Hi,
$res = mysql_query (SELECT COUNT(deptid) FROM maintenance GROUP BY
deptid);
$deptcount = array(); // reset the array
while ($row = mysql_fetch_row ($res)) {
$deptcount[] = $row[0];
this should be $deptcount[] .= $row[0]; shouldn't it?
}
cheers
J
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$res = mysql_query (SELECT COUNT(deptid) FROM maintenance GROUP BY
deptid);
$deptcount = array(); // reset the array
while ($row = mysql_fetch_row ($res)) {
$deptcount[] = $row[0];
this should be $deptcount[] .= $row[0]; shouldn't it?
No. The way it's written is it's adding an
Nope. Anytime you set an array with no index equal to something, (i.e.
$deptcount[]) it will add another element to the end of the array.
If you use .=, that means append the data, but since you're not specifying
an element, I'm not sure what it would do. Perhaps PHP is smart enough to
just
Hi,
Micah Stevens wrote:
Nope. Anytime you set an array with no index equal to something, (i.e.
$deptcount[]) it will add another element to the end of the array.
If you use .=, that means append the data, but since you're not
specifying an element, I'm not sure what it would do. Perhaps
