It seems to me that this code will not provide useful information:
if ($result)
echo mysql_affected_rows()." affected.";
If the insert was successful, it will always say "1 affected." Since
you are only inserting one row at a time.
On Sat, 07 Jun 2003 08:49:15 -0400, Becoming Digital wrote:
> Try this. I made some minor syntax changes and added some error reporting.
> While it may not fix things, it might help you figure out what's wrong.
>
> $mails=file("mails.txt");
> $number_of_mails = count($mails);
>
> for ($i=0; $i<$number_of_mails; $i++)
> {
> $link = @ mysql_connect("localhost")
> or die( mysql_error() );
> $db = mysql_select_db("me2resh00", $link);
> $query = "insert into recipients (recipient_name,
> recipient_email) values
> (\"friend\", \"".$mails[$i]."\")";
> $result = mysql_query($query);
> if ($result)
> echo mysql_affected_rows()." affected.";
> }
> ?>
>
> Edward Dudlik
> Becoming Digital
> www.becomingdigital.com
>
>
> - Original Message -
> From: "Ahmed Abdelaliem" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Saturday, 07 June, 2003 08:15
> Subject: [PHP-DB] problem with insert query
>
>
> hi
> i am wrote a script to read e-malis from a file and insert it into the
> tables of database
> i get error when i write it
> here is the code
> can anyone tell me what is wrong?
>
> $mails=file("mails.txt");
> $number_of_mails = count($mails);
>
> for ($i=0; $i<$number_of_mails; $i++){
>
> @ $db = mysql_connect("localhost");
> mysql_select_db("me2resh00");
> $query = "insert into recipients (recipient_name, recipient_email) values
> ('"friend"', '".$mails[$i]."')";
> $result = mysql_query($query);
> if ($result)
> echo mysql_affected_rows()." affected.";
>
>}
> ?>
>
>
> here is the error that i get
>
> Parse error: parse error in enter.php on line 9
>
>
> and line 9 is
>
> $query = "insert into recipients (recipient_name, recipient_email) values
> ('"friend"', '".$mails[$i]."')";
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