Re: [PHP-DEV] Bug #11008 Updated: exit() should return an exit status if passed, not send to stdout

2001-12-06 Thread Markus Fischer
Sadly no :-/ There were some discussions in the past and some ideas came up (exit_shell() or shell_exit()) but no further steps where taken. - Markus On Thu, Dec 06, 2001 at 10:02:53PM -, [EMAIL PROTECTED] wrote : ID: 11008 Updated by: sniper Reported By: [EMAIL

Re: [PHP-DEV] Bug #11008 Updated: exit() should return an exit status if passed, not send to stdout

2001-12-06 Thread Markus Fischer
On Fri, Dec 07, 2001 at 02:33:50AM +0200, Jani Taskinen wrote : Creating some new function (or language construct :) and not fixing the existing one is really stupid idea. exit(string) - same behaviour as before eixt(int)- only set exit-status and no echo out anything to stdout.

Re: [PHP-DEV] Bug #11008 Updated: exit() should return an exit status if passed, not send to stdout

2001-07-17 Thread Jason Greene
Zeev, New Comment: Simply put - no, it should not. exit's optional argument is a termination message, not a shell status. Actually, if exit's argument is of type long, then the status is set. I think that since we support this functionality echoing the status code doesn't make much sense.

Re: [PHP-DEV] Bug #11008 Updated: exit() should return an exit status if passed, not send to stdout

2001-05-22 Thread Daniel Beckham
Can we go ahead and change this behavior then? Is there really a reason to echo the status to standard out? Daniel - Original Message - From: [EMAIL PROTECTED] To: [EMAIL PROTECTED] Sent: Monday, May 21, 2001 6:59 PM Subject: [PHP-DEV] Bug #11008 Updated: exit() should return an exit