Dan Brow [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
A little confused with mktime, I'm trying to get how many days are in a
year.
$year = 2006;
$epoch = mktime(0, 0, 0, 1, 0, $year); // I have to have 1 for month or
I get which day it is now. Which sucks.
$date = date(z Y,
Jasper Bryant-Greene [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Dan Brow wrote:
A little confused with mktime, I'm trying to get how many days are in a
year.
How about doing it differently. I'd tackle this problem like this:
?php
$year = '2005';
$time = strtotime(1
Gustav Wiberg [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
- Original Message -
From: Shaw, Chris - Accenture [EMAIL PROTECTED]
To: Gustav Wiberg [EMAIL PROTECTED]; PHP General
php-general@lists.php.net
Sent: Wednesday, September 07, 2005 5:03 PM
Subject: RE: [PHP]
M. Sokolewicz [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
snip
or, easier, simply make this script:
?php
echo PHP_INT_MAX;
?
and you're done :P The maximum integer value is stored in PHP_INT_MAX as
of 4.4.0 and PHP 5.0.5
before that, you had to use a way as the one Brian
Shaun [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi,
Is it possible to get the number of saturdays and sundays for a given
month
/ year?
Thanks for your help.
Here's another way to do it. Each function will return either 4 or 5. If you
need both Saturdays and Sundays, just
Sorry, I made a mistake. See below:
Brian P. O'Donnell [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Shaun [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Hi,
Is it possible to get the number of saturdays and sundays for a given
month
/ year?
Thanks for your
It's bad enough when somebody posts a blank email to the list, but when
people start posting blank replies, it gets really frustrating.
Please cease desist.
Thanks
Brian
Andy Pieters [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
Hello
I have the following code:
?
$a = 252.73;
$b = 252.73;
$c = 0;
if ($a == ($b + $c))
{
// do the first thing
}
elseif ($a ($b + $c))
{
// do the second thing
}
elseif ($a ($b + $c))
{
// do the third thing
}
?
Each of the three variables is derived by some earlier calculation, but for
That did the trick.
Thanks a million.
Brian
Jasper Bryant-Greene [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Brian P. O'Donnell wrote:
?
$a = 252.73;
$b = 252.73;
$c = 0;
if ($a == ($b + $c))
{
// do the first thing
}
elseif ($a ($b + $c))
{
// do
9 matches
Mail list logo
