ok. to anser my own questions. oi. type=image name=done then the var will
not be $done but $done_x and $done_y
--
Chris Lee
[EMAIL PROTECTED]
Chris Lee [EMAIL PROTECTED] wrote in message
9ehgvu$s2b$[EMAIL PROTECTED]">news:9ehgvu$s2b$[EMAIL PROTECTED]...
?php
echo
$done1br
ok Im having a hard time reading my own writing, the headers for both are
correct. what I didnt take 10sec to see was that done2 was not being sent,
done2.x and done2.y is being sent. oi.
?php
echo
$done1_x
$done1_y
$done2_x
$done2_y
form method='post'
?php
echo
$done1br
$done2br
form action='$PHP_SELF' method='post'
input type='submit' name='done1' value='done1'
input type='image' src='image/done.gif' name='done2' value='done2'
/form
;
?
ok, type='submit' works like it should, the headers
Packet ID (from_IP.port-to_IP.port):
an input tag of the type image cannot pass a name and value. therefore you
will have to use a script to detect if both the button and hidden are passed
or jsut the hidden. applying a hidden is helpful for this.
?php
if ($done1 $done2) {
$done2 = '';
}
echo
$done1 . 'br'.
$done2 . 'br
form
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