Ok...so, I'm a couple days behind...
[somewhat OT tidbit]
!isNaN(null) will also return true since null is parsed as 0.
Now, if you're going to use a String search, might as well use something
built-in that does just that.
First advantage: shorter code and smaller files.
Also, RegExp's usually (but, no always) parse faster than charAt loops.
Javascript:
function isInteger(value) {
// accepts untrimmed strings
return (/^\s*[0-9]+\s*$/).test(String(value));
}
function findInteger(value) {
return String(value).replace(/^[^0-9]*([0-9]*).*?$/, '$1');
}
Tests:
var i, j;
var funcs = [isInteger, findInteger];
var input = ['12 ', '12sds', 'fhe34', 'a12.3b', '1abc2', 99, 2.4, null];
for (i = 0; i funcs.length; i += 1) {
for (j = 0; j input.length; j += 1) {
document.write(funcs[i](input[j]), '; ');
}
document.write('br');
}
Output:
true; false; false; false; false; true; false; false;
12; 12; 34; 12; 1; 99; 2; ;
Usage:
input type=text onblur=this.value=findInteger(this.value); /!--
silently strips invalid characters --
span(integers only)/span
function validate() {
if (!isInteger(FormObject.input1.value)) {
alert('Please enter an integer for ...');
}
}
- Jon L.
On Mon, May 12, 2008 at 11:47 AM, YVES SUCAET [EMAIL PROTECTED] wrote:
Nope, it's not. The problem was formulated as Integer detection. not
numerical detection in general. isNaN will return positive for e.g.
floating
point values as well. The solutions described in this thread all result in
integer-only values.
All solutions presented are still off-topic, of course...
Yves
-- Original Message --
Received: Mon, 12 May 2008 11:12:02 AM CDT
From: Thiago Pojda [EMAIL PROTECTED]
To: 'sahabettin akca' [EMAIL PROTECTED], php-db@lists.php.net
Subject: RES: [PHP-DB] input field validation
It'd be simpler to use isNaN()
Thiago Henrique Pojda
Desenvolvimento Web
+55 41 3033-7676
[EMAIL PROTECTED]
Excelência em Softwares Financeiros
-Mensagem original-
De: sahabettin akca [mailto:[EMAIL PROTECTED]
Enviada em: domingo, 11 de maio de 2008 14:31
Para: php-db@lists.php.net
Assunto: Re: [PHP-DB] input field validation
hi,
*javascript function :
function isNumber(obj) {
var len = obj.value.length;
var lastChar = obj.value.charAt(len-1);
if( lastChar != '0' lastChar != '1' lastChar != '2'
lastChar
!= '3' lastChar != '4'
lastChar != '5' lastChar != '6' lastChar != '7' lastChar !=
'8' lastChar != '9' ) {
obj.value = obj.value.substring(0, len-1);
}
}
this is function use :
input *onKeyUp='isNumber(this)' /
do not alert , but add alert
* obj.value = obj.value.substring(0, len-1);
---
this line before
---
alert('this field only integer!');
*
add.
good luck
?ahabettin akca (saho)
2008/5/11 arafat uddin [EMAIL PROTECTED]:
-
and
this database field data type select int (integer) ,
tinyint, int, bigint... or
if(gettype($_POST['field'])!=integer) // or
if(intval($_POST['field'])==0)
or if(!intval($_POST['field']))
{
printnot integer;
location(header: .php);
#or
printmeta http-equiv='refresh' content='0;url=.php';
}
else
{
...
}
2008/5/11 Yves Sucaet [EMAIL PROTECTED]:
Allow me to point out that this is not database-related...
This website should get you everything you want:
http://www.acmesoffware.com/acme/ExamplesJS/jsExm_ValidateInteger.asp
HTH,
Yves
- Original Message - From: arafat uddin [EMAIL PROTECTED]
To: php-db@lists.php.net
Sent: Sunday, May 11, 2008 12:48 AM
Subject: [PHP-DB] input field validation
hi,
i want to input only integer in my field.if without integer any
input put in the field it will show warning messege.
such as 12 will be accept
but 12sds will not accept .
fhe34 will not accept
plz help me by any javascript code.
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?ahabettin akca // saho
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