ID: 9092
Updated by: jmoore
Reported By: [EMAIL PROTECTED]
Old-Status: Duplicate
Status: Closed
Bug Type: Class/Object related
Operating system:
PHP Version: 4.0.4pl1
Assigned To:
Comments:
You cant pass a literal via reference. Closing report. This is in the todo for 4.1.
Previous Comments:
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[2001-02-20 01:34:45] [EMAIL PROTECTED]
covered by 6343
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[2001-02-03 19:00:05] [EMAIL PROTECTED]
hmm, i see your point.
is it possible to define a value that should be
passwd by reference as optional?
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[2001-02-03 18:09:28] [EMAIL PROTECTED]
This should not work - how can you pass a literal value by reference?
However, you are right about the error message - it does seem to be incorrect.
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[2001-02-03 17:53:52] [EMAIL PROTECTED]
This code snippet:
class test {
function test(&$test1=false) {
}
}
gives me
Parse error - parse error, expecting `')''
on the line with the constructor (function ...)
shouldn't this work (or at least return a useful error)?
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