This is CorpseEater's reply on your message send to him on 8/15/2002 :
Bo basically this a code for uploading images and text info into a mysql
Bo database, however, when I execute this code, an error occured as:
Bo Undefined variable: action in \phpmySQL\add.php on line 2
Bo what will be the problem?
Bo ?php
-snatch--
Bo if ((isset($action)||($action == upload)) {
snatch-
Bo // ok, let's get the uploaded data and insert it into the db now
Bo include open_db.inc;
Bo if (isset($binFile) $binFile != none) {
Bo $data = addslashes(fread(fopen($binFile, r), filesize($binFile)));
Bo $strDescription = addslashes(nl2br($txtDescription));
Bo $sql = INSERT INTO tbl_Files ;
Bo $sql .= (description, bin_data, filename, filesize, filetype) ;
Bo $sql .= VALUES ('$strDescription', '$data', ;
Bo $sql .= '$binFile_name', '$binFile_size', '$binFile_type');
Bo $result = mysql_query($sql, $db);
Bo mysql_free_result($result); // it's always nice to clean up!
Bo echo Thank you. The new file was successfully added to our
Bo database.brbr;
Bo echo a href='main.php'Continue/a;
Bo }
Bo mysql_close();
Bo } else {
?
Bo HTML
Bo BODY
Bo FORM METHOD=post ACTION=add.php ENCTYPE=multipart/form-data
Bo INPUT TYPE=hidden NAME=MAX_FILE_SIZE VALUE=100
Bo INPUT TYPE=hidden NAME=action VALUE=upload
Bo TABLE BORDER=1
Bo TR
BoTDDescription: /TD
BoTDTEXTAREA NAME=txtDescription ROWS=10 COLS=50/TEXTAREA/TD
Bo /TR
Bo TR
BoTDFile: /TD
BoTDINPUT TYPE=file NAME=binFile/TD
Bo /TR
Bo TR
BoTD COLSPAN=2INPUT TYPE=submit VALUE=Upload/TD
Bo /TR
Bo /TABLE
Bo /FORM
Bo /BODY
Bo /HTML
Bo ?php
Bo }
?
--
Greets
[EMAIL PROTECTED]
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