Re: SV: [PHP-DB] Assistance with if..elseif statement

[Craig Hoffman]

Thanks all - CH

On Jan 17, 2005, at 8:35 AM, Henrik Hornemann wrote:

Hi,

}  elseif ($_POST['route_photo'] = $_POST['oldimage'])
Should probably be
}  elseif ($_POST['route_photo'] == $_POST['oldimage'])

Regards Henrik Hornemann

-----Oprindelig meddelelse-----
Fra: Craig Hoffman [mailto:[EMAIL PROTECTED]
Sendt: 17. januar 2005 15:22
Til: php-db@lists.php.net
Emne: [PHP-DB] Assistance with if..elseif statement

I have this block of code which checks to see if an image has been
uploaded from an update form.  Everything in the form works,  except I
can not get the the elseif statements to behave properly. See the
comments below for explanation.  Any help would be appreciated.

$route_photo = $_FILES['image']['name'];

// if no new image and no existing image put NULL in the DB
  if(empty($_FILES['image']['name']) && ($_POST['oldimage']) == '')
         {
             $route_photo = 'NULL';
              echo ("No image supplied.");

// if new image put the new image name in the DB
} elseif ($_POST['route_photo'] || $_FILES['image']['name']) {
$route_photo = $_POST['route_photo'];
echo ("The image has been replaced with
$route_photo.");

// If no new image update, use the old image
         }  elseif ($_POST['route_photo'] = $_POST['oldimage'])
                     {
                      $route_photo = $_POST['oldimage'];
                         echo("No new image supplied");
                     }

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