$row10 = mysqli_fetch_row($result10); ?
I would suggest using
while (($row1 = mysqli_fetch_row($result1))!= 0 ) { ... }
instead of
do { ... } while (($row1 = mysqli_fetch_row($result1))!= 0 );
This avoids the need of the extra mysqli_fetch_row before the do-while loop.
- Matijn
Re: [PHP-DB] Problem wkith Query
On 23 June 2013 21:37, Ethan Rosenberg, PhD
erosenb...@hygeiabiomedical.com wrote:
On 6/23/2013 2:31 PM, Ethan Rosenberg, PhD wrote:
Dear List -
There is an error in my query, and I cannot find it.
This fails:
$_SESSION['Cust_Num'] = $_REQUEST['cnum'];
$_SESSION['CustNum'] = $_REQUEST['cnum'];
echo sessionbr /; //this has the proper values
print_r($_SESSION);
$sql10 = select Balance, Payments, Charges, Date from Charges
where
Cust_Num = $_SESSION[Cust_Num] order by Date;
echo $sql10; //echos the correct query
$result10 = mysqli_query($cxn, $sql10);
var_dump($result1); // this returns NULL
Against my better judgement, here I go again.
Is this the actual code you executed, or is it once again a typeover?
Your 1st error is in these two lines:
$result10 = mysqli_query($cxn, $sql10);
var_dump($result1); // this returns NULL
Yes your dump returns null. And always will.
Any further errors might be related to your non-standard syntax for
the session variable. Per the manual, associative arrays using string
indices should always use ' ' around them. They work (as mentioned in
the manual) but are wrong.
===
Jim -
Is this the actual code you executed, or is it once again a typeover?
The actual code
Any further errors might be related to your non-standard syntax for
the session variable. Per the manual, associative arrays using string
indices should always use ' ' around them. They work (as mentioned in
the manual) but are wrong.
Newbie is confused.
Please explain.
Try ...
$sql10 = select Balance, Payments, Charges, Date from Charges where
Cust_Num = {$_SESSION['Cust_Num']} order by Date;
--
Richard Quadling
Twitter : @RQuadling
EE : http://e-e.com/M_248814.html
Zend : http://bit.ly/9O8vFY
=
Tried it. No luck
Ethan
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Re: [PHP-DB] Problem wkith Query
Turn on error reporting/logging/displaying and what errors are you getting?
And as you said ...
$result10 = mysqli_query($cxn, $sql10);
var_dump($result1); // this returns NULL
is your actual code, maybe ...
?php
$a = 'set variable a to this message';
var_dump($b);
?
gives you a better clue?
On 23 June 2013 23:06, Ethan Rosenberg, PhD erosenb...@hygeiabiomedical.com
wrote:
On 23 June 2013 21:37, Ethan Rosenberg, PhD erosenberg@hygeiabiomedical.*
*com erosenb...@hygeiabiomedical.com wrote:
On 6/23/2013 2:31 PM, Ethan Rosenberg, PhD wrote:
Dear List -
There is an error in my query, and I cannot find it.
This fails:
$_SESSION['Cust_Num'] = $_REQUEST['cnum'];
$_SESSION['CustNum'] = $_REQUEST['cnum'];
echo sessionbr /; //this has the proper values
print_r($_SESSION);
$sql10 = select Balance, Payments, Charges, Date from Charges
where
Cust_Num = $_SESSION[Cust_Num] order by Date;
echo $sql10; //echos the correct query
$result10 = mysqli_query($cxn, $sql10);
var_dump($result1); // this returns NULL
Against my better judgement, here I go again.
Is this the actual code you executed, or is it once again a typeover?
Your 1st error is in these two lines:
$result10 = mysqli_query($cxn, $sql10);
var_dump($result1); // this returns NULL
Yes your dump returns null. And always will.
Any further errors might be related to your non-standard syntax for
the session variable. Per the manual, associative arrays using string
indices should always use ' ' around them. They work (as mentioned in the
manual) but are wrong.
===
Jim -
Is this the actual code you executed, or is it once again a typeover?
The actual code
Any further errors might be related to your non-standard syntax for
the session variable. Per the manual, associative arrays using string
indices should always use ' ' around them. They work (as mentioned in the
manual) but are wrong.
Newbie is confused.
Please explain.
Try ...
$sql10 = select Balance, Payments, Charges, Date from Charges where
Cust_Num = {$_SESSION['Cust_Num']} order by Date;
--
Richard Quadling
Twitter : @RQuadling
EE : http://e-e.com/M_248814.html
Zend : http://bit.ly/9O8vFY
=
Tried it. No luck
Ethan
--
Richard Quadling
Twitter : @RQuadling
EE : http://e-e.com/M_248814.html
Zend : http://bit.ly/9O8vFY
Re: [PHP-DB] Problem w/query - again
Dear Ethan
It seems you are trying to build a query.But you are not getting field
names. If you required field names then change the following line to
foreach ( $allowed_fields AS $field = $_POST['field'])
to
foreach ( $allowed_fields AS $field)
This would convert the variable field to value. In yoyr line the variable
field is treated as array index
regds
amit
The difference between fiction and reality? Fiction has to make sense.
On Fri, Feb 10, 2012 at 9:40 AM, Ethan Rosenberg eth...@earthlink.netwrote:
Dear list -
This did not seem to post, so I am sending it again.
If it did post, and I missed it, my apologies.
Ethan
Dear list -
I have the following code:
$query = select * from Intake3 where 1;
$allowed_fields = array('Site', 'MedRec', 'Fname', 'Lname',
'Phone', 'Sex', 'Height');
foreach ( $allowed_fields AS $field = $_POST['field'])
{
if ( ! empty( $_POST['field'] ) )
{
$query .= AND '$field' = '$_POST[$field]' ;
echo $query;
}
}
This is the value of $_POST:
Array
(
[Site] = AA
[MedRec] = 1
[Fname] =
[Lname] =
[Phone] =
[Height] =
[welcome_already_seen] = already_seen
)
I receive the following errors on run:
Notice: Undefined offset: 0 in /var/www/srchrhsptl4.php on line 135
select * from Intake3 where 1 AND '0' = ''
Notice: Undefined offset: 1 in /var/www/srchrhsptl4.php on line 135
select * from Intake3 where 1 AND '0' = '' AND '1' = ''
Notice: Undefined offset: 2 in /var/www/srchrhsptl4.php on line 135
select * from Intake3 where 1 AND '0' = '' AND '1' = '' AND '2' = ''
Advice and help please.
Thanks.
Ethan
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Re: [PHP-DB] Problem w/query - again
At 12:13 AM 2/10/2012, Amit Tandon wrote: Dear Ethan It seems you are trying to build a query.But you are not getting field names. If you required field names then change the following line to foreach ( $allowed_fields AS $field = $_POST['field']) to foreach ( $allowed_fields AS $field) This would convert the variable field to value. In yoyr line the variable field is treated as array index regds amit The difference between fiction and reality? Fiction has to make sense. snip Advice and help please. Thanks. Ethan PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Amit - Thanks. Tried it. Still does not work. This is the query I get: select * from Intake3 where 1 Ethan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem w/query - again
Dear Ethan The line you are getting is because the $_POST[fieldname] is blank. So for the following line if ( ! empty( $_POST['field'] ) ) change it to if ( ! empty( $_POST[$field] ) ) Your line : Program is searxchinbg for variable name field New line : The Program is seacging for varable stored in $field. Rember to use double quotes And to verify the value echo $_POST[$field] before your if line i.e. if ( ! empty( $_POST[$field] ) ) regds amit The difference between fiction and reality? Fiction has to make sense. On Fri, Feb 10, 2012 at 11:04 AM, Ethan Rosenberg eth...@earthlink.netwrote: At 12:13 AM 2/10/2012, Amit Tandon wrote: Dear Ethan It seems you are trying to build a query.But you are not getting field names. If you required field names then change the following line to foreach ( $allowed_fields AS $field = $_POST['field']) to foreach ( $allowed_fields AS $field) This would convert the variable field to value. In yoyr line the variable field is treated as array index regds amit The difference between fiction and reality? Fiction has to make sense. snip Advice and help please. Thanks. Ethan PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php Amit - Thanks. Tried it. Still does not work. This is the query I get: select * from Intake3 where 1 Ethan
Re: [PHP-DB] Problem w/query - again
At 12:48 AM 2/10/2012, Amit Tandon wrote: Dear Ethan The line you are getting is because the $_POST[fieldname] is blank. So for the following line  if ( ! empty( $_POST['field'] ) ) change it to  if ( ! empty( $_POST[$field] ) ) Your line : Program is searxchinbg for variable name field New line : The Program is seacging for varable stored in $field. Rember to use double quotes And to verify the value echo $_POST[$field] before your if line i.e.  if ( ! empty( $_POST[$field] ) )    regds amit The difference between fiction and reality? Fiction has to make sense. On Fri, Feb 10, 2012 at 11:04 AM, Ethan Rosenberg mailto:eth...@earthlink.neteth...@earthlink.net wrote: At 12:13 AM 2/10/2012, Amit Tandon wrote: Dear Ethan It seems you are trying to build a query.But you are not getting field names. If you required field names then change the following line to foreach ( $allowed_fields AS $field = $_POST['field']) to foreach ( $allowed_fields AS $field) This would convert the variable field to value. In yoyr line the variable field is treated as array index regds amit The difference between fiction and reality? Fiction has to make sense. snip Advice and help please. Thanks. Ethan PHP Database Mailing List (http://www.php.net/http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.phphttp://www.php.net/unsub.php Amit - Thanks. Tried your edit. Still does not work. Ethan Amit - Thanks. Tried it.  Still does not work. This is the query I get: select * from Intake3 where  1 Ethan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem w/query - again - CORRECTION
At 12:48 AM 2/10/2012, Amit Tandon wrote: Dear Ethan The line you are getting is because the $_POST[fieldname] is blank. So for the following line  if ( ! empty( $_POST['field'] ) ) change it to  if ( ! empty( $_POST[$field] ) ) Your line : Program is searxchinbg for variable name field New line : The Program is seacging for varable stored in $field. Rember to use double quotes And to verify the value echo $_POST[$field] before your if line i.e.  if ( ! empty( $_POST[$field] ) )    regds amit The difference between fiction and reality? Fiction has to make sense. On Fri, Feb 10, 2012 at 11:04 AM, Ethan Rosenberg mailto:eth...@earthlink.neteth...@earthlink.net wrote: At 12:13 AM 2/10/2012, Amit Tandon wrote: Dear Ethan It seems you are trying to build a query.But you are not getting field names. If you required field names then change the following line to foreach ( $allowed_fields AS $field = $_POST['field']) to foreach ( $allowed_fields AS $field) This would convert the variable field to value. In yoyr line the variable field is treated as array index regds amit The difference between fiction and reality? Fiction has to make sense. snip Advice and help please. Thanks. Ethan PHP Database Mailing List (http://www.php.net/http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.phphttp://www.php.net/unsub.php Amit - Thanks. Tried your edit. Still does not work. Ethan Amit - Thanks. Tried it.  Still does not work. This is the query I get: select * from Intake3 where  1 Ethan - Amit - SORRY. Works Perfectly I had commented out my output routine!! Ethan -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with mysql and php
Jason Pruim li...@pruimphotography.com wrote:
Given the following 2 queries:
SELECT DISTINCT areacode FROM main WHERE state = '{$query_exploded[0]}';
SELECT DISTINCT areacode FROM main;
The second displays ALOT faster Like by minutes... the first one is what
I really want though Currently working with a dataset of 89 million
records, will be expanding that to many many more times that... To the tune
of possibly a couple billion records...
Any ideas? :)
make state an index into the table.
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Re: [PHP-DB] Problem with mysql and php
Try running this : http://mysqltuner.pl/mysqltuner.pl
If the server has been up for over 24hrs it gives a lot of good insight and
things to try tuning wise as a starting point. It'll uncover a lot of
common configuration issues or MySQL server level bottlenecks.
-Dan
(apologizes for the top post from the mobile)
On Nov 29, 2011 5:33 PM, Tamara Temple tamouse.li...@tamaratemple.com
wrote:
Jason Pruim li...@pruimphotography.com wrote:
Given the following 2 queries:
SELECT DISTINCT areacode FROM main WHERE state =
'{$query_exploded[0]}';
SELECT DISTINCT areacode FROM main;
The second displays ALOT faster Like by minutes... the first one is
what I really want though Currently working with a dataset of 89
million records, will be expanding that to many many more times that... To
the tune of possibly a couple billion records...
Any ideas? :)
make state an index into the table.
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with mysql and php
Didn't the OP begin this very same subject a month ago? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Problem with mysql and php
From: joker_mos...@hotmail.com To: phps...@gmail.com Date: Tue, 29 Nov 2011 23:07:13 -0500 CC: phildob...@gmail.com; php-db@lists.php.net Subject: Re: [PHP-DB] Problem with mysql and php Le 2011-11-28 à 22:38, Bastien Koert phps...@gmail.com a écrit : On Mon, Nov 28, 2011 at 9:19 PM, Phil Dobbin phildob...@gmail.com wrote: On 29/11/11 02:08, Jason Pruim pru...@gmail.com wrote: PostgreSQL? ;-)... In all seriousness... Would it help or change it in anyway? :) I am free to use what I want (I believe) on this project... It's well worth looking into. Postgres can handle far bigger db's much quicker than MySQL but the downside is that it's a very steep learning curve after coming from mysql. It's relatively easy to install there are the drivers of course for PHP but it'll take up a lot of your time to learn it to the extent of being confident with it in my experience. Good luck, Cheers, Phil... -- Nothing to see here... move along, move along -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php jason, Assuming you have indexes on the data properly, have you looked into the mysql settings to ensure that you have the ones for large or xl datasets? There are a number of settings for buffers and sort spaces that can tune the database for performance http://www.mysqlperformanceblog.com/2006/06/09/why-mysql-could-be-slow-with-large-tables/ Also, what kind of hard ware are you using? Does the db server have oodles (yeah that techie term) of RAM? Have you looked into creating views for each state? If the db has a fairly static dataset (only adding not much updating) then you create those views so that you are then doing a single select against a pre-processed dataset. More tuning can be done by sharding the data across different diskdrives to aid i/o. A great book on mysql performance is High Peformance MySQL http://www.amazon.com/dp/0596101716?tag=xaprb-20 which is chockful of great options and info about gaining performance. -- Bastien Cat, the other other white meat -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php You can try nosql :) -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php You can try nosql :)
Re: [PHP-DB] Problem with mysql and php
Jim, Similar yes... But this was specifically about replacing distinct with something since it was taking WAY to long... But it did evolve into a very similar conversation :) Jason Pruim pru...@gmail.com On Nov 29, 2011, at 6:25 PM, Jim Giner wrote: Didn't the OP begin this very same subject a month ago? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with mysql and php
On 29/11/11 01:38, Jason Pruim li...@pruimphotography.com wrote:
Given the following 2 queries:
SELECT DISTINCT areacode FROM main WHERE state = '{$query_exploded[0]}';
SELECT DISTINCT areacode FROM main;
The second displays ALOT faster Like by minutes... the first one is what I
really want though Currently working with a dataset of 89 million records,
will be expanding that to many many more times that... To the tune of possibly
a couple billion records...
Any ideas? :)
PostgreSQL?
;-)...
Cheers,
Phil...
--
Nothing to see here... move along, move along
--
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Re: [PHP-DB] Problem with mysql and php
Jason Pruim
pru...@gmail.com
On Nov 28, 2011, at 8:58 PM, Phil Dobbin wrote:
On 29/11/11 01:38, Jason Pruim li...@pruimphotography.com wrote:
Given the following 2 queries:
SELECT DISTINCT areacode FROM main WHERE state = '{$query_exploded[0]}';
SELECT DISTINCT areacode FROM main;
The second displays ALOT faster Like by minutes... the first one is what
I
really want though Currently working with a dataset of 89 million
records,
will be expanding that to many many more times that... To the tune of
possibly
a couple billion records...
Any ideas? :)
PostgreSQL?
;-)...
In all seriousness... Would it help or change it in anyway? :)
I am free to use what I want (I believe) on this project...
--
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Re: [PHP-DB] Problem with mysql and php
On 29/11/11 02:08, Jason Pruim pru...@gmail.com wrote: PostgreSQL? ;-)... In all seriousness... Would it help or change it in anyway? :) I am free to use what I want (I believe) on this project... It's well worth looking into. Postgres can handle far bigger db's much quicker than MySQL but the downside is that it's a very steep learning curve after coming from mysql. It's relatively easy to install there are the drivers of course for PHP but it'll take up a lot of your time to learn it to the extent of being confident with it in my experience. Good luck, Cheers, Phil... -- Nothing to see here... move along, move along -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with mysql and php
On Mon, Nov 28, 2011 at 9:19 PM, Phil Dobbin phildob...@gmail.com wrote: On 29/11/11 02:08, Jason Pruim pru...@gmail.com wrote: PostgreSQL? ;-)... In all seriousness... Would it help or change it in anyway? :) I am free to use what I want (I believe) on this project... It's well worth looking into. Postgres can handle far bigger db's much quicker than MySQL but the downside is that it's a very steep learning curve after coming from mysql. It's relatively easy to install there are the drivers of course for PHP but it'll take up a lot of your time to learn it to the extent of being confident with it in my experience. Good luck, Cheers, Phil... -- Nothing to see here... move along, move along -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php jason, Assuming you have indexes on the data properly, have you looked into the mysql settings to ensure that you have the ones for large or xl datasets? There are a number of settings for buffers and sort spaces that can tune the database for performance http://www.mysqlperformanceblog.com/2006/06/09/why-mysql-could-be-slow-with-large-tables/ Also, what kind of hard ware are you using? Does the db server have oodles (yeah that techie term) of RAM? Have you looked into creating views for each state? If the db has a fairly static dataset (only adding not much updating) then you create those views so that you are then doing a single select against a pre-processed dataset. More tuning can be done by sharding the data across different diskdrives to aid i/o. A great book on mysql performance is High Peformance MySQL http://www.amazon.com/dp/0596101716?tag=xaprb-20 which is chockful of great options and info about gaining performance. -- Bastien Cat, the other other white meat -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with mysql and php
Le 2011-11-28 à 22:38, Bastien Koert phps...@gmail.com a écrit : On Mon, Nov 28, 2011 at 9:19 PM, Phil Dobbin phildob...@gmail.com wrote: On 29/11/11 02:08, Jason Pruim pru...@gmail.com wrote: PostgreSQL? ;-)... In all seriousness... Would it help or change it in anyway? :) I am free to use what I want (I believe) on this project... It's well worth looking into. Postgres can handle far bigger db's much quicker than MySQL but the downside is that it's a very steep learning curve after coming from mysql. It's relatively easy to install there are the drivers of course for PHP but it'll take up a lot of your time to learn it to the extent of being confident with it in my experience. Good luck, Cheers, Phil... -- Nothing to see here... move along, move along -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php jason, Assuming you have indexes on the data properly, have you looked into the mysql settings to ensure that you have the ones for large or xl datasets? There are a number of settings for buffers and sort spaces that can tune the database for performance http://www.mysqlperformanceblog.com/2006/06/09/why-mysql-could-be-slow-with-large-tables/ Also, what kind of hard ware are you using? Does the db server have oodles (yeah that techie term) of RAM? Have you looked into creating views for each state? If the db has a fairly static dataset (only adding not much updating) then you create those views so that you are then doing a single select against a pre-processed dataset. More tuning can be done by sharding the data across different diskdrives to aid i/o. A great book on mysql performance is High Peformance MySQL http://www.amazon.com/dp/0596101716?tag=xaprb-20 which is chockful of great options and info about gaining performance. -- Bastien Cat, the other other white meat -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php You can try nosql :) -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] problem in connecting to mysql from php
Hello everyone,
I am in the process of learning php and I was trying to connect to a mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
You should NOT need to move the .dll at all. There is a
setting in the ini which tells PHP where to look for extensions and that
should have pointed to the original location. Hence, removing the
semicolon should be the only part necessary.
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
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Re: [PHP-DB] problem in connecting to mysql from php
create a file with phpinfo() and make sure mysqli is listed in the loaded
modules
On Tue, Jun 14, 2011 at 12:07 PM, Niel Archer n...@chance.now wrote:
Hello everyone,
I am in the process of learning php and I was trying to connect to a
mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
You should NOT need to move the .dll at all. There is a
setting in the ini which tells PHP where to look for extensions and that
should have pointed to the original location. Hence, removing the
semicolon should be the only part necessary.
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
--
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Re: [PHP-DB] problem in connecting to mysql from php
Okay. I tried using that too. If I run this:
?php
$link = mysql_connect('localhost', 'root',
'Password123');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully';
mysql_close($link);
?
I get the error: *Fatal error*: Call to undefined function mysql_connect()
in *C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on
line *2
*I think there is something wrong with my configuration.
On Mon, Jun 13, 2011 at 6:00 PM, mrfroasty mrfroa...@gmail.com wrote:
Your error message is about class not found.That means there is no class
named MySQLi.Please use a textbook with online manual
http://www.php.net/manual/en/ref.mysql.php
On 06/13/2011 02:08 PM, C0mf0rtably Numb wrote:
Hello everyone,
I am in the process of learning php and I was trying to connect to a
mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
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Re: [PHP-DB] problem in connecting to mysql from php
On 13 June 2011 13:26, C0mf0rtably Numb 08.kus...@gmail.com wrote:
Okay. I tried using that too. If I run this:
?php
$link = mysql_connect('localhost', 'root',
'Password123');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully';
mysql_close($link);
?
I get the error: *Fatal error*: Call to undefined function mysql_connect()
in *C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on
line *2
*I think there is something wrong with my configuration.
On Mon, Jun 13, 2011 at 6:00 PM, mrfroasty mrfroa...@gmail.com wrote:
Your error message is about class not found.That means there is no class
named MySQLi.Please use a textbook with online manual
http://www.php.net/manual/en/ref.mysql.php
On 06/13/2011 02:08 PM, C0mf0rtably Numb wrote:
Hello everyone,
I am in the process of learning php and I was trying to connect to a
mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
--
Extra details:
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profile:x86
Hardware:msi geforce 8600GT asus p5k-se
location:/home/muhsin
language(s):C/C++,PHP,SQL,HTML
Typo:40WPM
url:http://www.mzalendo.net
url:http://www.zanbytes.com
Copying the files to windows\system ... what files? Where were you
told to do this?
Normally the extension files you need for PHP are in C:\PHP5\ext (or PHPx).
I've never copied a single file into my Windows folder for PHP.
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Re: [PHP-DB] Problem with pg_prepare - PostgresSQL
Giancarlo Boaron wrote: Hi all. I'm receiving the following message when I try to use pg_prepare() function: Call to undefined function pg_prepare(). My application works very well with others pg_* commands... What version of php do you have? This came in with 5.1.0 according to the manual. -- Postgresql php tutorials http://www.designmagick.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with PDO Mysql and FETCH::ASSOC
Hello, I am using the following code to perform queries on a MySQL database: $dbh = new PDO($GLOBALS['database'],$GLOBALS['username'],$GLOBALS['password']); $dbh-setAttribute(PDO::ATTR_EMULATE_PREPARES, true); $dbh-setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $query = $dbh-prepare(SELECT * FROM log); $query-execute(); $results = $query-fetchALL(PDO::FETCH_ASSOC); $dbh = null; If I perform this query in MySQL, I get: mysql select * from log; +-++---+--+++ | type| date | client_id | model_id | request| message| +-++---+--+++ | message | 1.2375e+09 | domain.18052 | | client_start | started client | However, if I perform this query with the PHP code above, I get: Array ( [type] = error [date] = 1.2375e+09 [log] = [distributed] = client_start [def] = started client) ) which is clearly wrong. 'distributed' is actually the name of the database, so I don't really know what it is doing as a key in the above result. If I use PDO::FETCH_BOTH instead of PDO::FETCH_ASSOC, I get Array ( [type] = message [0] = message [date] = 1.2375e+09 [1] = 1.2375e+09 [log] = [2] = domain.18052 [3] = [distributed] = client_start [4] = client_start [def] = started client [5] = started client ) which *does* contain the correct values with the numerical keys. Before using MySQL, I was using SQLite, and this problem did not occur. The description of the table is: mysql describe log; +---+--+--+-+-+---+ | Field | Type | Null | Key | Default | Extra | +---+--+--+-+-+---+ | type | char(10) | YES | | NULL| | | date | float| YES | | NULL| | | client_id | char(50) | YES | | NULL| | | model_id | char(50) | YES | | NULL| | | request | char(20) | YES | | NULL| | | message | char(50) | YES | | NULL| | +---+--+--+-+-+---+ 6 rows in set (0.00 sec) Does anyone have any ideas as to what I might be doing wrong? Thanks for any help! Thomas First of all check if you are actually connecting to the same database both times. Start with printing $GLOBALS['database'] and see if it connects where you really want. You mentioned a field def while printing the query's output which obviously is not included in the table's description. Have you changed the schema in the meantime? -- Thodoris -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with PDO Mysql and FETCH::ASSOC
Does anyone have any ideas as to what I might be doing wrong? Thanks for any help! Thomas First of all check if you are actually connecting to the same database both times. Start with printing $GLOBALS['database'] and see if it connects where you really want. You mentioned a field def while printing the query's output which obviously is not included in the table's description. Have you changed the schema in the meantime? Thanks for your suggestions. I've managed to fix the issue by switching to a 32-bit installation of MySQL and Apache. The problem appeared to be due to the 64-bit versions somehow. Thomas -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with PDO Mysql and FETCH::ASSOC
Thomas Robitaille wrote: I've managed to fix the issue by switching to a 32-bit installation of MySQL and Apache. The problem appeared to be due to the 64-bit versions somehow. If you think there's a bug (and you tested the latest version of PHP), please report the problem at http://bugs.php.net/ Chris -- Email: christopher.jo...@oracle.com Tel: +1 650 506 8630 Twitter: http://twitter.com/ghrdFree PHP Book: http://tinyurl.com/UGPOM -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with PDO exceptions
I think it is a bug. I have seen this happening at work (PDO not
throwing exception when executing a query on a non existing table)
News on iPhone: http://trk7.com/mob
On 08/03/2009, at 6:44 AM, Daniel Carrera
daniel.carr...@theingots.org wrote:
Hello,
I have MySQL 5.1 and PHP 5.2. For some reason PDO is not throwing
exceptions when I give it a broken SQL query. For example:
try {
$stmt = $db-prepare(SELECT * FROM foobar WHERE 1);
} catch(PDOException $e) {
error($e-getMessage());
}
In this example there is no table called 'foobar', so this should
give an error. Yet, it doesn't.
Any ideas why that would happen? Possible causes I can think of:
1) PDO decide to emulate prepared statements.
2) PDO has some sort of errors off setting.
3) My try-catch statement is wrong.
I doubt it's (1) because I have MySQL 5.1 and PDO is only supposed
to emulate prepared statements for MySQL versions prior to 4.1. And
phpinfo says that I'm running pdo_mysql version 5.1.30.
Btw, $db-exec() and $db-query() also fail to produce an error when
I give them a broken query. That's another reason why I think that
the problem is elsewhere.
Any ideas?
Thank you very much for your help.
Best,
Daniel.
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Re: [PHP-DB] Problem with PDO exceptions
Hi, Did you set the value of the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION|? Btw, I don't think ||prepare would throw an exception even for a malformed query, but ||execute definitely should. Regards, Z
Re: [PHP-DB] Problem with PDO exceptions
yup, I have set the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION| and I am still not getting an exception! My Code is something like this: $query = $db-prepare($sql); $query-execute($bind); $row = $query-fetch(PDO::FETCH_ASSOC); wher $db is the PDO obj and $sql is the sql query and $bind is the bound parameter On Sun, Mar 8, 2009 at 5:35 PM, Zoltan Ormandi ormandi.zol...@webfunteam.hu wrote: Hi, Did you set the value of the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION|? Btw, I don't think ||prepare would throw an exception even for a malformed query, but ||execute definitely should. Regards, Z
Re: [PHP-DB] Problem with PDO exceptions
I am sorry, setting |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION| *does* throw an Exception when the table cannot be found. Stupid me; I was trying to catch Exception rather than a PDOException. On Sun, Mar 8, 2009 at 6:03 PM, kesavan trichy rengarajan k...@trk7.comwrote: yup, I have set the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION| and I am still not getting an exception! My Code is something like this: $query = $db-prepare($sql); $query-execute($bind); $row = $query-fetch(PDO::FETCH_ASSOC); wher $db is the PDO obj and $sql is the sql query and $bind is the bound parameter On Sun, Mar 8, 2009 at 5:35 PM, Zoltan Ormandi ormandi.zol...@webfunteam.hu wrote: Hi, Did you set the value of the |PDO::ATTR_ERRMODE| attribute to |PDO::ERRMODE_EXCEPTION|? Btw, I don't think ||prepare would throw an exception even for a malformed query, but ||execute definitely should. Regards, Z
Re: [PHP-DB] Problem after moving servers
$list-render( $db, $start, COUNT ); Send the code of this function and tell me the value of COUNT. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem after moving servers
Can you send over the function ProfileList::render? And you should make sure that whenever the render() function of one of ProfileList's subclasses is called, the value of $count is 30... It seems the most likely source of your problem to me. To check the value of $count you can do and echo $count; or var_dump($count); in the ProfileList::render() function. Make sure to always include the list in your replies. This way people can reuse solutions from the archives. Evert On Sun, Aug 31, 2008 at 11:21 AM, Gav [EMAIL PROTECTED] wrote: Hi All, I moved a site across from one server to another, and now there is one thing no longer working properly that worked fine on the other. It may turn out to be a PHP4 to PHP5 problem, dont know as I cant access now what the other server had. Certain pages on the website were able to render a list of 30 items, since the move it now only renders the first item only. I'm sure you want some code, but before I give that can we determine if I'm on the right list - the function does pull items from a database so it is sort of related, though I'm not sure it is a db problem. In the php output page we have $list-render( $db, $start, COUNT ); Not sure if that is a clue or not, anyway let me know if you me to post all the related classes and functions. Cheers Gav... -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem after moving servers
On Sun, Aug 31, 2008 at 8:09 PM, Evert Lammerts [EMAIL PROTECTED]wrote:
Can you send over the function ProfileList::render? And you should
make sure that whenever the render() function of one of ProfileList's
subclasses is called, the value of $count is 30... It seems the most
likely source of your problem to me. To check the value of $count you
can do and echo $count; or var_dump($count); in the
ProfileList::render() function.
Hmm, I'm no guru but I thought it may have been some incompatibility I'd
need to change so it worked on a newer PHP than was on the old server. This
code has remained unchanged and working perfect for at least 3 years that I
know of. I never changed a single byte of it when moving servers except the
new db connection parameters.
COUNT and $count look like they have different roles to me, COUNT is the
amount of designers to be listed per page, $count is the number of designers
to be listed altogether, so 150 designers would give me 5 pages of 30
designers.
Anyway, I did not write the code and I don't pretend to understand all of
it, so I'm including most of the file here so you can pick what you need :)
Note that that RegionSelector() and SpecSelector() work fine.
And that AllProfiles() , ProfilesByRegion() and ProfilesBySpec() are the
ones that now do not work any more - these three that do not work are part
of the ProfileList Class, so I thought it would be something in this class
as they are all common to it. I had also read the the re-use of $this had
changed in PHP5.2+ but I can not work out if this (npi) would apply in this
case.
Make sure to always include the list in your replies. This way people
can reuse solutions from the archives.
Sorry about that, most lists I'm subscribed to have reply-all set
automatically.
Here the code :-
// Number of designers to display per page on the list.php page.
define( COUNT, 30 );
// Makes DB present for ALL client scripts / pages.
// This is a global scope variable. To minimize memory
// usage the $db variable is passed by reference, and not
// copyied for each function or object.
$db = new db( DBUSER, DBPASS, DBNAME );
// The RegionMultiSelector class creates the form conponent
// responsible for the input of the designers regions.
// Appears on the Get Listed page.
class RegionMultiSelector
{
var $html;
function RegionMultiSelector( $db )
{
// Create query to get all regions in regions database table.
$q = SELECT id, name FROM regions;
// Run the query on the database.
$db-runquery( $q );
// Start collecting HTML.
$h = select .BC. name=\regions[]\ multiple=\multiple\
size=\7\\n;
// For each row in the results print the region
while( $row = $db-getrow() )
{
$h.=\t\toption value=\$row-name\$row-name/option\n;
}
$h.=/select\n;
$this-html = $h;
}
function render()
{
print $this-html;
}
}
// The RegionSelector is a drop down list for selecting singular
// regions. For purposes of filtering lists etc.
class RegionSelector extends DropNav
{
function RegionSelector( $db )
{
$q = SELECT id, name FROM regions;
$db-runquery( $q );
$this-addItem( , Please select... );
while( $row = $db-getrow() )
{
$this-addItem( $PHP_SELF.?region=.$row-id, $row-name );
}
}
function renderBody()
{
print h5 .BBC.Select developers based on region./h5;
print div .BC.;
DropNav::renderBody();
print /div;
}
}
// The SpecSelector is a drop down list for selecting singular
// specialities. For purposes of filtering lists etc.
class SpecSelector extends DropNav
{
function SpecSelector( $db )
{
$q = SELECT id, name FROM specialities;
$db-runquery( $q );
$this-addItem( , Please select... );
while( $row = $db-getrow() )
{
$this-addItem( $PHP_SELF.?spec=.$row-id, $row-name );
}
}
function renderBody()
{
print h5 .BBC.Select developers based on Speciality./h5;
print div .BC.;
DropNav::renderBody();
print /div;
}
}
// The Profile List is the base class for all Profile lists.
// Subclasses must at least define the query
class ProfileList
{
var $query;
var $des;
var $lastcount;
// Render the Brief HomePage list
// $db is a reference to the database object created for the page.
function render( $db, $start=0, $count=1024 )
{
if ( ( $this-query== ) or ( ! $this-query ))
print pHey, you! You forgot to define a query in my subclass:
Yours iProfileList/i/p;
$q = $this-query;
$q = $q. LIMIT $start, $count ;
// print h1Query: $q/h1;
$db-runquery( $q );
$this-lastcount = $db-numrows;
if ( $db-numrows 0 )
{
$this-setView();
// Loop through each designer in the
Re: [PHP-DB] Problem after moving servers
The code you've sent seems to be fine, and if I check your website it does everything it should do in terms of filtering - if I select Tayside as a region I get a development company with the region set to Tayside. It seems to me that this means the problem is not in one of the subclasses of ProfileList, so not a compatibility issue on that level ($this-query works fine). while( $row = $db-getrow() ) seems to stop after one loop. This is either because there are no more results - the query is limited to 1, so $count=1 - or because $db-getRow generates an error. COUNT and $count look like they have different roles to me, COUNT is the amount of designers to be listed per page, $count is the number of designers to be listed altogether, so 150 designers would give me 5 pages of 30 designers. In ProfileList::render the query is appended with LIMIT $start, $count, and the results of the query all seem to be rendered. This probably means that $count and COUNT should have the same value - 30 - and that the render function is initially called with the global variable COUNT as parameter. To check what goes wrong you first need to set error_reporting to E_ALL in php.ini and restart your webserver, or add the line error_reporting(E_ALL); at the beginning of you code. After that you need to print the query from ProfileList::render. Can you adjust the function and add var_dump($q); after the line $q = $q. LIMIT $start, $count ;? Evert -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem after moving servers
You don't need to print the query anymore - I already did that. You need to change your code because right now it is open for SQL injection attacks: I added some SQL to the url and generated an SQL error (http://www.iwdp.co.uk/list.php?region=1start=30,2). When you retrieve start, e.g. $_GET['start'], do a check to make sure the value is an integer. The good news is that the query looks fine: SELECT d.id AS id FROM designers d, designer_regions dr WHERE dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC LIMIT 0, 30; Can you run this query directly on the database and see what the result is? Also check if you get an error after setting error_reporting to E_ALL. On Sun, Aug 31, 2008 at 1:16 PM, Evert Lammerts [EMAIL PROTECTED] wrote: The code you've sent seems to be fine, and if I check your website it does everything it should do in terms of filtering - if I select Tayside as a region I get a development company with the region set to Tayside. It seems to me that this means the problem is not in one of the subclasses of ProfileList, so not a compatibility issue on that level ($this-query works fine). while( $row = $db-getrow() ) seems to stop after one loop. This is either because there are no more results - the query is limited to 1, so $count=1 - or because $db-getRow generates an error. COUNT and $count look like they have different roles to me, COUNT is the amount of designers to be listed per page, $count is the number of designers to be listed altogether, so 150 designers would give me 5 pages of 30 designers. In ProfileList::render the query is appended with LIMIT $start, $count, and the results of the query all seem to be rendered. This probably means that $count and COUNT should have the same value - 30 - and that the render function is initially called with the global variable COUNT as parameter. To check what goes wrong you first need to set error_reporting to E_ALL in php.ini and restart your webserver, or add the line error_reporting(E_ALL); at the beginning of you code. After that you need to print the query from ProfileList::render. Can you adjust the function and add var_dump($q); after the line $q = $q. LIMIT $start, $count ;? Evert -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem after moving servers
On Sun, Aug 31, 2008 at 9:27 PM, Evert Lammerts [EMAIL PROTECTED]wrote:
You don't need to print the query anymore - I already did that. You
need to change your code because right now it is open for SQL
injection attacks: I added some SQL to the url and generated an SQL
error (http://www.iwdp.co.uk/list.php?region=1start=30,2). When you
retrieve start, e.g. $_GET['start'], do a check to make sure the value
is an integer.
The good news is that the query looks fine:
SELECT d.id AS id FROM designers d, designer_regions dr WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC
LIMIT 0, 30;
Can you run this query directly on the database and see what the result is?
*SQL query:* SELECT d.id AS id FROM designers d, designer_regions dr WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC LIMIT
0, 30;
*Rows:* 30 id 2 4 5 11 43 63 86 99 117 119 158 165 233 272
290 305 328 335 363 396 414 425 430 436 459 489 490 518 536
554
Also check if you get an error after setting error_reporting to E_ALL.
Yup, I left it up there at http://www.iwdp.co.uk/list.php
The PHP_SELF being referred to as undefined is in the included file
generic.php :-
class DropNav
{
var $items =array();
var $head;
var $body;
// CONSTRUCTOR
function DropNav()
{
}
// PUBLIC
function renderHead()
{
$this-buildHTML();
print $this-head;
}
// PUBLIC
function renderBody()
{
$this-buildHTML();
print $this-body;
}
// PUBLIC
function addItem( $url, $desc )
{
$this-items[] = array( url = $url, desc=$desc );
}
// PRIVATE
function buildHTML()
{
global $PHP_SELF;
$this-body = form action=\$PHP_SELF\\n;
$this-body .= \tpselect name=\newLocation\
onchange=\jumpPage(this.form.newLocation)\\n;
foreach ( $this-items as $item )
{
$this-body .=\t\toption value=\.$item[url].\;
$this-body .= $item[desc];
$this-body .=/option\n;
}
$this-body .= \t/select/p\n/form\n;
$this-head = script type=\text/javascript\\n;
$this-head .= !--
function jumpPage( newLoc )
{
newPage = newLoc.options[newLoc.selectedIndex].value;
if ( newPage != \\ )
{
window.location.href=newPage;
}
} // --\n;
$this-head .= /script\n\n;
}
}
Thanks
Gav...
On Sun, Aug 31, 2008 at 1:16 PM, Evert Lammerts
[EMAIL PROTECTED] wrote:
The code you've sent seems to be fine, and if I check your website it
does everything it should do in terms of filtering - if I select
Tayside as a region I get a development company with the region set to
Tayside. It seems to me that this means the problem is not in one of
the subclasses of ProfileList, so not a compatibility issue on that
level ($this-query works fine).
while( $row = $db-getrow() )
seems to stop after one loop. This is either because there are no more
results - the query is limited to 1, so $count=1 - or because
$db-getRow generates an error.
COUNT and $count look like they have different roles to me, COUNT is the
amount of
designers to be listed per page, $count is the number of designers to be
listed altogether,
so 150 designers would give me 5 pages of 30 designers.
In ProfileList::render the query is appended with LIMIT $start,
$count, and the results of the query all seem to be rendered. This
probably means that $count and COUNT should have the same value - 30 -
and that the render function is initially called with the global
variable COUNT as parameter.
To check what goes wrong you first need to set error_reporting to
E_ALL in php.ini and restart your webserver, or add the line
error_reporting(E_ALL); at the beginning of you code. After that you
need to print the query from ProfileList::render. Can you adjust the
function and add var_dump($q); after the line $q = $q. LIMIT $start,
$count ;?
Evert
--
Gav...
[LinkedIn : http://www.linkedin.com/in/ipv6guru]
www.16degrees.com.au | www.iwdp.co.uk | www.minitutorials.com
(Sponsorship slots available on above three sites!)
Re: [PHP-DB] Problem after moving servers
Just copying the error messages here so I can revert my changes on the site.
*Notice*: Undefined variable: PHP_SELF in *
/var/virtual/web/w0019/html/profilemanager.php* on line *75*
*Notice*: Undefined variable: PHP_SELF in *
/var/virtual/web/w0019/html/profilemanager.php* on line *76
x 22 more times. Then I get :-
**Notice*: Use of undefined constant url - assumed 'url' in *
/var/virtual/web/w0019/html/generic.php* on line *289*
*Notice*: Use of undefined constant desc - assumed 'desc' in *
/var/virtual/web/w0019/html/generic.php* on line *290
x many more times.
Then the result of the var_dump($q);
*string(66) SELECT id FROM designers WHERE view=1 ORDER BY id ASC LIMIT 0,
30
HTH
I am still looking at it myself, but going round in circles, so thanks for
your help.
Gav...
On Sun, Aug 31, 2008 at 10:15 PM, Gav [EMAIL PROTECTED] wrote:
On Sun, Aug 31, 2008 at 9:27 PM, Evert Lammerts [EMAIL PROTECTED]wrote:
You don't need to print the query anymore - I already did that. You
need to change your code because right now it is open for SQL
injection attacks: I added some SQL to the url and generated an SQL
error (http://www.iwdp.co.uk/list.php?region=1start=30,2). When you
retrieve start, e.g. $_GET['start'], do a check to make sure the value
is an integer.
The good news is that the query looks fine:
SELECT d.id AS id FROM designers d, designer_regions dr WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC
LIMIT 0, 30;
Can you run this query directly on the database and see what the result
is?
*SQL query:* SELECT d.id AS id FROM designers d, designer_regions dr WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC
LIMIT 0, 30;
*Rows:* 30 id 2 4 5 11 43 63 86 99 117 119 158 165 233 272
290 305 328 335 363 396 414 425 430 436 459 489 490 518 536
554
Also check if you get an error after setting error_reporting to E_ALL.
Yup, I left it up there at http://www.iwdp.co.uk/list.php
The PHP_SELF being referred to as undefined is in the included file
generic.php :-
class DropNav
{
var $items =array();
var $head;
var $body;
// CONSTRUCTOR
function DropNav()
{
}
// PUBLIC
function renderHead()
{
$this-buildHTML();
print $this-head;
}
// PUBLIC
function renderBody()
{
$this-buildHTML();
print $this-body;
}
// PUBLIC
function addItem( $url, $desc )
{
$this-items[] = array( url = $url, desc=$desc );
}
// PRIVATE
function buildHTML()
{
global $PHP_SELF;
$this-body = form action=\$PHP_SELF\\n;
$this-body .= \tpselect name=\newLocation\
onchange=\jumpPage(this.form.newLocation)\\n;
foreach ( $this-items as $item )
{
$this-body .=\t\toption value=\.$item[url].\;
$this-body .= $item[desc];
$this-body .=/option\n;
}
$this-body .= \t/select/p\n/form\n;
$this-head = script type=\text/javascript\\n;
$this-head .= !--
function jumpPage( newLoc )
{
newPage = newLoc.options[newLoc.selectedIndex].value;
if ( newPage != \\ )
{
window.location.href=newPage;
}
} // --\n;
$this-head .= /script\n\n;
}
}
Thanks
Gav...
On Sun, Aug 31, 2008 at 1:16 PM, Evert Lammerts
[EMAIL PROTECTED] wrote:
The code you've sent seems to be fine, and if I check your website it
does everything it should do in terms of filtering - if I select
Tayside as a region I get a development company with the region set to
Tayside. It seems to me that this means the problem is not in one of
the subclasses of ProfileList, so not a compatibility issue on that
level ($this-query works fine).
while( $row = $db-getrow() )
seems to stop after one loop. This is either because there are no more
results - the query is limited to 1, so $count=1 - or because
$db-getRow generates an error.
COUNT and $count look like they have different roles to me, COUNT is
the amount of
designers to be listed per page, $count is the number of designers to
be listed altogether,
so 150 designers would give me 5 pages of 30 designers.
In ProfileList::render the query is appended with LIMIT $start,
$count, and the results of the query all seem to be rendered. This
probably means that $count and COUNT should have the same value - 30 -
and that the render function is initially called with the global
variable COUNT as parameter.
To check what goes wrong you first need to set error_reporting to
E_ALL in php.ini and restart your webserver, or add the line
error_reporting(E_ALL); at the beginning of you code. After that you
need to print the query from ProfileList::render. Can you adjust the
function and add var_dump($q); after the line
Re: [PHP-DB] Problem after moving servers
In PHP5 register_globals defaults to off. You can either switch it
back on through your php.ini and restart your webserver, or change all
PHP_SELF references to $_SERVER['PHP_SELF']. See if that fixes your
problem.
I hope you understood the SQL injection problem I pointed out. Anybody
can drop your database, so do fix it!
On 8/31/08, Gav [EMAIL PROTECTED] wrote:
On Sun, Aug 31, 2008 at 9:27 PM, Evert Lammerts
[EMAIL PROTECTED]wrote:
You don't need to print the query anymore - I already did that. You
need to change your code because right now it is open for SQL
injection attacks: I added some SQL to the url and generated an SQL
error (http://www.iwdp.co.uk/list.php?region=1start=30,2). When you
retrieve start, e.g. $_GET['start'], do a check to make sure the value
is an integer.
The good news is that the query looks fine:
SELECT d.id AS id FROM designers d, designer_regions dr WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC
LIMIT 0, 30;
Can you run this query directly on the database and see what the result
is?
*SQL query:* SELECT d.id AS id FROM designers d, designer_regions dr WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC LIMIT
0, 30;
*Rows:* 30 id 2 4 5 11 43 63 86 99 117 119 158 165 233 272
290 305 328 335 363 396 414 425 430 436 459 489 490 518 536
554
Also check if you get an error after setting error_reporting to E_ALL.
Yup, I left it up there at http://www.iwdp.co.uk/list.php
The PHP_SELF being referred to as undefined is in the included file
generic.php :-
class DropNav
{
var $items =array();
var $head;
var $body;
// CONSTRUCTOR
function DropNav()
{
}
// PUBLIC
function renderHead()
{
$this-buildHTML();
print $this-head;
}
// PUBLIC
function renderBody()
{
$this-buildHTML();
print $this-body;
}
// PUBLIC
function addItem( $url, $desc )
{
$this-items[] = array( url = $url, desc=$desc );
}
// PRIVATE
function buildHTML()
{
global $PHP_SELF;
$this-body = form action=\$PHP_SELF\\n;
$this-body .= \tpselect name=\newLocation\
onchange=\jumpPage(this.form.newLocation)\\n;
foreach ( $this-items as $item )
{
$this-body .=\t\toption value=\.$item[url].\;
$this-body .= $item[desc];
$this-body .=/option\n;
}
$this-body .= \t/select/p\n/form\n;
$this-head = script type=\text/javascript\\n;
$this-head .= !--
function jumpPage( newLoc )
{
newPage = newLoc.options[newLoc.selectedIndex].value;
if ( newPage != \\ )
{
window.location.href=newPage;
}
} // --\n;
$this-head .= /script\n\n;
}
}
Thanks
Gav...
On Sun, Aug 31, 2008 at 1:16 PM, Evert Lammerts
[EMAIL PROTECTED] wrote:
The code you've sent seems to be fine, and if I check your website it
does everything it should do in terms of filtering - if I select
Tayside as a region I get a development company with the region set to
Tayside. It seems to me that this means the problem is not in one of
the subclasses of ProfileList, so not a compatibility issue on that
level ($this-query works fine).
while( $row = $db-getrow() )
seems to stop after one loop. This is either because there are no more
results - the query is limited to 1, so $count=1 - or because
$db-getRow generates an error.
COUNT and $count look like they have different roles to me, COUNT is
the
amount of
designers to be listed per page, $count is the number of designers to
be
listed altogether,
so 150 designers would give me 5 pages of 30 designers.
In ProfileList::render the query is appended with LIMIT $start,
$count, and the results of the query all seem to be rendered. This
probably means that $count and COUNT should have the same value - 30 -
and that the render function is initially called with the global
variable COUNT as parameter.
To check what goes wrong you first need to set error_reporting to
E_ALL in php.ini and restart your webserver, or add the line
error_reporting(E_ALL); at the beginning of you code. After that you
need to print the query from ProfileList::render. Can you adjust the
function and add var_dump($q); after the line $q = $q. LIMIT $start,
$count ;?
Evert
--
Gav...
[LinkedIn : http://www.linkedin.com/in/ipv6guru]
www.16degrees.com.au | www.iwdp.co.uk | www.minitutorials.com
(Sponsorship slots available on above three sites!)
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem after moving servers
On Sun, Aug 31, 2008 at 10:36 PM, Evert Lammerts
[EMAIL PROTECTED]wrote:
In PHP5 register_globals defaults to off. You can either switch it
back on through your php.ini and restart your webserver, or change all
PHP_SELF references to $_SERVER['PHP_SELF']. See if that fixes your
problem.
I already have
php_admin_flag register_globals 1
in the VirtualHost config for that site, so it should be on already.
So I guess I'll try changing the references anyway jic.
I hope you understood the SQL injection problem I pointed out. Anybody
can drop your database, so do fix it!
Will do, thanks.
Gav...
On 8/31/08, Gav [EMAIL PROTECTED] wrote:
On Sun, Aug 31, 2008 at 9:27 PM, Evert Lammerts
[EMAIL PROTECTED]wrote:
You don't need to print the query anymore - I already did that. You
need to change your code because right now it is open for SQL
injection attacks: I added some SQL to the url and generated an SQL
error (http://www.iwdp.co.uk/list.php?region=1start=30,2). When you
retrieve start, e.g. $_GET['start'], do a check to make sure the value
is an integer.
The good news is that the query looks fine:
SELECT d.id AS id FROM designers d, designer_regions dr WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC
LIMIT 0, 30;
Can you run this query directly on the database and see what the result
is?
*SQL query:* SELECT d.id AS id FROM designers d, designer_regions dr
WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC
LIMIT
0, 30;
*Rows:* 30 id 2 4 5 11 43 63 86 99 117 119 158 165 233 272
290 305 328 335 363 396 414 425 430 436 459 489 490 518 536
554
Also check if you get an error after setting error_reporting to E_ALL.
Yup, I left it up there at http://www.iwdp.co.uk/list.php
The PHP_SELF being referred to as undefined is in the included file
generic.php :-
class DropNav
{
var $items =array();
var $head;
var $body;
// CONSTRUCTOR
function DropNav()
{
}
// PUBLIC
function renderHead()
{
$this-buildHTML();
print $this-head;
}
// PUBLIC
function renderBody()
{
$this-buildHTML();
print $this-body;
}
// PUBLIC
function addItem( $url, $desc )
{
$this-items[] = array( url = $url, desc=$desc );
}
// PRIVATE
function buildHTML()
{
global $PHP_SELF;
$this-body = form action=\$PHP_SELF\\n;
$this-body .= \tpselect name=\newLocation\
onchange=\jumpPage(this.form.newLocation)\\n;
foreach ( $this-items as $item )
{
$this-body .=\t\toption value=\.$item[url].\;
$this-body .= $item[desc];
$this-body .=/option\n;
}
$this-body .= \t/select/p\n/form\n;
$this-head = script type=\text/javascript\\n;
$this-head .= !--
function jumpPage( newLoc )
{
newPage = newLoc.options[newLoc.selectedIndex].value;
if ( newPage != \\ )
{
window.location.href=newPage;
}
} // --\n;
$this-head .= /script\n\n;
}
}
Thanks
Gav...
On Sun, Aug 31, 2008 at 1:16 PM, Evert Lammerts
[EMAIL PROTECTED] wrote:
The code you've sent seems to be fine, and if I check your website it
does everything it should do in terms of filtering - if I select
Tayside as a region I get a development company with the region set to
Tayside. It seems to me that this means the problem is not in one of
the subclasses of ProfileList, so not a compatibility issue on that
level ($this-query works fine).
while( $row = $db-getrow() )
seems to stop after one loop. This is either because there are no more
results - the query is limited to 1, so $count=1 - or because
$db-getRow generates an error.
COUNT and $count look like they have different roles to me, COUNT is
the
amount of
designers to be listed per page, $count is the number of designers to
be
listed altogether,
so 150 designers would give me 5 pages of 30 designers.
In ProfileList::render the query is appended with LIMIT $start,
$count, and the results of the query all seem to be rendered. This
probably means that $count and COUNT should have the same value - 30 -
and that the render function is initially called with the global
variable COUNT as parameter.
To check what goes wrong you first need to set error_reporting to
E_ALL in php.ini and restart your webserver, or add the line
error_reporting(E_ALL); at the beginning of you code. After that you
need to print the query from ProfileList::render. Can you adjust the
function and add var_dump($q); after the line $q = $q. LIMIT $start,
$count ;?
Evert
Re: [PHP-DB] Problem after moving servers
On Sun, Aug 31, 2008 at 10:45 PM, Gav [EMAIL PROTECTED] wrote:
On Sun, Aug 31, 2008 at 10:36 PM, Evert Lammerts [EMAIL PROTECTED]
wrote:
In PHP5 register_globals defaults to off. You can either switch it
back on through your php.ini and restart your webserver, or change all
PHP_SELF references to $_SERVER['PHP_SELF']. See if that fixes your
problem.
I already have
php_admin_flag register_globals 1
in the VirtualHost config for that site, so it should be on already.
So I guess I'll try changing the references anyway jic.
Well, with E_ALL still on I have cleared all errors now so no more errors on
screen.
However, problem persists, still looking but its now 3am so I should just
try again later.
Gav...
I hope you understood the SQL injection problem I pointed out. Anybody
can drop your database, so do fix it!
Will do, thanks.
Gav...
On 8/31/08, Gav [EMAIL PROTECTED] wrote:
On Sun, Aug 31, 2008 at 9:27 PM, Evert Lammerts
[EMAIL PROTECTED]wrote:
You don't need to print the query anymore - I already did that. You
need to change your code because right now it is open for SQL
injection attacks: I added some SQL to the url and generated an SQL
error (http://www.iwdp.co.uk/list.php?region=1start=30,2). When you
retrieve start, e.g. $_GET['start'], do a check to make sure the value
is an integer.
The good news is that the query looks fine:
SELECT d.id AS id FROM designers d, designer_regions dr WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC
LIMIT 0, 30;
Can you run this query directly on the database and see what the result
is?
*SQL query:* SELECT d.id AS id FROM designers d, designer_regions dr
WHERE
dr.region_id=1 AND dr.designer_id=d.id AND d.view=1 ORDER BY d.id ASC
LIMIT
0, 30;
*Rows:* 30 id 2 4 5 11 43 63 86 99 117 119 158 165 233
272
290 305 328 335 363 396 414 425 430 436 459 489 490 518
536
554
Also check if you get an error after setting error_reporting to E_ALL.
Yup, I left it up there at http://www.iwdp.co.uk/list.php
The PHP_SELF being referred to as undefined is in the included file
generic.php :-
class DropNav
{
var $items =array();
var $head;
var $body;
// CONSTRUCTOR
function DropNav()
{
}
// PUBLIC
function renderHead()
{
$this-buildHTML();
print $this-head;
}
// PUBLIC
function renderBody()
{
$this-buildHTML();
print $this-body;
}
// PUBLIC
function addItem( $url, $desc )
{
$this-items[] = array( url = $url, desc=$desc );
}
// PRIVATE
function buildHTML()
{
global $PHP_SELF;
$this-body = form action=\$PHP_SELF\\n;
$this-body .= \tpselect name=\newLocation\
onchange=\jumpPage(this.form.newLocation)\\n;
foreach ( $this-items as $item )
{
$this-body .=\t\toption value=\.$item[url].\;
$this-body .= $item[desc];
$this-body .=/option\n;
}
$this-body .= \t/select/p\n/form\n;
$this-head = script type=\text/javascript\\n;
$this-head .= !--
function jumpPage( newLoc )
{
newPage = newLoc.options[newLoc.selectedIndex].value;
if ( newPage != \\ )
{
window.location.href=newPage;
}
} // --\n;
$this-head .= /script\n\n;
}
}
Thanks
Gav...
On Sun, Aug 31, 2008 at 1:16 PM, Evert Lammerts
[EMAIL PROTECTED] wrote:
The code you've sent seems to be fine, and if I check your website it
does everything it should do in terms of filtering - if I select
Tayside as a region I get a development company with the region set
to
Tayside. It seems to me that this means the problem is not in one of
the subclasses of ProfileList, so not a compatibility issue on that
level ($this-query works fine).
while( $row = $db-getrow() )
seems to stop after one loop. This is either because there are no
more
results - the query is limited to 1, so $count=1 - or because
$db-getRow generates an error.
COUNT and $count look like they have different roles to me, COUNT is
the
amount of
designers to be listed per page, $count is the number of designers
to
be
listed altogether,
so 150 designers would give me 5 pages of 30 designers.
In ProfileList::render the query is appended with LIMIT $start,
$count, and the results of the query all seem to be rendered. This
probably means that $count and COUNT should have the same value - 30
-
and that the render function is initially called with the global
variable COUNT as parameter.
To check what goes wrong you first need to set error_reporting to
E_ALL in php.ini and restart your
Re: [PHP-DB] Problem after moving servers
I'm pretty sure I found the problem - I should've spotted it earlier.
The function ProfileList::render gets a reference to the $db object by
its parameter $db. While you loop over your results, you pass the
reference on to $this-des-load. I'm guessing that the definition of
$this-des-load is something like function load($id, $db);, in which
case it's not getting a reference to the $db object but an actual copy
in PHP4. Since PHP 5 there is a new object model that makes sure that
any variable that holds an object is actually just a handle to the
object - so whenever you pass it to a function you use it as a
reference instead of a copy.
To make it clear:
class test {
var $a = 1;
function aa() {
$this-a++;
}
}
$c = new test();
$d = $c;
$c-aa();
$d-aa();
var_dump ($c);
results in:
object(test)#1 (1) { [a]= int(3) }
This means you should first change the function definitions to not use
references for objects, so take away the at every $db parameter.
Second you need to create a new $db object for your $this-des-load
function before the while loop in ProfileList::render. I think the
safest option is to do something like $db2 = new Db(...). You can also
use the keyword clone to clone an object, but i'm not sure what this
does with your internal DB handle you could try and see what
happens. Just add $db2 = clone $db; right before the while loop. Call
$this-des-load with $db2 instead of $db.
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To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem after moving servers
On Mon, Sep 1, 2008 at 9:23 AM, Evert Lammerts [EMAIL PROTECTED]wrote:
I'm pretty sure I found the problem - I should've spotted it earlier.
The function ProfileList::render gets a reference to the $db object by
its parameter $db. While you loop over your results, you pass the
reference on to $this-des-load. I'm guessing that the definition of
$this-des-load is something like function load($id, $db);, in which
case it's not getting a reference to the $db object but an actual copy
in PHP4. Since PHP 5 there is a new object model that makes sure that
any variable that holds an object is actually just a handle to the
object - so whenever you pass it to a function you use it as a
reference instead of a copy.
To make it clear:
class test {
var $a = 1;
function aa() {
$this-a++;
}
}
$c = new test();
$d = $c;
$c-aa();
$d-aa();
var_dump ($c);
results in:
object(test)#1 (1) { [a]= int(3) }
This means you should first change the function definitions to not use
references for objects, so take away the at every $db parameter.
Second you need to create a new $db object for your $this-des-load
function before the while loop in ProfileList::render. I think the
safest option is to do something like $db2 = new Db(...). You can also
use the keyword clone to clone an object, but i'm not sure what this
does with your internal DB handle you could try and see what
happens. Just add $db2 = clone $db; right before the while loop. Call
$this-des-load with $db2 instead of $db.
aha, excellent explanation , and $db2 = clone$db; worked fine!
I was reading my way round php.net and getting closer I think, your
explanation and probably saved my a few days , so thanks.
--
Gav...
Re: [PHP-DB] Problem after moving servers
On Mon, Sep 1, 2008 at 10:10 AM, Gav [EMAIL PROTECTED] wrote:
On Mon, Sep 1, 2008 at 9:23 AM, Evert Lammerts [EMAIL PROTECTED]wrote:
I'm pretty sure I found the problem - I should've spotted it earlier.
The function ProfileList::render gets a reference to the $db object by
its parameter $db. While you loop over your results, you pass the
reference on to $this-des-load. I'm guessing that the definition of
$this-des-load is something like function load($id, $db);, in which
case it's not getting a reference to the $db object but an actual copy
in PHP4. Since PHP 5 there is a new object model that makes sure that
any variable that holds an object is actually just a handle to the
object - so whenever you pass it to a function you use it as a
reference instead of a copy.
To make it clear:
class test {
var $a = 1;
function aa() {
$this-a++;
}
}
$c = new test();
$d = $c;
$c-aa();
$d-aa();
var_dump ($c);
results in:
object(test)#1 (1) { [a]= int(3) }
This means you should first change the function definitions to not use
references for objects, so take away the at every $db parameter.
Second you need to create a new $db object for your $this-des-load
function before the while loop in ProfileList::render. I think the
safest option is to do something like $db2 = new Db(...). You can also
use the keyword clone to clone an object, but i'm not sure what this
does with your internal DB handle you could try and see what
happens. Just add $db2 = clone $db; right before the while loop. Call
$this-des-load with $db2 instead of $db.
aha, excellent explanation , and $db2 = clone$db; worked fine!
I was reading my way round php.net and getting closer I think, your
explanation and probably saved my a few days , so thanks.
hmm, did I speak to soon, it does work well for the whole list, but as soon
as you select a region or speciality then it all goes pear shaped, I'll keep
looking.
Gav...
--
Gav...
--
Gav...
[LinkedIn : http://www.linkedin.com/in/ipv6guru]
www.16degrees.com.au | www.iwdp.co.uk | www.minitutorials.com
(Sponsorship slots available on above three sites!)
Re: [PHP-DB] Problem after moving servers
On Mon, Sep 1, 2008 at 10:38 AM, Gav [EMAIL PROTECTED] wrote:
On Mon, Sep 1, 2008 at 10:10 AM, Gav [EMAIL PROTECTED] wrote:
On Mon, Sep 1, 2008 at 9:23 AM, Evert Lammerts [EMAIL PROTECTED]wrote:
I'm pretty sure I found the problem - I should've spotted it earlier.
The function ProfileList::render gets a reference to the $db object by
its parameter $db. While you loop over your results, you pass the
reference on to $this-des-load. I'm guessing that the definition of
$this-des-load is something like function load($id, $db);, in which
case it's not getting a reference to the $db object but an actual copy
in PHP4. Since PHP 5 there is a new object model that makes sure that
any variable that holds an object is actually just a handle to the
object - so whenever you pass it to a function you use it as a
reference instead of a copy.
To make it clear:
class test {
var $a = 1;
function aa() {
$this-a++;
}
}
$c = new test();
$d = $c;
$c-aa();
$d-aa();
var_dump ($c);
results in:
object(test)#1 (1) { [a]= int(3) }
This means you should first change the function definitions to not use
references for objects, so take away the at every $db parameter.
Second you need to create a new $db object for your $this-des-load
function before the while loop in ProfileList::render. I think the
safest option is to do something like $db2 = new Db(...). You can also
use the keyword clone to clone an object, but i'm not sure what this
does with your internal DB handle you could try and see what
happens. Just add $db2 = clone $db; right before the while loop. Call
$this-des-load with $db2 instead of $db.
aha, excellent explanation , and $db2 = clone$db; worked fine!
I was reading my way round php.net and getting closer I think, your
explanation and probably saved my a few days , so thanks.
hmm, did I speak to soon, it does work well for the whole list, but as soon
as you select a region or speciality then it all goes pear shaped, I'll keep
looking.
Ok, sorted that too, all is well again, sorry for noise.
Gav...
Re: [PHP-DB] Problem with updating MySQL table
Ah, how to debug SQL code in PHP...
Here's what I would do: run your query separately in something like SQLyog or
the Netbeans database interface. Just to echo $sql and copy and paste. An
echo $Record statement may also help to assure that you're passing on the PK
to the record correctly.
One suggestion: you may want put mysql_real_escape_string() wrappers around
all those $_POST[] fields to prevent SQL hijacking of your site.
HTH,
Yves
-- Original Message --
Received: Wed, 27 Aug 2008 11:07:20 AM CDT
From: Jason Pruim [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] Problem with updating MySQL table
Hi Everyone,
So I'm working on a project (Same one I sent the question about
regarding the user access rights on monday) And now I am attempting to
update the record... Here is some of my code:
index.php
?PHP
form method=post action=purlprocess.php
First Name/Last Nameinput type=text name=txtFName
value={$row['FName']} $edit input type=text name=txtLName
value={$row['LName']} $editbr
Email Address input type=text name=txtEmail
value={$row['email']} $editbr
Company name input type=text name=txtBusiness
value={$row['Business']} $editbr
Company Address input type=text name=txtAddress1
value={$row['Address1']} $editbr
City/State/Zip input type=text name=txtCity
value={$row['City']} $edit input type=text name=txtState
value={$row['State']} $edit input type=text name=txtZip
value={$row['Zip']} $editbr
Phone input type=text name=txtPhone value={$row['phone']}
$editbr
Your Favorite Type of coffee: input type=radio name=rdoCoffee
value=Starbucks img src=../media/starbucks.jpeg width=10%
input type=radio name=rdoCoffee value=Folgers img src=../
media/folgers.jpeg width=10% input type=radio name=rdoCoffee
value=Other Other: input type=text name=txtCoffee size=20br
When would a good time to bring it over be? input type=text
name=txtMeetingbr
input type=submit value=Yes! Give me the caffeine!
input type=hidden name=Record value={$row['record']}
/p
/form
?
purlprocessing.php
?PHP
$FName= $_POST['txtFName'];
$LName= $_POST['txtLName'];
$Email= $_POST['txtEmail'];
$Business = $_POST['txtBusiness'];
$Address1 = $_POST['txtAddress1'];
$City = $_POST['txtCity'];
$State = $_POST['txtState'];
$Zip = $_POST['txtZip'];
$CoffeeChoicetest = $_POST['rdoCoffee'];
//$Coffee = $_POST['txtCoffee'];
$Phone = $_POST['txtPhone'];
$Record = $_POST['Record'];
$Meeting = $_POST['txtMeeting'];
$date = time();
$IPAddress = $_SERVER['REMOTE_ADDR'];
if ($CoffeeChoicetest == Other){
$Coffee = $_POST['txtCoffee'];
}else{
$Coffee = $_POST['rdoCoffee'];
}
$sql = UPDATE `schreur` set FName='{$FName}', LName='{$LName}',
email='{$Email}', Business='{$Business}', Address1='{$Address1}',
City='{$City}', State='{$State}', Zip='{$Zip}', Coffee='{$Coffee}',
subscribed='0', date='{$date}', IPAddress='{$IPAddress}',
Meeting='{$Meeting}' WHERE record='{$Record}';
mysqli_query($link, $sql) or die(Could not update... .
mysqli_error($link));
?
mysql describe schreur;
++-+--+-+-+---+
| Field | Type| Null | Key | Default | Extra |
++-+--+-+-+---+
| FName | varchar(20) | YES | | NULL| |
| LName | varchar(20) | YES | | NULL| |
| email | varchar(50) | YES | | NULL| |
| phone | varchar(12) | YES | | NULL| |
| url| int(12) | YES | | NULL| |
| record | int(7) | YES | | NULL| |
| subscribed | int(1) | NO | | | |
| date | varchar(12) | YES | | NULL| |
| IPAddress | varchar(19) | YES | | NULL| |
| Business | varchar(20) | YES | | NULL| |
| Address1 | varchar(50) | YES | | NULL| |
| City | varchar(20) | YES | | NULL| |
| State | varchar(2) | YES | | NULL| |
| Zip| varchar(10) | YES | | NULL| |
| Coffee | varchar(20) | YES | | NULL| |
| Meeting| text| YES | | NULL| |
++-+--+-+-+---+
The problem is when I am attempting to update some of the info, it
erases the info in the field.
Anyone got a clue as to what is going on? :)
Thanks for looking!
--
Jason Pruim
Raoset Inc.
Technology Manager
MQC Specialist
11287 James St
Holland, MI 49424
www.raoset.com
[EMAIL PROTECTED]
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with updating MySQL table
Your index.php looks very strange: ?PHP form method=post action=purlprocess.php /form ? I'm guessing you're echoing this? I never echo from my scripts so I don't know if this is new functionality, but in my days you echoed either by ?=...;? or by ? echo ...; ?. Anyway, since you're using the $_POST variable, did you check if it contains any values? You can do this with var_dump($_POST); Let us know what the results are. Another tip: $FName= $_POST['txtFName']; etc is terrible practice - if anybody writes an SQL command into one of your textfields it WILL be executed; this is called SQL injection. A less terrible scenario, but still one that messes up your page, is if somebody uses quotes. So always use mysql_real_escape_string() on your post variables before using them in a query. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with updating MySQL table
Hi, Jason. Do you realize this code is wide open for an SQL injection
attack? The problem could easily be addressed by using a prepared query
instead. For more details, check the mysqli documentation.
Jason Pruim wrote:
The problem is when I am attempting to update some of the info, it
erases the info in the field.
Anyone got a clue as to what is going on? :)
I'm not sure I understand. You mean that some of the fields that should
receive content in the update do not do so? Why not echo $sql and then
submit the form so that you can see the query being sent to your
database? That will probably help you solve the problem. Odds are
there is something wrong with your query.
You'd never want to echo an SQL query in a production environment, but
since this is in development, I assume you needn't worry about that.
You block of $variable = $_POST['key']; is a complete waste of time,
BTW. Why create another copy of the data? You could just as easily use
set FName = '{$_POST['txtFName']}'... That would also make your
injection vulnerability more obvious to you.
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Re: [PHP-DB] Problem with updating MySQL table
Hi Yves,
I plan to wrap the $_POST's into something to protect against some
issues like that. But this was a proof of concept for the boss so it
just needed to be up quickly to see if it was something we wanted to
go ahead with :)
On Aug 27, 2008, at 12:21 PM, YVES SUCAET wrote:
Ah, how to debug SQL code in PHP...
Here's what I would do: run your query separately in something like
SQLyog or
the Netbeans database interface. Just to echo $sql and copy and
paste. An
echo $Record statement may also help to assure that you're passing
on the PK
to the record correctly.
One suggestion: you may want put mysql_real_escape_string() wrappers
around
all those $_POST[] fields to prevent SQL hijacking of your site.
HTH,
Yves
-- Original Message --
Received: Wed, 27 Aug 2008 11:07:20 AM CDT
From: Jason Pruim [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] Problem with updating MySQL table
Hi Everyone,
So I'm working on a project (Same one I sent the question about
regarding the user access rights on monday) And now I am attempting to
update the record... Here is some of my code:
index.php
?PHP
form method=post action=purlprocess.php
First Name/Last Nameinput type=text name=txtFName
value={$row['FName']} $edit input type=text name=txtLName
value={$row['LName']} $editbr
Email Address input type=text name=txtEmail
value={$row['email']} $editbr
Company name input type=text name=txtBusiness
value={$row['Business']} $editbr
Company Address input type=text name=txtAddress1
value={$row['Address1']} $editbr
City/State/Zip input type=text name=txtCity
value={$row['City']} $edit input type=text name=txtState
value={$row['State']} $edit input type=text name=txtZip
value={$row['Zip']} $editbr
Phone input type=text name=txtPhone value={$row['phone']}
$editbr
Your Favorite Type of coffee: input type=radio name=rdoCoffee
value=Starbucks img src=../media/starbucks.jpeg width=10%
input type=radio name=rdoCoffee value=Folgers img src=../
media/folgers.jpeg width=10% input type=radio name=rdoCoffee
value=Other Other: input type=text name=txtCoffee
size=20br
When would a good time to bring it over be? input type=text
name=txtMeetingbr
input type=submit value=Yes! Give me the caffeine!
input type=hidden name=Record value={$row['record']}
/p
/form
?
purlprocessing.php
?PHP
$FName= $_POST['txtFName'];
$LName= $_POST['txtLName'];
$Email= $_POST['txtEmail'];
$Business = $_POST['txtBusiness'];
$Address1 = $_POST['txtAddress1'];
$City = $_POST['txtCity'];
$State = $_POST['txtState'];
$Zip = $_POST['txtZip'];
$CoffeeChoicetest = $_POST['rdoCoffee'];
//$Coffee = $_POST['txtCoffee'];
$Phone = $_POST['txtPhone'];
$Record = $_POST['Record'];
$Meeting = $_POST['txtMeeting'];
$date = time();
$IPAddress = $_SERVER['REMOTE_ADDR'];
if ($CoffeeChoicetest == Other){
$Coffee = $_POST['txtCoffee'];
}else{
$Coffee = $_POST['rdoCoffee'];
}
$sql = UPDATE `schreur` set FName='{$FName}', LName='{$LName}',
email='{$Email}', Business='{$Business}', Address1='{$Address1}',
City='{$City}', State='{$State}', Zip='{$Zip}', Coffee='{$Coffee}',
subscribed='0', date='{$date}', IPAddress='{$IPAddress}',
Meeting='{$Meeting}' WHERE record='{$Record}';
mysqli_query($link, $sql) or die(Could not update... .
mysqli_error($link));
?
mysql describe schreur;
++-+--+-+-+---+
| Field | Type| Null | Key | Default | Extra |
++-+--+-+-+---+
| FName | varchar(20) | YES | | NULL| |
| LName | varchar(20) | YES | | NULL| |
| email | varchar(50) | YES | | NULL| |
| phone | varchar(12) | YES | | NULL| |
| url| int(12) | YES | | NULL| |
| record | int(7) | YES | | NULL| |
| subscribed | int(1) | NO | | | |
| date | varchar(12) | YES | | NULL| |
| IPAddress | varchar(19) | YES | | NULL| |
| Business | varchar(20) | YES | | NULL| |
| Address1 | varchar(50) | YES | | NULL| |
| City | varchar(20) | YES | | NULL| |
| State | varchar(2) | YES | | NULL| |
| Zip| varchar(10) | YES | | NULL| |
| Coffee | varchar(20) | YES | | NULL| |
| Meeting| text| YES | | NULL| |
++-+--+-+-+---+
The problem is when I am attempting to update some of the info, it
erases the info in the field.
Anyone got a clue as to what is going on? :)
Thanks for looking!
--
Jason Pruim
Raoset
Re: [PHP-DB] Problem with updating MySQL table
YVES SUCAET wrote:
One suggestion: you may want put mysql_real_escape_string() wrappers
around
all those $_POST[] fields to prevent SQL hijacking of your site.
[...]
mysqli_query($link, $sql) or die(Could not update... .
Yves, he's using mysqli, not mysql. You should not mix those functions.
What he should do is this:
?php
$sql = UPDATE `schreur` set FName=?, LName=?,
email=?, Business=?, Address1=?,
City=?, State=?, Zip=?, Coffee=?,
subscribed=?, date=?, IPAddress=?,
Meeting=? WHERE record=?;
$statement = mysqli_prepare($link, $sql);
mysqli_stmt_bind_param($statement,
'sisssi',
$_POST['txtFName'],
$_POST['txtLName'],
// etc..
);
mysqli_stmt_execute($statement);
?
Personally, I find the object style much easier to use than this
procedural style, but I am just being consistent with his code. Using a
prepare query will escape all necessary data automatically, provided
your string of types ('sisssi') is correct.
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Re: [PHP-DB] Problem with updating MySQL table
Jason Pruim wrote: I plan to wrap the $_POST's into something to protect against some issues like that. But this was a proof of concept for the boss so it just needed to be up quickly to see if it was something we wanted to go ahead with :) Well, no worries about that then. We're just looking out for your data security. Heaven forbid someone tamper with your database resulting in some poor soul receiving the wrong coffee! ;) -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with updating MySQL table
Everybody seems to agree on escaping :-) And I'm learning! HEREDOC, nifty indeed! How about your $_POST variable, is there anything in there? On Wed, Aug 27, 2008 at 6:38 PM, Jason Pruim [EMAIL PROTECTED] wrote: On Aug 27, 2008, at 12:24 PM, Evert Lammerts wrote: Your index.php looks very strange: ?PHP form method=post action=purlprocess.php /form ? I'm guessing you're echoing this? I never echo from my scripts so I don't know if this is new functionality, but in my days you echoed either by ?=...;? or by ? echo ...; ?. It is a index.php page using the HEREDOC syntax... so basically: echo HTML Pany HTML code goes here HTML; pretty nifty I feel. Anyway, since you're using the $_POST variable, did you check if it contains any values? You can do this with var_dump($_POST); Let us know what the results are. Another tip: $FName= $_POST['txtFName']; etc is terrible practice - if anybody writes an SQL command into one of your textfields it WILL be executed; this is called SQL injection. A less terrible scenario, but still one that messes up your page, is if somebody uses quotes. So always use mysql_real_escape_string() on your post variables before using them in a query. mysql_real_escape_string() won't help with my mysqlI connection though :) I will be wrapping the whole thing in a prepared statement before going to production with this. At this point this is simply a proof of concept for the boss. -- Jason Pruim Raoset Inc. Technology Manager MQC Specialist 11287 James St Holland, MI 49424 www.raoset.com [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with updating MySQL table
On Aug 27, 2008, at 12:41 PM, Evert Lammerts wrote:
Everybody seems to agree on escaping :-) And I'm learning! HEREDOC,
nifty indeed!
Yeah, ever since I found out about HEREDOC I've used it quite
extensively with some of my projects... Also, when you're in the
HEREDOC block, if you need to reference a variable just do this:
?PHP
$var1 = World;
echo HTML
pHello {$var1}!/p
HTML;
?
and voila!
How about your $_POST variable, is there anything in there?
I think I have it narrowed down to disabling the editing of the
fields...
If I do NOT disable the editing, then it submits fine, if I DO disable
it then they don't submit.
I need to find a better to stop accidental editing rather then just
input type=text disable
On Wed, Aug 27, 2008 at 6:38 PM, Jason Pruim [EMAIL PROTECTED]
wrote:
On Aug 27, 2008, at 12:24 PM, Evert Lammerts wrote:
Your index.php looks very strange:
?PHP
form method=post action=purlprocess.php
/form
?
I'm guessing you're echoing this? I never echo from my scripts so I
don't know if this is new functionality, but in my days you echoed
either by ?=...;? or by ? echo ...; ?.
It is a index.php page using the HEREDOC syntax... so basically:
echo HTML Pany HTML code goes here
HTML;
pretty nifty I feel.
Anyway, since you're using the $_POST variable, did you check if it
contains any values? You can do this with var_dump($_POST); Let us
know what the results are.
Another tip:
$FName= $_POST['txtFName'];
etc
is terrible practice - if anybody writes an SQL command into one of
your textfields it WILL be executed; this is called SQL injection. A
less terrible scenario, but still one that messes up your page, is
if
somebody uses quotes. So always use mysql_real_escape_string() on
your
post variables before using them in a query.
mysql_real_escape_string() won't help with my mysqlI connection
though :)
I will be wrapping the whole thing in a prepared statement before
going to
production with this. At this point this is simply a proof of
concept for
the boss.
--
Jason Pruim
Raoset Inc.
Technology Manager
MQC Specialist
11287 James St
Holland, MI 49424
www.raoset.com
[EMAIL PROTECTED]
--
Jason Pruim
Raoset Inc.
Technology Manager
MQC Specialist
11287 James St
Holland, MI 49424
www.raoset.com
[EMAIL PROTECTED]
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with updating MySQL table
On Aug 27, 2008, at 12:48 PM, Jason Pruim wrote: For everyone that has helped me on this thank you! :) the solution was changing from: input type=text name=txtFName DISABLED to input type=text name=txtFName READONLY Read only fields still get passed with POST'ed info where as disabled does not. And yes I will be adding some prepared statements to prevent SQL injections as I'm hoping this will be a VERY popular feature that will be used by my company for quite a long time :) -- Jason Pruim Raoset Inc. Technology Manager MQC Specialist 11287 James St Holland, MI 49424 www.raoset.com [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with updating MySQL table
Putting commands into input containers in HTML is deprecated in the XHTML specification. You should use this instead in the input: readonly=readonly Thank you, Micah Gersten onShore Networks Internal Developer http://www.onshore.com Jason Pruim wrote: On Aug 27, 2008, at 12:48 PM, Jason Pruim wrote: For everyone that has helped me on this thank you! :) the solution was changing from: input type=text name=txtFName DISABLED to input type=text name=txtFName READONLY Read only fields still get passed with POST'ed info where as disabled does not. And yes I will be adding some prepared statements to prevent SQL injections as I'm hoping this will be a VERY popular feature that will be used by my company for quite a long time :) -- Jason Pruim Raoset Inc. Technology Manager MQC Specialist 11287 James St Holland, MI 49424 www.raoset.com [EMAIL PROTECTED] -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB]problem in creating the ibm_db2 extension
On Thu, May 1, 2008 at 5:53 AM, Chris [EMAIL PROTECTED] wrote: H Thirividi wrote: Hi All, I have installed db2 on my* fedora core 7* system and now i wan t to access the database using the* php apis*. For this reason I downloaded the *ibm_db2 1.6* package and tried to create the extension. I did the following phpize output is Configuring for: PHP Api Version: 20041225 Zend Module Api No: 20060613 Zend Extension Api No: 220060519 ./configure --with-IBM_DB2=/opt/ibm/db2/V9.5 part of the ouput checking for re2c... no configure: WARNING: You will need re2c 0.12.0 or later if you want to regenerate PHP parsers. checking for gawk... gawk checking for IBM_DB2 support... yes, shared checking Looking for DB2 CLI libraries... checking in /opt/ibm/db2/V9.5... checking in /opt/ibm/db2/V9.5/lib64... checking in /opt/ibm/db2/V9.5/lib32... found checking for DB2 CLI include files in default path... checking in /opt/ibm/db2/V9.5... not found It's looking for the include/, lib/ etc folders under that (ie the headers and so on). Where are they located? Hello Chris, I am not sure if after getting a reply to the question one should still reply to the mailing list or reply to the *person directly*. If I have committed a mistake kindly oblige as this is new to me. After posting the question I just *searched* and then came to know that while installing db2, it had created 3 users named *db2inst1*, *db2fenc1*and one more *administrative user* whose name i am not able to recollect and then saw *db2 cli include files* in *db2inst1's home* when i logged onto the system as a db2inst1 user and tried to copy those files to /opt/ibm/db2/V9.5 (which is where db2 database is installed) but gave me an error saying that I cannot copy. I also changed the permissions and even then could not copy. So does this mean i have to complie the extension by logging in as db2inst1 and cant this be as root or what should I do to continue further. With Regards, Harsha
Re: [PHP-DB]problem in creating the ibm_db2 extension
H Thirividi wrote: On Thu, May 1, 2008 at 5:53 AM, Chris [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] wrote: H Thirividi wrote: Hi All, I have installed db2 on my* fedora core 7* system and now i wan t to access the database using the* php apis*. For this reason I downloaded the *ibm_db2 1.6* package and tried to create the extension. I did the following phpize output is Configuring for: PHP Api Version: 20041225 Zend Module Api No: 20060613 Zend Extension Api No: 220060519 ./configure --with-IBM_DB2=/opt/ibm/db2/V9.5 part of the ouput checking for re2c... no configure: WARNING: You will need re2c 0.12.0 or later if you want to regenerate PHP parsers. checking for gawk... gawk checking for IBM_DB2 support... yes, shared checking Looking for DB2 CLI libraries... checking in /opt/ibm/db2/V9.5... checking in /opt/ibm/db2/V9.5/lib64... checking in /opt/ibm/db2/V9.5/lib32... found checking for DB2 CLI include files in default path... checking in /opt/ibm/db2/V9.5... not found It's looking for the include/, lib/ etc folders under that (ie the headers and so on). Where are they located? Hello Chris, I am not sure if after getting a reply to the question one should still reply to the mailing list or reply to the *person directly*. If I have committed a mistake kindly oblige as this is new to me. mailing list - so others can chime in with suggestions and/or learn from the questions/comments. After posting the question I just *searched* and then came to know that while installing db2, it had created 3 users named *db2inst1*, *db2fenc1* and one more *administrative user* whose name i am not able to recollect and then saw *db2 cli include files* in *db2inst1's home* when i logged onto the system as a db2inst1 user and tried to copy those files to /opt/ibm/db2/V9.5 (which is where db2 database is installed) but gave me an error saying that I cannot copy. Note - I have never installed db2 so not sure how it works/is set up. However, with mysql, postgresql, gd other extensions for php, you have to install the devel or dev package along with the main one for php to compile against. The dev package provides the headers which other packages can use, for example: /usr/include/postgresql/*.h /usr/lib/postgresql/* PHP looks at those headers (*.h) and uses those to work out functionality. So when you compile, you have to point php to the base folder which contains the include/ and lib/ subdirectories. ./configure --with-pgsql=/usr in your case: ./configure --with-db2=/path/to/db2 under /path/to/db2 you need the include/, lib/ etc folders which include the program headers. Without those files, php won't compile with db2 support. It looks like you have the lib stuff there (lib32/ is fine, it was picked up) but there's no include/ stuff which is what configure is complaining about. -- Postgresql php tutorials http://www.designmagick.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB]problem in creating the ibm_db2 extension
H Thirividi wrote: Hi All, I have installed db2 on my* fedora core 7* system and now i wan t to access the database using the* php apis*. For this reason I downloaded the *ibm_db2 1.6* package and tried to create the extension. I did the following phpize output is Configuring for: PHP Api Version: 20041225 Zend Module Api No: 20060613 Zend Extension Api No: 220060519 ./configure --with-IBM_DB2=/opt/ibm/db2/V9.5 part of the ouput checking for re2c... no configure: WARNING: You will need re2c 0.12.0 or later if you want to regenerate PHP parsers. checking for gawk... gawk checking for IBM_DB2 support... yes, shared checking Looking for DB2 CLI libraries... checking in /opt/ibm/db2/V9.5... checking in /opt/ibm/db2/V9.5/lib64... checking in /opt/ibm/db2/V9.5/lib32... found checking for DB2 CLI include files in default path... checking in /opt/ibm/db2/V9.5... not found It's looking for the include/, lib/ etc folders under that (ie the headers and so on). Where are they located? -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem when using SQL_CUR_USE_ODBC on connect
(This isn't a solution, per se...just a suggestion.)
I don't know how they compare; I've never personally used the ODBC
functions...
But, you may give the MSSQL functions a try:
http://php.net/mssql
- Jon L.
On Mon, Mar 31, 2008 at 3:27 PM, cfs [EMAIL PROTECTED] wrote:
I'm using PHP with Apache. PHP code connects to MS SQL server using ODBC.
I'm doing a query against a table that is very simple: one column of the
real data type, one of the text data type.
The text field is set to testing 1,2,3. The real column is set to
10.015.
When I use the default connect options, I get both values back fine.
When I use SQL_CUR_USE_ODBC, which I very much want to use, then the text
column data comes back as boolean(false).
Does anyone know of a solution?
Table:
CREATE TABLE [dbo].[test1](
[ID] [int] IDENTITY(1,1) NOT NULL,
[real1] [real] NULL,
[text1] [text] COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
CONSTRAINT [PK_test1] PRIMARY KEY CLUSTERED
(
[ID] ASC
)WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
Code:
?php
$conn = odbc_connect(db-name, user-name,password, SQL_CUR_USE_ODBC);
$result = odbc_exec($conn, select * from test1);
if (odbc_fetch_row($result)) {
print Values: . odbc_result($result,real1) . , .
odbc_result($result,text1);
}
?
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Re: [PHP-DB] problem in recorset that seems temporary
Hi!
I did not quite get the point here, but maybe that's not needed to solve
the problem... :-)
First of all, you seem to have enabled the register_global setting,
since I can't see from where the parameter $id is posted. Use the $_GET
or $_POST superglobal array instead. Take big care of input filtering
also and do not put dirty data directly into your query.
Second, the function mysql_db_query() has been deprecated for a long
time now, use mysql_select_db() and mysql_query() instead.
I think your problem is in your while-loop:
You loop over the result set $result and fetch the row as an object.
Then you execute a delete statement and at the same time overwriting
your previous result set $result, thus you will break the loop with an
error that the provided parameter is not a result set.
I also guess you have a typo in your last statement where you (probably)
try to delete the gallery. I guess that you maybe want to use the
variable $galerie_id..? Well, I can't tell without any more information
about your application.
Greetings,
Krister Karlström, Helsinki, Finland
Ruprecht Helms wrote:
while($row = mysql_fetch_object($result))
{
$galerie_id=$row-ID;
$result=mysql_db_query(pferdeservice-karle,DELETE FROM
Galerie_kultur WHERE GalerieID=$id);
}
$result=mysql_db_query(pferdeservice-karle,DELETE FROM Galerie WHERE
ID=$id);
echo mysql_error();
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Re: [PHP-DB] Problem with reading out value from urlline
Hi, you should do it like this ?php $id = $_GET['id']; // -- getting var from the url line echo $id; ? - Aleksandar Ruprecht Helms wrote: Hi, I have the problem that a phpscript is not able to read out a value from the browserline. In the browserline I have the URL domain/page?id=value. The id-Value I want to process within the script but a echo $id shows me no value. The Php-Surrounding is very secured. Formfields and variables that schould be part of a mysqldatabase must be escaped by the mysql_real_escape_string-command. What is the right command to get the value from the browserline. Regards, Ruprecht -- Ruprecht Helms IT-Service Softwaredevelopment Web: a href=http://www.rheyn.deRuprecht Helms IT-Service Softwareentwicklung, Loerrach/a -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with passing variable to mssql
William Curry wrote:
I have issues I cant understand passing a sql statement to mssql, most
of which work fine, however in some cases, a statement like
SELECT * FROM tblX where value like 'variable%' will return 0
records when I know they are there. No errors, just 0 records.
When I echo the sql string to the page, cut and paste it into SQL query
analyzer, the exact same statement returns the expected records.
Anyome point me to the answer??
It's over there -
Sorry, couldn't resist.
Anyhoo, are you expecting variable to be replaced with the contents of
$variable? If so that's never going to work. Try this instead...
SELECT * FROM tblX where value like '.str_replace(', '',
$variable).%'
-Stut
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Re: [PHP-DB] Problem with passing variable to mssql
Please include the list when replying.
William Curry wrote:
Thanx for the quick reply, I left out the concats in my sample here is
the exact statement:
$qry1 = SELECT *,CONVERT(Char(24),CALL_ENTRY_DATE,101) as MYDATE from
PcarsCallComplete
where Location_address = .$Location2. order by CALL_NO;
and as echoed with the $Location2 value inserted:
SELECT *,CONVERT(Char(24),CALL_ENTRY_DATE,101) as MYDATE from
PcarsCallComplete where Location_address = '1121 800N,TOT,TOT' order by
CALL_NO
$Location2 is passed in the URL when the user clicks a hyperlink for a
certain address record from a list of possible matches.
$qry1 returns 0 records in the page, but 10 records in SQL QA. I run
the URL var through a stripslashes and add the '%' before inserting it
into the string.
I've, never used the str_replace function, and generally get the same
results with similar statements. baffled
1) The str_replace is necessary to protect against SQL injection
attacks. If you don't know what that means, Google it.
2) Are you checking return values for errors? If not, try that.
Aside from that I have no idea. If there are no errors and you are still
getting different results from the script and from QA with the same SQL
statement then by definition something *is* different.
-Stut
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Stut [EMAIL PROTECTED] 6/28/2007 8:30 AM
William Curry wrote:
I have issues I cant understand passing a sql statement to mssql, most
of which work fine, however in some cases, a statement like
SELECT * FROM tblX where value like 'variable%' will return 0
records when I know they are there. No errors, just 0 records.
When I echo the sql string to the page, cut and paste it into SQL query
analyzer, the exact same statement returns the expected records.
Anyome point me to the answer??
It's over there -
Sorry, couldn't resist.
Anyhoo, are you expecting variable to be replaced with the contents of
$variable? If so that's never going to work. Try this instead...
SELECT * FROM tblX where value like '.str_replace(', '',
$variable).%'
-Stut
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Re: [PHP-DB] Problem with passing variable to mssql
William Curry wrote: $qry1 = SELECT *,CONVERT(Char(24),CALL_ENTRY_DATE,101) as MYDATE from PcarsCallComplete where Location_address = .$Location2. order by CALL_NO; This method usually works well for me for debugging purposes: immediately prior to query, echo it to see exactly what you're telling mysql and then exit the script so it's the only output. Log in to mysql as the user that your script is logging in as (just in case it's a permission setting) Enter sql via copy paste Check results. So, for you: echo \$qry1 = \SELECT *,CONVERT(Char(24),CALL_ENTRY_DATE,101) as MYDATE from PcarsCallComplete where Location_address = $Location2 order by CALL_NO\;; Enter output into mysql (obviously only the code between the quotes) and run query. Be sure you're logged in as the same user that the script logs in with, else you may have different privileges! If you don't receive an error or an empty set in mysql, then it could be something simple yet hard to diagnose. Perhaps you're inserting (and logging directly in) to a different database than your script is reading from (such as if you have multiple comps on your network acting as servers, perhaps you're trying to select from the wrong machine's database). Thanks, Jim -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with rss-feed generation
I support Neil on this point! But anyway this list has answered many other aspects, so why not some XML? Ruprecht you might like FeedCreator latest stable from here http://www.bitfolge.de/rsscreator it just doesn't generate ATOM 1.0, but all other formats will be readable atleast by IE and Firefox. Best Regards. - Shape Yahoo! in your own image. Join our Network Research Panel today!
Re: [PHP-DB] Problem with rss-feed generation
Hi the first line is badly formed xml version=1.0 encoding=ISO-8859-1 Should be: ?xml version=1.0 encoding=ISO-8859-1 ? Niel -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with rss-feed generation
Niel Archer wrote: Hi the first line is badly formed xml version=1.0 encoding=ISO-8859-1 Should be: ?xml version=1.0 encoding=ISO-8859-1 ? ok by beginning the php-code with ?php I fixed the problem. Unfortunately my RSSowl tell me that there must be other errors in the xml-formating. And I don't got a detailed information what RSSowl dislike in the xml-file. Regards, Ruprecht -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with rss-feed generation
Hi ok by beginning the php-code with ?php I fixed the problem. Unfortunately my RSSowl tell me that there must be other errors in the xml-formating. And I don't got a detailed information what RSSowl dislike in the xml-file. Try opening it in a browser. Opera, for example, tells you what error it encounters. That's how I identified your initial error. Niel -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with rss-feed generation
Niel Archer wrote: Hi ok by beginning the php-code with ?php I fixed the problem. Unfortunately my RSSowl tell me that there must be other errors in the xml-formating. And I don't got a detailed information what RSSowl dislike in the xml-file. Try opening it in a browser. Opera, for example, tells you what error it encounters. That's how I identified your initial error. firefox tells me that it dislike the closing xml-tag. In my quanta-editor it seems that can be difficulties with the tagend of the opening xml-line of the second position of the questionmark. Regards, Ruprecht ?xml version=1.0 encoding=ISO-8859-1? !DOCTYPE rss PUBLIC -//Netscape Communications//DTD RSS 0.91//EN http://my.netscape.com/publish/formats/rss-0.91.dtd; rss version=0.91 channel title(RSS 2.0)/title linkhttp://www.bla.com//link descriptionDie neuesten Artikel in Bla-Bereich ; /description languagede/language managingEditorRuprecht Helms [EMAIL PROTECTED]/managingEditor webMasterRuprecht Helms [EMAIL PROTECTED]/webMaster item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; dsklfdsafdsajfasdf lt;brgt;/description descriptiondsklfdsafdsajfasdflt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; Test lt;brgt;/description descriptionTestlt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; Testantwort lt;brgt;/description descriptionTestantwortlt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; xx lt;brgt;/description descriptionxxlt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; ]Test erneuter Testlt;brgt;/description description]Test erneuter Test lt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; ]Test erneuter 2. Test lt;brgt;/description description]Test erneuter 2. Test lt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; ]Test erneuter 2. Test lt;brgt;/description description]Test erneuter 2. Test lt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; dfklödsfadfsjdkjsdafasdj lt;brgt;/description descriptiondfklödsfadfsjdkjsdafasdjlt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; ]dfklödsfadfsjdkjsdafasdj lt;brgt;/description description]dfklödsfadfsjdkjsdafasdj lt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; ]dfklödsfadfsjdkjsdafasdj lt;brgt;/description description]dfklödsfadfsjdkjsdafasdj lt;brgt; - /description /item item title/title link/link descriptionlt;table CELLPADDING=quot;5quot; CELLSPACING=quot;0quot; border=quot;0quot; align=quot;leftquot;gt;lt;trgt;lt;tdgt;lt;#47;tdgt;lt;#47;trgt;lt;#47;tablegt; lt;brgt; ]dfklödsfadfsjdkjsdafasdj lt;brgt;/description description]dfklödsfadfsjdkjsdafasdj
Re: [PHP-DB] Problem with rss-feed generation
Hi Niel, firefox tells me that it dislike the closing xml-tag. In my quanta-editor it seems that can be difficulties with the tagend of the opening xml-line of the second position of the questionmark. Because you missed the space in front of it. You really need to find out more about XML and RSS specifications. This isn't a PHP or Db problem so doesn't belong on this list. Maybe I thought that someone of the member have worked with a dynamicly rss-feed generator. I use some mysql-tables for content within the feed. Du you know a good tutorial for XML and RSS, possible relating with PHP. Regards, Ruprecht -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with rss-feed generation
Hi Du you know a good tutorial for XML and RSS, possible relating with PHP. Not a tutorial, no. I got my information from the specification documents. You should consider changing your method. Instead of creating the RSS/XMl file manually, try using one of the PHP extensions that will generate XML for you, like the PEAR XML_Query2XML package which converts SQL SELECT results into valid XML data. Or PECL's xmlwriter. Niel -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with imagebuilding
$hintergrund = $row_hintergrundsbild-Bildname; $backgroundimage = $hintergrund; this is the problem whole about. u call img name but not img file.. fyi.. to build a img u must begin with this.. $im = imagecreatefrompng(test.png); what u want to do?? plz explain - Original Message - From: Ruprecht Helms [EMAIL PROTECTED] To: php-db@lists.php.net Sent: Friday, May 04, 2007 3:10 PM Subject: [PHP-DB] Problem with imagebuilding Hi, I actually have a problem with a script that creates a picture from database content. I the following error: Warning: imagepng(): supplied argument is not a valid Image resource in /opt/lampp/htdocs/cycosmos_2/avatare/avatarbild.php on line 315 The other lines that copy and resize other content for the imagebuilding I've remarked, because there produce errors too. Another script that produce the result that I want by working with hardcoded content works without no problems. Can someone tell me what can be wrong in the databasescript. The file avatarbild.php contails the malefunction script. The file bild_komplettavatar.php contains an example with the correct output. Regards, Ruprecht --- Ruprecht Helms IT-Service Softwaredevelopment allow your worktools be individual Web: http://www.rheyn.de -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with ocilogon
Dominik Helle wrote: Hi, I've a problem with php-oci and I hope anybody can help me. I want to connect with ocilogon to an Oracle Database. If i call my php-Script in the browser, this error message turn up: Warning: ocilogon() [function.ocilogon]: OCIEnvNlsCreate() failed. There is something wrong with your system - please check that ORACLE_HOME is set and points to the right directory in... That is very funny, because if i activate the file on the command line - the connect is possible and no error message turns up. FYI: My System: Ubunutu 6, Apache 2 and php 5-with-oci Oracle Database 10g (10.1.0.2). Thank you for helping. Dominik I'm assuming since you mention the apache, this is a web application... It looks like the ORACLE_HOME path is not know by apache/PHP. So, you might try stopping apache, and doing something like 'source /etc/profile' or wherever your ORACLE_HOME env variable is set, and then restarting apache and trying again... HTH -B -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with ocilogon
Brad Bonkoski schrieb: Dominik Helle wrote: Hi, I've a problem with php-oci and I hope anybody can help me. I want to connect with ocilogon to an Oracle Database. If i call my php-Script in the browser, this error message turn up: Warning: ocilogon() [function.ocilogon]: OCIEnvNlsCreate() failed. There is something wrong with your system - please check that ORACLE_HOME is set and points to the right directory in... That is very funny, because if i activate the file on the command line - the connect is possible and no error message turns up. FYI: My System: Ubunutu 6, Apache 2 and php 5-with-oci Oracle Database 10g (10.1.0.2). Thank you for helping. Dominik I'm assuming since you mention the apache, this is a web application... It looks like the ORACLE_HOME path is not know by apache/PHP. So, you might try stopping apache, and doing something like 'source /etc/profile' or wherever your ORACLE_HOME env variable is set, and then restarting apache and trying again... HTH -B Mhmmm I set this variables in the Apache - but it don't work :( SetEnv ORACLE_HOME /xxx SetEnv TNS_ADMIN /xxx SetEnv LD_LIBRARY_PATH /xxx SetEnv ORACLE_SID orcl10g SetEnv NLS_LANG GERMAN_GERMANY.WE8ISO8859P1 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with ocilogon
Here are a couple of things I have done ...
1) Edit the apachectl script and set the variables there
2) Set the variables in your shell then start apache
3) use phpinfo() to display your settings (I also found the below php
script to work well)
-
?php
phpinfo();
$a= ini_get_all();//Call ini_get_all()
$output=table border=1; //Start an output string
while(list($key, $value)=each($a)) //Loop through results
{
list($k, $v)= each($a[$key]); //Access each array
$output.=trtd
$key
/tdtd
$v
/tdtd
$k
/td/tr;//Build output
}//while
$output.=/table; //Finish up
echo $output; //Spit it all out
?
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Pager:
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Dominik Helle [EMAIL PROTECTED]
16-Feb-2007 09:58
To
php-db@lists.php.net
cc
Subject
Re: [PHP-DB] Problem with ocilogon
Brad Bonkoski schrieb:
Dominik Helle wrote:
Hi,
I've a problem with php-oci and I hope anybody can help me. I want to
connect with ocilogon to an Oracle Database. If i call my php-Script
in the browser, this error message turn up:
Warning: ocilogon() [function.ocilogon]: OCIEnvNlsCreate() failed.
There is something wrong with your system - please check that
ORACLE_HOME is set and points to the right directory in...
That is very funny, because if i activate the file on the command line
- the connect is possible and no error message turns up.
FYI: My System: Ubunutu 6, Apache 2 and php 5-with-oci Oracle
Database 10g (10.1.0.2).
Thank you for helping.
Dominik
I'm assuming since you mention the apache, this is a web application...
It looks like the ORACLE_HOME path is not know by apache/PHP. So, you
might try stopping apache, and doing something like 'source
/etc/profile' or wherever your ORACLE_HOME env variable is set, and then
restarting apache and trying again...
HTH
-B
Mhmmm I set this variables in the Apache - but it don't work :(
SetEnv ORACLE_HOME /xxx
SetEnv TNS_ADMIN /xxx
SetEnv LD_LIBRARY_PATH /xxx
SetEnv ORACLE_SID orcl10g
SetEnv NLS_LANG GERMAN_GERMANY.WE8ISO8859P1
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Re: [PHP-DB] Problem with PHP 4.4.4 and MSSQL in Centos
Hi Claudio,
1) Check the version of FreeTDS on both systems.
2) Check the freetds.conf file for differences (use the sam TDS version)
3) Check that php is compiled using --with-mssql on both systems
(--with-sybase will give you aliases to some mssql_( functions but not
all)
- Frank
Hi all!
I've stepped into an annoying problem when trying to fetch the tuples
returned by a stored procedure in a MSSQL database from a PHP program
running in a Centos Linux server running PHP 4.4.4.
The stored procedure returns an arbitrary number of tuples, and my code
is only working when the SP returns one row.
The code I'm using, simplified, follows:
$db_conn = mssql_connect (server, user, passwd);
mssql_select_db(db,$db_conn);
$query = Exec stored_procedure '$par1', '$par2';
$result = mssql_query ($query);
while ($row = mssql_fetch_array ($result)) {
echo $row[COL1];
echo br/;
}
If stored_procedure () returns only one row, the code executes without
any problem. However, if there are more than one rows to be returned,
the program not only blocks, but also eats all the server's memory.
I've run this program also in Ubuntu with PHP 4.4, and it works without
any problem, so I'm thinking it may be either a configuration problem of
the centos server, or a bug in the PHP version.
Do you have any hint to solve this? I would appreciate any advice.
Thanks in advance,
Claudio
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Re: [PHP-DB] Problem with PHP 4.4.4 and MSSQL in Centos
Hi Frank, El vie, 12-01-2007 a las 10:49 -0800, Frank M. Kromann escribió: 1) Check the version of FreeTDS on both systems. It proved irrelevant. See above. 2) Check the freetds.conf file for differences (use the sam TDS version) No differences. 3) Check that php is compiled using --with-mssql on both systems (--with-sybase will give you aliases to some mssql_( functions but not all) I fixed it by compiling again php with --with-mssql instead of --with-sybase. Now it works perfectly. Thanks for your suggestions. Anyway, I wouldn't expect php to hang and kill my server if compiled with --sybase. Maybe just a runtime error would be ok, but a hang like that, it's a bug to me. I would gladly report it, if I knew where should I. Do you think it may be in freeTDS or PHP itself? I am not really into PHP internals. Best regards, Claudio -- Claudio Saavedra [EMAIL PROTECTED] - La informacion contenida en esta transmision (y sus documentos adjuntos), es confidencial y no puede ser usada o difundida por personas distintas a su(s) destinatario(s). El uso no autorizado de la informacion contenida en esta transmision puede ser sancionado criminalmente de conformidad con la ley chilena. Si ha recibido esta transmision por error, por favor destruyala y notifique al remitente. Atendido que no existe certidumbre que el presente mensaje no sera modificado como resultado de su transmision por correo electronico, nuestra empresa, no sera responsable si el contenido del mismo ha sido modificado. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with PHP 4.4.4 and MSSQL in Centos
Hi Claudio, bugs.php.net would be the place to report the bug. As both the MSSQL and Sybase extensions are using the same FreeTDS library I would think the bug is in the Sybase extension. You will get more mssql_* functions with the MSSQL extension, and much better support for storred procedures so I think you will be happy about the change. - Frank Hi Frank, El vie, 12-01-2007 a las 10:49 -0800, Frank M. Kromann escribió: 1) Check the version of FreeTDS on both systems. It proved irrelevant. See above. 2) Check the freetds.conf file for differences (use the sam TDS version) No differences. 3) Check that php is compiled using --with-mssql on both systems (--with-sybase will give you aliases to some mssql_( functions but not all) I fixed it by compiling again php with --with-mssql instead of --with-sybase. Now it works perfectly. Thanks for your suggestions. Anyway, I wouldn't expect php to hang and kill my server if compiled with --sybase. Maybe just a runtime error would be ok, but a hang like that, it's a bug to me. I would gladly report it, if I knew where should I. Do you think it may be in freeTDS or PHP itself? I am not really into PHP internals. Best regards, Claudio -- Claudio Saavedra [EMAIL PROTECTED] - La informacion contenida en esta transmision (y sus documentos adjuntos), es confidencial y no puede ser usada o difundida por personas distintas a su(s) destinatario(s). El uso no autorizado de la informacion contenida en esta transmision puede ser sancionado criminalmente de conformidad con la ley chilena. Si ha recibido esta transmision por error, por favor destruyala y notifique al remitente. Atendido que no existe certidumbre que el presente mensaje no sera modificado como resultado de su transmision por correo electronico, nuestra empresa, no sera responsable si el contenido del mismo ha sido modificado. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with executing Oracle query for creating procedure
Christopher Jones [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Rosen wrote: Hi, i have problem with PHP and Oracle database. I read with PHP script an sql files like this: create or replace procedure test_proc1(p1 IN number, p3 OUT number) as begin p3 := p1 + 10; end; And when I execute it I receive an error: Warning: ociexecute(): OCIStmtExecute: OCI_SUCCESS_WITH_INFO: ORA-24344: success with compilation error in... And the procedue doesn't put in the database. When I edit the .sql file - all to be on 1 row - like this: create or replace procedure test_proc1(p1 IN number, p2 OUT number) as begin p2 := p1 + 10; end; Then I have no problems. Can someone help me with this? Thanks in advance, Rosen Normally I'd use a tool such as SQL Developer or SQL*Plus to pre-create database resident things like tables and PL/SQL procedures. Yes, but this is update system, i.e. - it will need to execute scripts from .sql files to many servers. The procesures/functions must be wrapped with wrap.exe before executing. This is very important. However, back to your problem: use UNIX style end of line characters. Or build up the statement using PHP string concatenation. How can I do this? Can you give me some example. Thanks in advance, Rosen Chris -- Christopher Jones, Oracle Email: [EMAIL PROTECTED]Tel: +1 650 506 8630 Blog: http://blogs.oracle.com/opal/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with executing Oracle query for creating procedure
Rosen wrote: Hi, i have problem with PHP and Oracle database. I read with PHP script an sql files like this: create or replace procedure test_proc1(p1 IN number, p3 OUT number) as begin p3 := p1 + 10; end; And when I execute it I receive an error: Warning: ociexecute(): OCIStmtExecute: OCI_SUCCESS_WITH_INFO: ORA-24344: success with compilation error in... And the procedue doesn't put in the database. When I edit the .sql file - all to be on 1 row - like this: create or replace procedure test_proc1(p1 IN number, p2 OUT number) as begin p2 := p1 + 10; end; Then I have no problems. Can someone help me with this? Thanks in advance, Rosen Normally I'd use a tool such as SQL Developer or SQL*Plus to pre-create database resident things like tables and PL/SQL procedures. However, back to your problem: use UNIX style end of line characters. Or build up the statement using PHP string concatenation. Chris -- Christopher Jones, Oracle Email: [EMAIL PROTECTED]Tel: +1 650 506 8630 Blog: http://blogs.oracle.com/opal/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with Oracle
[EMAIL PROTECTED] wrote:
In Oracle you would write: insert into pts (pid, txt) values (1,'502a');
But in PHP you are going to do the following:
$conn = oci_connect('scott','tiger','my_db');
$sql = insert into pts (pid, txt) values (1,'502a');
$cursor = oci_parse($conn, $sql);
if (! $cursor)
{ $err = oci_error($conn);
print htmlentities($e['message']);
exit;
}
$results = oci_execute($cursor);
oci_commit($conn);
oci_close($conn);
The statements:
$results = oci_execute($cursor);
oci_commit($conn);
do two commits. Oci_execute() commits by default. The message
to the database to perform the commit is piggybacked in the
execute call. However the subsequent (unecessary in this case)
oci_commit() call requires an explicit round trip to the DB.
If you were doing multiple inserts you might do something like:
$s = oci_parse($c, 'insert into ptab (pdata) values (:bv)');
oci_bind_by_name($s, ':bv', $v, 20, SQLT_CHR);
foreach ($a as $v) {
$r = oci_execute($s, OCI_DEFAULT);
}
oci_commit($c);
Or explore calling a PL/SQL block and do a bulk FORALL insert.
I'll blog about bulk FORALL in a few days.
Chris
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Re: [PHP-DB] Problem with Oracle
In Oracle you would write: insert into pts (pid, txt) values (1,'502a');
But in PHP you are going to do the following:
$conn = oci_connect('scott','tiger','my_db');
$sql = insert into pts (pid, txt) values (1,'502a');
$cursor = oci_parse($conn, $sql);
if (! $cursor)
{ $err = oci_error($conn);
print htmlentities($e['message']);
exit;
}
$results = oci_execute($cursor);
oci_commit($conn);
oci_close($conn);
The difference is that in PHP it appends a command seperator during the
parsing. A simple thing is to remove the trailing comma from the parsed
SQL or remove it from the file.
Roy A. Jones
Rosen [EMAIL PROTECTED]
23-Oct-2006 19:21
To
php-db@lists.php.net
cc
Subject
[PHP-DB] Problem with Oracle
Hi,
I have a problem with PHP and Oracle 10 Database.
I read sql script from file and execute it.
Files are something like this:
insert into pts (pid, txt) values (1,'502a');
insert into pts (pid, txt) values (2,'502b');
.
I receive a message: ORA-00911: invalid character
When I remove manually the ; from the end of every row and execute
separate every command
everything is ok.
I have and script files fo creating procedures/functions and there in not
a
problem with ;.
Where is the problem ? Why can not be used ; as command separator from
PHP
?
Thanks in advance!
Rosen
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RE: [PHP-DB] Problem with pg_fetch_array
show relevant code around the query and attempt to loop thru resultset
bastien
From: Vignesh M P N [EMAIL PROTECTED]
To: php-db@lists.php.net
Subject: [PHP-DB] Problem with pg_fetch_array
Date: Mon, 23 Oct 2006 15:12:25 -0500
Hi
I am trying to display the rows from a database table in a grid.
I retrieved the results using pg_query() with a Select command. pg_query()
returns true.
But when I pass the results $rows to pg_fetch_array(), it returns false. I
even tried displaying the error, if any, using:
pg_fetch_array($rows) or die('fetch array failed: ' . pg_last_error());
I also tried pg_result_error(), but both didn't display error.
It just displays fetch array failed: , but it doesn't display any error.
When the pg_query() returns a result, I wonder why pg_fetch_array() is not
able to iterate through the rows.
I am new to this PHP database stuff, please help me in this.
Thanks
Vignesh.
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Re: [PHP-DB] Problem with pg_fetch_array
Vignesh M P N wrote:
Hi
I am trying to display the rows from a database table in a grid.
I retrieved the results using pg_query() with a Select command. pg_query()
returns true.
But when I pass the results $rows to pg_fetch_array(), it returns false. I
even tried displaying the error, if any, using:
You return $result to pg_fetch_array not $rows.
$query = SELECT version();
$result = pg_query($query);
while($row = pg_fetch_array($result)) {
print_r($row);
}
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Re: [PHP-DB] Problem with Oracle
Rosen wrote: Hi, I have a problem with PHP and Oracle 10 Database. I read sql script from file and execute it. Files are something like this: insert into pts (pid, txt) values (1,'502a'); insert into pts (pid, txt) values (2,'502b'); . I receive a message: ORA-00911: invalid character When I remove manually the ; from the end of every row and execute separate every command everything is ok. I have and script files fo creating procedures/functions and there in not a problem with ;. Then you're not showing us the exact content of the files or the code you're using to make this insert into your database. What's the exact code you're using to go through the file and insert the data? -- Postgresql php tutorials http://www.designmagick.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with Oracle query
Try this ... SELECT m.id ,m.text FROM main m ,recs r WHERE m.id = r.id AND r.log like '%sometext%' ORDER BY m.id / Roy A. Jones Rick [EMAIL PROTECTED] 13-Oct-2006 10:53 To php-db@lists.php.net cc Subject Re: [PHP-DB] Problem with Oracle query Brad Bonkoski [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Rosen wrote: Hi, I have a problem with PHP and Oracle SQL query. I have 2 tables : Table Main: --- id number text varchar2(100) Table Recs --- id number pos number log varchar2(200) I need to make query to select a list from first table(Main), where somewhere in the second table (Recs), the log field contains some string. The records for one ID from Main table can be many in table Recs. ( Table Recs acts as log for every row from table Main). Can someone help me with this query? Thanks in advance, Rosen select m.id, r.log from main m left outer join recs r on r.id = m.id This will output something like: Id log 1log item 1 1log item 2 1log item 3 2another log etc... Thanks, but I want to retrieve only one row for ID field (row from Main table) where the string contains in second table. Something like this: ID Text 1 Sometext 1 2 Sometext 2 6Sometext 3 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with Oracle query
[EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Try this ... SELECT m.id ,m.text FROM main m ,recs r WHERE m.id = r.id AND r.log like '%sometext%' ORDER BY m.id / Thanks, but this retrieves me so much rows as many are the appearance the 'sometext' in the Recs table Roy A. Jones Rick [EMAIL PROTECTED] 13-Oct-2006 10:53 To php-db@lists.php.net cc Subject Re: [PHP-DB] Problem with Oracle query Brad Bonkoski [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Rosen wrote: Hi, I have a problem with PHP and Oracle SQL query. I have 2 tables : Table Main: --- id number text varchar2(100) Table Recs --- id number pos number log varchar2(200) I need to make query to select a list from first table(Main), where somewhere in the second table (Recs), the log field contains some string. The records for one ID from Main table can be many in table Recs. ( Table Recs acts as log for every row from table Main). Can someone help me with this query? Thanks in advance, Rosen select m.id, r.log from main m left outer join recs r on r.id = m.id This will output something like: Id log 1log item 1 1log item 2 1log item 3 2another log etc... Thanks, but I want to retrieve only one row for ID field (row from Main table) where the string contains in second table. Something like this: ID Text 1 Sometext 1 2 Sometext 2 6Sometext 3 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with Oracle query
When you say so much rows I am assuming you mean 1 row from MAIN for every row in RECS. If that is true and you just want 1 MAIN row then I would add DISTINCT or EXISTS or IN ... SELECT DISTINCT m.id ,m.text FROM main m ,recs r WHERE m.id = r.id AND r.log like '%sometext%' ORDER BY m.id / Roy A. Jones Rosen [EMAIL PROTECTED] 13-Oct-2006 11:09 To php-db@lists.php.net cc Subject Re: [PHP-DB] Problem with Oracle query [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Try this ... SELECT m.id ,m.text FROM main m ,recs r WHERE m.id = r.id AND r.log like '%sometext%' ORDER BY m.id / Thanks, but this retrieves me so much rows as many are the appearance the 'sometext' in the Recs table Roy A. Jones Rick [EMAIL PROTECTED] 13-Oct-2006 10:53 To php-db@lists.php.net cc Subject Re: [PHP-DB] Problem with Oracle query Brad Bonkoski [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] Rosen wrote: Hi, I have a problem with PHP and Oracle SQL query. I have 2 tables : Table Main: --- id number text varchar2(100) Table Recs --- id number pos number log varchar2(200) I need to make query to select a list from first table(Main), where somewhere in the second table (Recs), the log field contains some string. The records for one ID from Main table can be many in table Recs. ( Table Recs acts as log for every row from table Main). Can someone help me with this query? Thanks in advance, Rosen select m.id, r.log from main m left outer join recs r on r.id = m.id This will output something like: Id log 1log item 1 1log item 2 1log item 3 2another log etc... Thanks, but I want to retrieve only one row for ID field (row from Main table) where the string contains in second table. Something like this: ID Text 1 Sometext 1 2 Sometext 2 6Sometext 3 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Problem with insert BLOB into Oracle
Hello you can not insert a lob this way. Refer to the php manual pages at http://www.php.net/oci And search for Example 3. Inserting data into a CLOB column Vincent -Original Message- From: Rosen [mailto:[EMAIL PROTECTED] Sent: jeudi 5 octobre 2006 14:43 To: php-db@lists.php.net Subject: [PHP-DB] Problem with insert BLOB into Oracle Hi, I have problem with inserting into BLOB field in Oracle 10: insert into some_table(DESC) values ( '$txt') The DESC field type is LONG RAW The $txt variable contains large text, whitch is extracted from another table field with same type. When I read field DESC and print it, there is no problems, but when try to insert I receive an error:Error: ORA-01465: invalid hex number Can someone help ? Thanks, Rosen -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] problem with header()
On 10/4/06, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Hi
I can not submit any header() information in the following context.
What is wrong within the code?
?php
require_once includes/db.inc;
require_once HTML/Template/ITX.php;
if (!($connection = @ mysql_connect($hostname, $username, $password)))
die(Could not connect to database);
$status = mysqlclean($_GET, status, 1, $connection);
$template = new HTML_Template_ITX(./templates);
$template-loadTemplatefile(form2tpl.tpl, true, true);
$template-setCurrentBlock(success);
$template-setVariable(AUTOR, $_REQUEST[autor_eb]);
$template-setVariable(STICHWORT, $_REQUEST[stichwort_eb]);
$template-setVariable(DATUM, $_REQUEST[datum_eb]);
$template-setVariable(ANLAGE, $_REQUEST[anlage_eb]);
$template-setVariable(PROBLEM, $_REQUEST[problem_eb]);
$template-parseCurrentBlock();
$template-show();
session_start();
foreach($_POST as $Key = $Value) {
$_SESSION[$Key] = $Value;
}
if ($_POST['submit'] == Eintrag Bearbeiten){
header(Location: http://127.0.0.1/www2/knowledge_db/knowbase02.php;);
exit;
}
?
Best regards, Joerg Kuehne
There must be NO output to the user, before any header(); calls.
1) Check the files you require() for any whitespaces before the ? tag
2) IF $template-show(); does what it says, you must start the session
before that call.
3) Good luck :)
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Re: [PHP-DB] Problem with list#2
You may get duplicate messages sometimes when someone responds directly to you as well as copying the message to the main mailing list. Like in this ccase, my To: field is the PHP DB list, and my CC: field is your personal email address. If that's not the issue, then try what Dave suggested and unsubscribe using one of your email addresses and see if that solves the problem. -TG On 7/7/06, Karl James [EMAIL PROTECTED] wrote: Team, I am still receiving duplicate emails. I check with my ISP and they tell me it is Not their problem. I tried to check the headers But I am not able to see anything that indicates What email address its being sent to because I have two of them. Can anyone help suggest on how to resolve this. I would send a screen shot but its not advise to In forums. Off list I can for sure if any one wants To see what's going on. Karl James (TheSaint) mailto:[EMAIL PROTECTED] [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] [EMAIL PROTECTED] www.theufl.com ___ Sent by ePrompter, the premier email notification software. Free download at http://www.ePrompter.com. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with list#2
On Friday 07 July 2006 14:30, Karl James wrote: Team, I am still receiving duplicate emails. Karl James (TheSaint) mailto:[EMAIL PROTECTED] [EMAIL PROTECTED] mailto:[EMAIL PROTECTED] [EMAIL PROTECTED] www.theufl.com Did you save your confirm and welcome e-mail from the list? That will tell you which one or if both of them are on the list. -- Jack Gates http://www.jlgates.com/ http://www.myenergyproducts.com/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with a login page.
snip...
// check passwords match
$_POST['password'] = stripslashes($_POST['password']);
$info['password'] = stripslashes($info['password']);
$_POST['password'] = $_POST['password'];
if ($_POST['password'] != $info['password']) {
die('Incorrect password, please try again.');
}
snip...
Alex,
Sticking for the moment with the error message you get, I can't see
anyplace where an array named $info with a key of password is declared
or assigned this value. Are you sure that this variable exists?
David
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RE: [PHP-DB] Problem installing mssql extension
You still need to set the PHPRC system variable to c:\php5 (on the System Properties menu, Advanced tab, click Environment Variables). Also, PHP4 has an extensions directory. PHP5 should point to extension_dir = C:\PHP5\ext\ PLEASE NOTE that I disagree with Frank that the correct methodology is to pollute system32 with all of your PHP DLLs. This makes maintenance harder. All of my dll's live in the C:\php tree, so when I swap to the next 5.1.x release, I don't have to go hunt down a bunch of random dll's in system32. When I tried to run only the mssql extension, I kept getting a php startup error that it was Unable to load c:\php5\ext\php_mssql.dll. I knew that the file was there, why couldn't it be opened? I researched this (sorry, lost the link) and found that mssql extension has a dependency on the mysql extension. So then I was getting Unable to load c:\php5\ext\php_mysql.dll. That's when I learned that it's best to set your PHPRC System Variable to load the required dll's directly from the php5 directory tree, rather than copying them to system32. This should be especially useful to you as you are running 5.1.2-dev, as these dll's may change with the stable release. -jim -Original Message- From: Andrew Kleimeyer [mailto:[EMAIL PROTECTED] Sent: Tuesday, January 24, 2006 11:21 PM To: Bastien Koert Cc: php-db@lists.php.net Subject: Re: [PHP-DB] Problem installing mssql extension Yes. My extensions directory is c:\php\extensions and I'm already successfully running the mysql extension. On 1/25/06, Bastien Koert [EMAIL PROTECTED] wrote: Have you added the path to the extensions in the path/dir section to point to the extensions directory? ext_dir = c:\php5\ext; bastien From: Andrew Kleimeyer [EMAIL PROTECTED] To: php-db@lists.php.net Subject: [PHP-DB] Problem installing mssql extension Date: Wed, 25 Jan 2006 12:56:09 +0800 I've read all the documentation, and tried every suggestion, but I'm still unable to run the mssql extension. When I uncomment the line in php.ini, PHP crashes. My system: Windows 2000 IIS 5.0 PHP Version 5.1.2-dev What I have tried: I've placed the ntwdblib.dll that came with php into the winnt/system32/ directory. Nothing. I've placed the ntwdblib.dll that is running on my mssql machine into winnt/system32/ directory on the php machine. Nothing. I've copied the php_mssql.dll into the winnt/system32/ directory on the php machine. Nothing. Any ideas would be greatly appreciated. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Problem installing mssql extension
Hi Jim, Using PHPRC is not needed on Win32. It's an option. If you read my post again you will see that I did not say anything about putting PHP dll's in system32. I was refering to ntwdblib.dll. This is not a PHP dll, it's a Microsoft DLL that will be installed with the CLient Tools. I agree with you about keeping installations simple. I don't even use an extension dir. Everything works nicly with all PHP files installed in c:\php5 (c:\php4 and c:\php6). Your research on MSSQL depending on MySQL is wrong. As the maintainer of the MSSQL extension I know for sure that it depends only on dblib from Microsoft. - Frank You still need to set the PHPRC system variable to c:\php5 (on the System Properties menu, Advanced tab, click Environment Variables). Also, PHP4 has an extensions directory. PHP5 should point to extension_dir = C:\PHP5\ext\ PLEASE NOTE that I disagree with Frank that the correct methodology is to pollute system32 with all of your PHP DLLs. This makes maintenance harder. All of my dll's live in the C:\php tree, so when I swap to the next 5.1.x release, I don't have to go hunt down a bunch of random dll's in system32. When I tried to run only the mssql extension, I kept getting a php startup error that it was Unable to load c:\php5\ext\php_mssql.dll. I knew that the file was there, why couldn't it be opened? I researched this (sorry, lost the link) and found that mssql extension has a dependency on the mysql extension. So then I was getting Unable to load c:\php5\ext\php_mysql.dll. That's when I learned that it's best to set your PHPRC System Variable to load the required dll's directly from the php5 directory tree, rather than copying them to system32. This should be especially useful to you as you are running 5.1.2-dev, as these dll's may change with the stable release. -jim -Original Message- From: Andrew Kleimeyer [mailto:[EMAIL PROTECTED] Sent: Tuesday, January 24, 2006 11:21 PM To: Bastien Koert Cc: php-db@lists.php.net Subject: Re: [PHP-DB] Problem installing mssql extension Yes. My extensions directory is c:\php\extensions and I'm already successfully running the mysql extension. On 1/25/06, Bastien Koert [EMAIL PROTECTED] wrote: Have you added the path to the extensions in the path/dir section to point to the extensions directory? ext_dir = c:\php5\ext; bastien From: Andrew Kleimeyer [EMAIL PROTECTED] To: php-db@lists.php.net Subject: [PHP-DB] Problem installing mssql extension Date: Wed, 25 Jan 2006 12:56:09 +0800 I've read all the documentation, and tried every suggestion, but I'm still unable to run the mssql extension. When I uncomment the line in php.ini, PHP crashes. My system: Windows 2000 IIS 5.0 PHP Version 5.1.2-dev What I have tried: I've placed the ntwdblib.dll that came with php into the winnt/system32/ directory. Nothing. I've placed the ntwdblib.dll that is running on my mssql machine into winnt/system32/ directory on the php machine. Nothing. I've copied the php_mssql.dll into the winnt/system32/ directory on the php machine. Nothing. Any ideas would be greatly appreciated. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem installing mssql extension
So I was able to get the extension working. Here was my fix: I replaced my php_mssql.dll file with a download from: http://kromann.info/download.php?strFolder=php5_1-Release_TSstrIndex=PHP5_1 and everything worked perfectly. Any ideas what the problem was with my original php_mssql.dll file? Thanks, andrew On 1/26/06, Frank M. Kromann [EMAIL PROTECTED] wrote: Hi Jim, Using PHPRC is not needed on Win32. It's an option. If you read my post again you will see that I did not say anything about putting PHP dll's in system32. I was refering to ntwdblib.dll. This is not a PHP dll, it's a Microsoft DLL that will be installed with the CLient Tools. I agree with you about keeping installations simple. I don't even use an extension dir. Everything works nicly with all PHP files installed in c:\php5 (c:\php4 and c:\php6). Your research on MSSQL depending on MySQL is wrong. As the maintainer of the MSSQL extension I know for sure that it depends only on dblib from Microsoft. - Frank You still need to set the PHPRC system variable to c:\php5 (on the System Properties menu, Advanced tab, click Environment Variables). Also, PHP4 has an extensions directory. PHP5 should point to extension_dir = C:\PHP5\ext\ PLEASE NOTE that I disagree with Frank that the correct methodology is to pollute system32 with all of your PHP DLLs. This makes maintenance harder. All of my dll's live in the C:\php tree, so when I swap to the next 5.1.x release, I don't have to go hunt down a bunch of random dll's in system32. When I tried to run only the mssql extension, I kept getting a php startup error that it was Unable to load c:\php5\ext\php_mssql.dll. I knew that the file was there, why couldn't it be opened? I researched this (sorry, lost the link) and found that mssql extension has a dependency on the mysql extension. So then I was getting Unable to load c:\php5\ext\php_mysql.dll. That's when I learned that it's best to set your PHPRC System Variable to load the required dll's directly from the php5 directory tree, rather than copying them to system32. This should be especially useful to you as you are running 5.1.2-dev, as these dll's may change with the stable release. -jim -Original Message- From: Andrew Kleimeyer [mailto:[EMAIL PROTECTED] Sent: Tuesday, January 24, 2006 11:21 PM To: Bastien Koert Cc: php-db@lists.php.net Subject: Re: [PHP-DB] Problem installing mssql extension Yes. My extensions directory is c:\php\extensions and I'm already successfully running the mysql extension. On 1/25/06, Bastien Koert [EMAIL PROTECTED] wrote: Have you added the path to the extensions in the path/dir section to point to the extensions directory? ext_dir = c:\php5\ext; bastien From: Andrew Kleimeyer [EMAIL PROTECTED] To: php-db@lists.php.net Subject: [PHP-DB] Problem installing mssql extension Date: Wed, 25 Jan 2006 12:56:09 +0800 I've read all the documentation, and tried every suggestion, but I'm still unable to run the mssql extension. When I uncomment the line in php.ini, PHP crashes. My system: Windows 2000 IIS 5.0 PHP Version 5.1.2-dev What I have tried: I've placed the ntwdblib.dll that came with php into the winnt/system32/ directory. Nothing. I've placed the ntwdblib.dll that is running on my mssql machine into winnt/system32/ directory on the php machine. Nothing. I've copied the php_mssql.dll into the winnt/system32/ directory on the php machine. Nothing. Any ideas would be greatly appreciated. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] Problem installing mssql extension
Have you added the path to the extensions in the path/dir section to point to the extensions directory? ext_dir = c:\php5\ext; bastien From: Andrew Kleimeyer [EMAIL PROTECTED] To: php-db@lists.php.net Subject: [PHP-DB] Problem installing mssql extension Date: Wed, 25 Jan 2006 12:56:09 +0800 I've read all the documentation, and tried every suggestion, but I'm still unable to run the mssql extension. When I uncomment the line in php.ini, PHP crashes. My system: Windows 2000 IIS 5.0 PHP Version 5.1.2-dev What I have tried: I've placed the ntwdblib.dll that came with php into the winnt/system32/ directory. Nothing. I've placed the ntwdblib.dll that is running on my mssql machine into winnt/system32/ directory on the php machine. Nothing. I've copied the php_mssql.dll into the winnt/system32/ directory on the php machine. Nothing. Any ideas would be greatly appreciated. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem installing mssql extension
Yes. My extensions directory is c:\php\extensions and I'm already successfully running the mysql extension. On 1/25/06, Bastien Koert [EMAIL PROTECTED] wrote: Have you added the path to the extensions in the path/dir section to point to the extensions directory? ext_dir = c:\php5\ext; bastien From: Andrew Kleimeyer [EMAIL PROTECTED] To: php-db@lists.php.net Subject: [PHP-DB] Problem installing mssql extension Date: Wed, 25 Jan 2006 12:56:09 +0800 I've read all the documentation, and tried every suggestion, but I'm still unable to run the mssql extension. When I uncomment the line in php.ini, PHP crashes. My system: Windows 2000 IIS 5.0 PHP Version 5.1.2-dev What I have tried: I've placed the ntwdblib.dll that came with php into the winnt/system32/ directory. Nothing. I've placed the ntwdblib.dll that is running on my mssql machine into winnt/system32/ directory on the php machine. Nothing. I've copied the php_mssql.dll into the winnt/system32/ directory on the php machine. Nothing. Any ideas would be greatly appreciated.
Re: [PHP-DB] Problem with creating parallel connections with mysql_connect
On Wed, 18 Jan 2006 19:51, Aarno Syvänen wrote: Hi List, decided to try non-permanent connections for now. So now I have: ? /* db.php */ $db_server=127.0.0.1; $db_user = asterisk; $db_pass = bozzo984; $db_db = bebbicell; $db_account_server=127.0.0.1; $db_account_user = asterisk; $db_account_pass = bozzo984; $db_account_db = asterisk; $allow_multiple = true; //$level= error_reporting ( 0); $bid=mysql_connect($db_server,$db_user,$db_pass, $allow_multiple); echo mysql_error(); //error_reporting ( $level); mysql_select_db($db_db,$bid); echo mysql_error(); //$level= error_reporting ( 0); $accid=mysql_connect($db_account_server,$db_account_user, echo mysql_error(); $db_account_pass, $allow_multiple); //error_reporting ( $level); mysql_select_db($db_account_db, $accid); echo mysql_error(); ? Still I have same error: Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /var/www/bebbicell.ch/signup.php on line 212 Warning: mysql_error(): supplied argument is not a valid MySQL-Link resource in /var/www/bebbicell.ch/signup.php on line 213 Offending statements are: $res = mysql_query($sql,$accid); echo mysql_error(); $err = mysql_error($accid); Note that I use php-5.1.2RC1 compiled for Darwin Kernel Version 8.3.0 and Macintosh powerpc Aarno Try the above to find exactly where your problem is Cheers -- David Robley If I had anything witty to say, I wouldn't put it here. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Problem with creating parallel connections with mysql_connect
I go following debug:
got error when doing first connection
resource id was Resource id #3
got error when selecting first database
got error when doing second connection
resource id was Resource id #4
got error when selecting second database
the code was:
$bid=mysql_connect($db_server,$db_user,$db_pass, $allow_multiple);
//error_reporting ( $level);
print got error . mysql_error() . when doing first connection\n;
print resource id was $bid\n;
mysql_select_db($db_db,$bid);
print got error . mysql_error() . when selecting first database
\n;
//$level= error_reporting ( 0);
$accid=mysql_connect($db_account_server,$db_account_user,
$db_account_pass, $allow_multiple);
print got error . mysql_error() . when doing second connection
\n;
print resource id was $accid\n;
//error_reporting ( $level);
mysql_select_db($db_account_db, $accid);
print got error . mysql_error() . when selecting second
database\n;
So resource ids seem to be proper, and there is no errors either.
Signup.php already tests $err:
$err = mysql_error($accid);
if($err==)
{
echo (BRBRp.lfunc
(signup_successful).BRBR/p);
}
else
{
echo $err;
}
It branches to $err==, when at same time reporting
Warning: mysql_error(): supplied argument is not a valid MySQL-Link
resource in /var/www/bebbicell.ch/signup.php on line 213
This looks really strange.
Aarno
On 18 Jan 2006, at 11:14, David Robley wrote:
On Wed, 18 Jan 2006 19:51, Aarno Syvänen wrote:
Hi List,
decided to try non-permanent connections for now. So now I have:
?
/* db.php */
$db_server=127.0.0.1;
$db_user = asterisk;
$db_pass = bozzo984;
$db_db = bebbicell;
$db_account_server=127.0.0.1;
$db_account_user = asterisk;
$db_account_pass = bozzo984;
$db_account_db = asterisk;
$allow_multiple = true;
//$level= error_reporting ( 0);
$bid=mysql_connect($db_server,$db_user,$db_pass, $allow_multiple);
echo mysql_error();
//error_reporting ( $level);
mysql_select_db($db_db,$bid);
echo mysql_error();
//$level= error_reporting ( 0);
$accid=mysql_connect($db_account_server,$db_account_user,
echo mysql_error();
$db_account_pass, $allow_multiple);
//error_reporting ( $level);
mysql_select_db($db_account_db, $accid);
echo mysql_error();
?
Still I have same error:
Warning: mysql_query(): supplied argument is not a valid MySQL-Link
resource in /var/www/bebbicell.ch/signup.php on line 212
Warning: mysql_error(): supplied argument is not a valid MySQL-Link
resource in /var/www/bebbicell.ch/signup.php on line 213
Offending statements are:
$res = mysql_query($sql,$accid);
echo mysql_error();
$err = mysql_error($accid);
Note that I use php-5.1.2RC1 compiled for Darwin Kernel Version 8.3.0
and Macintosh powerpc
Aarno
Try the above to find exactly where your problem is
Cheers
--
David Robley
If I had anything witty to say, I wouldn't put it here.
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